Chemical Principles: The Quest for Insight
7th Edition
ISBN: 9781464183959
Author: Peter Atkins, Loretta Jones, Leroy Laverman
Publisher: W. H. Freeman
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Chapter 8, Problem 8G.7E
Interpretation Introduction
Interpretation:
The formula and chemical equations of acids formed from
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The reaction of calcium hydride, CaH2, with water can be characterized as a Lewis acid-base reaction:
Identify the Lewis acid and the Lewis base among the reactants. The reaction is also an oxidation-reduction reaction. Identify the oxidizing agent, the reducing agent, and the changes in oxidation number that occur in the reaction.
Write and balance the Chemical Equation:HC2H3O2 + CaCO3→ calcium acetate + H2O + carbon dioxide
Consider the series of reactions to synthesize the alum (KAl(SO4 )2 · xH2O(s)) from the introduction.
(a) Assuming an excess of the other reagents, from one mole of aluminum Al (s), how many moles of alum will be produced?
(b) Assuming an excess of the other reagents, from one mole of potassium hydroxide KOH, how many moles of alum will be produced?
(c) Assuming an excess of the other reagents, from one mole of sulfuric acid H2SO4 , how many moles of alum will be produced?
(d) If you start the synthesis with 1.00 g of Al, 40.0 mL of 1.50 M KOH, and 20.0 mL of 9.00 M H2SO4 , which of the three will be the limiting reagent?
(e) Assuming that the product is anhydrous (that there are no waters of hydration), calculate the theoretical yield of alum, in grams, based on the amounts of reagents in part
(d). 3. Consider the nickel salt: (NH4 )2Ni(SO4 )2 ·y H2O (Ammonium Nickel Sulfate Hydrate), where y is the number of coordinated waters.
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Chapter 8 Solutions
Chemical Principles: The Quest for Insight
Ch. 8 - Prob. 8A.1ASTCh. 8 - Prob. 8A.1BSTCh. 8 - Prob. 8A.2ASTCh. 8 - Prob. 8A.2BSTCh. 8 - Prob. 8A.1ECh. 8 - Prob. 8A.2ECh. 8 - Prob. 8A.3ECh. 8 - Prob. 8A.4ECh. 8 - Prob. 8A.5ECh. 8 - Prob. 8A.6E
Ch. 8 - Prob. 8A.7ECh. 8 - Prob. 8A.8ECh. 8 - Prob. 8A.9ECh. 8 - Prob. 8A.10ECh. 8 - Prob. 8A.11ECh. 8 - Prob. 8A.12ECh. 8 - Prob. 8A.13ECh. 8 - Prob. 8A.14ECh. 8 - Prob. 8A.15ECh. 8 - Prob. 8A.16ECh. 8 - Prob. 8A.17ECh. 8 - Prob. 8A.18ECh. 8 - Prob. 8A.19ECh. 8 - Prob. 8A.20ECh. 8 - Prob. 8B.1ASTCh. 8 - Prob. 8B.1BSTCh. 8 - Prob. 8B.2ASTCh. 8 - Prob. 8B.2BSTCh. 8 - Prob. 8B.1ECh. 8 - Prob. 8B.2ECh. 8 - Prob. 8B.3ECh. 8 - Prob. 8B.4ECh. 8 - Prob. 8B.5ECh. 8 - Prob. 8B.6ECh. 8 - Prob. 8B.7ECh. 8 - Prob. 8B.8ECh. 8 - Prob. 8C.1ASTCh. 8 - Prob. 8C.1BSTCh. 8 - Prob. 8C.2BSTCh. 8 - Prob. 8C.1ECh. 8 - Prob. 8C.2ECh. 8 - Prob. 8C.3ECh. 8 - Prob. 8C.4ECh. 8 - Prob. 8C.5ECh. 8 - Prob. 8C.6ECh. 8 - Prob. 8D.1ASTCh. 8 - Prob. 8D.1BSTCh. 8 - Prob. 8D.2ASTCh. 8 - Prob. 8D.2BSTCh. 8 - Prob. 8D.1ECh. 8 - Prob. 8D.2ECh. 8 - Prob. 8D.3ECh. 8 - Prob. 8D.4ECh. 8 - Prob. 8D.5ECh. 8 - Prob. 8D.6ECh. 8 - Prob. 8D.7ECh. 8 - Prob. 8D.8ECh. 8 - Prob. 8E.1ASTCh. 