Make the following prediction on the basis of your observations of this circuit. Do not use a voltmeter.
-
1. Just after the switch is closed:
• What id the potential difference across the bulb? Explain how you can tell from the brightness of the bulb.
• What is the potential difference across each of the capacitors? Explain your reasoning.
-
2. A long time after the switch is closed:
• What is the potential difference across the bulb? Explain how you can tell.
• What is the sum of the potential difference across the two capacitors? Explain.
• Is the final charge on capacitor 1 greater than, less than, or equal to the final charge on capacitor 2? Explain.
Use the voltmeter to check your predictions in part B.
Want to see the full answer?
Check out a sample textbook solutionChapter 6 Solutions
Tutorials in Introductory Physics
Additional Science Textbook Solutions
Physics: Principles with Applications
Conceptual Integrated Science
Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (4th Edition)
College Physics (10th Edition)
Physics for Scientists and Engineers with Modern Physics
The Cosmic Perspective Fundamentals (2nd Edition)
- 1. What is the time constant of the circuit formed when a and c are connected? Give your answer in ms to 3 significant digits. 2. What is the time constant of the circuit formed when b and c connected? Give your answer in ms to 3 significant digits. 3. You perform the following sequence of events. The capacitor starts uncharged and the switch is flipped to connect a and c. The capacitor is charged for 20 ms. The switch is then flipped to connect b and c, and the capacitor is discharged for 26 ms, at which time the switch is set to the position where it is not in contact with either a or b. What is the voltage on the capacitor? Give your answer to 2 significant digits.arrow_forwardProblem 2: For the image shown, the capacitors have the following values: C1 = 2.95*10^-6, C2 = 9.45*10^-6, C3 = 1.35*10^-6, C4 = 1.15*10^-6, C5 = 3.6*10^-6, and C6 = 4.95*10^-6. II Part (a) Calculate the total capacitance of the circuit. Ceq = Farrow_forwardSuppose that R = 3 k2 and C=3 μP in (Figure 1). Figure :C RR 1 of 1 Part A What is the time constant for the discharge of the capacitors in (Eigure 1)? Express your answer with the appropriate units. ▸ View Available Hint(s) for Part A for Party do for Part redo foart A refor Part A keyboard shortcuts for Part A help for Part A Value Submit Provide Feedback Unitsarrow_forward
- B. Directions: Read, understand, and perform the tasks by applying what you learned. 1. Make a Venn Diagram comparing emf of a source and potential difference across the circuit. 2. The battery supplies a maximum voltage of 12 V. When it is connected to an external circuit, the voltage measured by the voltmeter across the circuit is only 10 V. Is this possible? Explain your answer. 3. Why do the problems occur when an ammeter is connected in parallel with the lamp?arrow_forwardSelect the correct value for each of the quantities listed below. A capacitor of capacitance C= 2.0 µF is initially charged with charge Qo = 6.0 µC. The %3D capacitor is then discharged by connecting it to a resistor of resistance R = 5.0 MN. V V. • The initial voltage of this capacitor is [Select ] At time t = 20 s: • the charge on the capacitor is Q = [Select ] µC, • the voltage across the capacitor is AV= [Select] Y V, • the current in the circuit is I = [ Select ] [ Select ] and the energy stored in the capacitor is U =arrow_forwardShow all work for this question on your paper and PDF upload. There is nothing to submit in this question section for this problem. Two resistors, 25 Q, 37.5 0, and in parallel. That combination is in series with an unknown resistor R. This parallel-series combination is connected to a 12 V battery. The total current flowing through the battery is 0.60 A. a) Draw the circuit diagram for this arrangement. • Include a voltmeter showing the measurement of the unknown resistor R. • Include an ammeter to show the current through the 25 Q resistor. b) Determine the value of resistance R. c) Determine the current through the unknown resistor.arrow_forward
- Question 2 Base your answer on the diagram below which shows two different capacitors, Cl and C2, in two different connections to the same source of emf that has no internal resistance. 由凸 How does the equivalent capacitance for these two cases compare? a It is the same for bath connections. b. It is different for each connection, but one must know the values of C1 and C2, to know which is greater. It is greater for the series connection. It is greater for the parallel connection. It is different for each connection, but one must know the value of E to know which is greater.arrow_forwardQuestion 1 For the circuit in the Figure EL2-1 below, RT= > R1 >1.0k Ω R9 510 3 R10 1300 1. Determine if the following statements are TRUE or FALSE. Write in the blank space T if the statement is TRUE or F if the statement is FALSE. • Resistors R1 and R2 are in parallel. Answer: • The current that flows through resistor R4 equals the sum of the currents through resistor R6 and resistor R7. Answer: • The equivalent resistance of R3 and R8 is 168.2 Q. Answer: • The voltage drop accross R6 and R7 is the same. Q. Answer: • The equivalent resistance of R9 and R10 is 181 Q. Answer: 2. Determine the total equivalent resistor RT (shown in Figure EL2-2 below) of the circuit shown in Figure 1. Give your answer to 1 decimal place (1 d.p.) R2 3.0k 3 R3 >8.20 7 R8 1600 2 R4 160 Figure EL2-1 - Resisitve DC circuit Downloadable image RT R5 750 R6 820 >R7 >1500 Figure EL2-2 - Equivalent circuit to Figure EL1V2-1 Downloadable imagearrow_forwardThe bar shown has right angles and dimensions, L=35 cm by a by a and volume 1 x 10m Part A Determine a VO AE aarrow_forward
- II. Solve for the total voltage, individual voltages, total current, individual currents, total resistance, and individual resistances in each circuit diagram. Write your answers in the table provided beside each circuit diagram and show all HANDWRITTEN solutions in the last page. 1. Type of Connection: VT = 15.0 V R1 = 7.00 2 R2 = 4.00 2 R3 = 2.00 2 VI = I = RT = Vi = R1 = V2 = 12 = R2 = V3 = 13 = R3 =arrow_forwardMY NOTES ASK YOUR TEACHER PRACTICE ANOTHER The circuit in the figure below contains a 9.00 V battery and four capacitors. The two capacitors on the left and right both have same capacitance of C1 = 46.20 µF. The capacitors in the top two branches have capacitances of 6.00 µF and C2 = 40.20 µF. A rectangular circuit contains a battery and four capacitors. The bottom side has a 9.00 V battery with the positive terminal on the left. The left and right sides of the circuit each contain a capacitor labeled C1. The top side splits into two parallel horizontal branches, which recombine before reaching the top right corner. There is a 6.00 µF capacitor on the upper branch and a capacitor labeled C2 on the lower branch. (a) What is the equivalent capacitance (in µF) of all the capacitors in the entire circuit? µF (b) What is the charge (in µC) stored by each capacitor? right 46.20 µF capacitor µC left 46.20 µF capacitor µC 40.20 µF capacitor µC 6.00 µF capacitor µC (c) What is…arrow_forwardFor the circuit below. Hint, use the fact that the change in voltage is equal across all branches in a parallel circuit. ΔV1=ΔV2, R1I1=R2I2 Determine I2. Determine I3. Determine I4. Determine IT.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON