Power System Analysis and Design (MindTap Course List)
6th Edition
ISBN: 9781305632134
Author: J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma
Publisher: Cengage Learning
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Textbook Question
Chapter 7, Problem 7.2MCQ
Even though the fault current is not symmetrical and not strictly periodic, the rms asymmetrical fault current is computed as the rms ac fault current times an "asymmetry factor," which is a function of _______.
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Check out a sample textbook solutionStudents have asked these similar questions
Approximately 75 percentage of the fault are either _____ or permanent LG Faults.
a.
LLG
b.
Transient
c.
Simple
d.
LL
The DC Components components initially average about ______ of the fault current.
a.
0.50 to 0.60 times
b.
infinity
c.
20 to 45 percentage
d.
50 percentage
1. The subscript d in the generator subtransient reactance refers to:
1. Generator
impedance
2. If the available fault current slightly exceeds the breaker published
2. Generator
3. Direct axis
4. 1 and 2
reactance
interrupting rating, then it is safe to use the breaker.
1. True
| 2. False
3. Maybe
3. The rms symmetrical fault current times an asymmetry factor K, is equal to
the ac fault current.
| 2. False
4. The most common fault on a 3-phase power system is:
1. True
3. Maybe
| 2. DLG
3. L-L
1. SLG
5. All rotating and non-rotating load impedances are usually included in a power
system fault study
1. True
2. False
3. Мaybe
Chapter 7 Solutions
Power System Analysis and Design (MindTap Course List)
Ch. 7 - Even though the fault current is not symmetrical...Ch. 7 - The amplitude of the sinusoidal symmetrical ac...Ch. 7 - Equipment ratings for the four-bus power system...Ch. 7 - Equipment ratings for the five-bus power system...Ch. 7 - Prob. 7.22PCh. 7 - A three-phase circuit breaker has a 15.5-kV rated...Ch. 7 - Prob. 7.32P
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- Q.3 When a line-to-ground fault occurs, the current in faulted phase 'a' is 100A. The zero-sequence current in phase 'c' is rarrow_forward7.In a line-to-ground fault we can expect that A) There are no currents to ground. B) The voltages at the fault point with respect to ground are zero in all three phases. C) The current in the faulted phase flows to ground. D) There are short circuit currents in all three phases. E) N. A.arrow_forwardIn a short circuit test on 132 kV, 3-phase system, the breaker gives the following results: Power factor of the fault = 0.45. Recovery voltage 0.9 time of full line voltage. The breaking current is symmetrical. The restriking transient has a natural frequency of 15 kHz. Calculate the rate of rise of restriking voltage (RRRV) in the following types of faults: (1) Grounded fault (2) Undergrounded fault.arrow_forward
- complet The equivalent reactance of the double circuit line under post fault condition is................than fault condition.arrow_forwardQ.3 When a line-to-ground fault occurs, the current in faulted phase 'a' is 100A. The zero-sequence current in phase 'c' isarrow_forwardIn a short-circuit test on a 3-pole, 110 kV circuit breaker. Power factor of the fault= 0.4. Recovery voltage= 0.95 times (full line voltage) The breaking current was symmetrical the restriking transient had a natural frequency of 15000 c/s. Determine the average rate of rise of restriking voltage. (The natural is grounded and the fault involves earth). Explain in details.arrow_forward
- 3.On a double line-to-ground faultImmersive reader A) The short-circuit currents in the faulted phases are equal. B) The voltages at the fault point on the faulted phases are zero. C) The phase not involved in the fault has a zero voltage at the fault point. D) There are no circulating currents through the neutrals to ground. E) N. A.arrow_forwardA three phase fault is applied at the point P as shown in the figure. Find the criticalclearing angle for clearing the fault with simultaneous openings of the breakers 1 and 2. Thegenerator is delivering 1.0 pu at the instant preceding the faultarrow_forwardIn a short-circuit test on a 3-pole, 220 kV circuit breaker. Power factor of the fault = 0.8 Recovery voltage, 1.90 times (full line voltage) The breaking current was symmetrical the restriking transient had a natural frequency of 30000 c/s. Determine the average rate of rise of restriking voltage. (The natural is grounded and the fault involves earth).arrow_forward
- A fault which gives rise to symmetrical fault currents (equal faults currents with 120-degree displacement) is called a symmetrical fault. Select one: a. False O b. Truearrow_forwardWhat is subtransient and transient fault current? How do they occur in a system?arrow_forward1 Xine = j0.30 %3D G M X" = j0.15 X" = j0.20 Xiine = j0.30 Xiine = j0.30 %3D 1. Find the Thévenin equivalent looking into bus 3. 2. Calculate the subtransient fault current for a bolted three-phase fault at bus 3. Pre-fault voltage is VF 1Z°, and pre-fault current is neglected. 3. Distribute the fault current between the motor and generator.arrow_forward
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