8 - Prob. 8E.1BSTCh. 8 - Prob. 8E.2ASTCh. 8 - Prob. 8E.2BSTCh. 8 - Prob. 8E.1ECh. 8 - Prob. 8E.2ECh. 8 - Prob. 8E.3ECh. 8 - Prob. 8E.4ECh. 8 - Prob. 8E.5ECh. 8 - Prob. 8E.6ECh. 8 - Prob. 8E.7ECh. 8 - Prob. 8E.8ECh. 8 - Prob. 8F.1ASTCh. 8 - Prob. 8F.1BSTCh. 8 - Prob. 8F.2ASTCh. 8 - Prob. 8F.2BSTCh. 8 - Prob. 8F.1ECh. 8 - Prob. 8F.2ECh. 8 - Prob. 8F.3ECh. 8 - Prob. 8F.4ECh. 8 - Prob. 8F.5ECh. 8 - Prob. 8F.6ECh. 8 - Prob. 8G.1ASTCh. 8 - Prob. 8G.1BSTCh. 8 - Prob. 8G.2ASTCh. 8 - Prob. 8G.2BSTCh. 8 - Prob. 8G.1ECh. 8 - Prob. 8G.2ECh. 8 - Prob. 8G.3ECh. 8 - Prob. 8G.4ECh. 8 - Prob. 8G.5ECh. 8 - Prob. 8G.6ECh. 8 - Prob. 8G.7ECh. 8 - Prob. 8G.8ECh. 8 - Prob. 8G.9ECh. 8 - Prob. 8G.10ECh. 8 - Prob. 8H.1ASTCh. 8 - Prob. 8H.1BSTCh. 8 - Prob. 8H.2ASTCh. 8 - Prob. 8H.2BSTCh. 8 - Prob. 8H.1ECh. 8 - Prob. 8H.2ECh. 8 - Prob. 8H.3ECh. 8 - Prob. 8H.4ECh. 8 - Prob. 8H.5ECh. 8 - Prob. 8H.6ECh. 8 - Prob. 8H.7ECh. 8 - Prob. 8H.8ECh. 8 - Prob. 8H.10ECh. 8 - Prob. 8H.11ECh. 8 - Prob. 8H.12ECh. 8 - Prob. 8I.1ASTCh. 8 - Prob. 8I.1BSTCh. 8 - Prob. 8I.2ASTCh. 8 - Prob. 8I.2BSTCh. 8 - Prob. 8I.1ECh. 8 - Prob. 8I.2ECh. 8 - Prob. 8I.3ECh. 8 - Prob. 8I.5ECh. 8 - Prob. 8I.6ECh. 8 - Prob. 8I.7ECh. 8 - Prob. 8I.8ECh. 8 - Prob. 8I.9ECh. 8 - Prob. 8I.10ECh. 8 - Prob. 8I.11ECh. 8 - Prob. 8I.12ECh. 8 - Prob. 8I.13ECh. 8 - Prob. 8I.14ECh. 8 - Prob. 8I.15ECh. 8 - Prob. 8I.16ECh. 8 - Prob. 8J.1ASTCh. 8 - Prob. 8J.1BSTCh. 8 - Prob. 8J.1ECh. 8 - Prob. 8J.2ECh. 8 - Prob. 8J.3ECh. 8 - Prob. 8J.4ECh. 8 - Prob. 8J.5ECh. 8 - Prob. 8J.6ECh. 8 - Prob. 8J.7ECh. 8 - Prob. 8J.8ECh. 8 - Prob. 8.3ECh. 8 - Prob. 8.4ECh. 8 - Prob. 8.5ECh. 8 - Prob. 8.6ECh. 8 - Prob. 8.7ECh. 8 - Prob. 8.8ECh. 8 - Prob. 8.9ECh. 8 - Prob. 8.11ECh. 8 - Prob. 8.12ECh. 8 - Prob. 8.13ECh. 8 - Prob. 8.14ECh. 8 - Prob. 8.15ECh. 8 - Prob. 8.17ECh. 8 - Prob. 8.18ECh. 8 - Prob. 8.19ECh. 8 - Prob. 8.20ECh. 8 - Prob. 8.21ECh. 8 - Prob. 8.22ECh. 8 - Prob. 8.25ECh. 8 - Prob. 8.29ECh. 8 - Prob. 8.31CE
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- When carbon dioxide dissolves in water it reacts to produce carbonic acid, H2CO3(aq), which can ionize in two steps. H2CO3(aq)HCO3(aq)+H+(aq)Kc1=4.2107HCO3(aq)CO32(aq)+H+(aq)Kc2=4.81011 Calculate the equilibrium constant for the reaction H2CO3(aq)CO32(aq)+2H+(aq)arrow_forwardThe reaction of calcium hydride, CaH2, with water can be characterized as a Lewis acid-base reaction: CaH2(s)+2H2O(l)Ca(OH)2(aq)+2H2(g) Identify the Lewis acid and the Lewis base among the reactants. The reaction is also an oxidation-reduction reaction. Identify the oxidizing agent, the reducing agent, and the changes in oxidation number that occur in the reaction.arrow_forwardThe Properties, Reactions and Applications of Oxygen Explain the classification of oxides as basic, acid, amphoteric and neutral. How can we predict whether an oxide will be acidic or basic based on its composition? Give an example of an amphoteric oxide and give two typical reactionsarrow_forward
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