Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 6.13, Problem 63AAP
To determine
Time required to 50% recrystallization of the sheet at
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A cylindrical brass rod with a minimum tensile strength of 450 MPa, a ductility of at least 13% EL (elongation), and a final diameter of 12.7mm is required. You have in your inventory some 19.0mm diameter brass stock that has been cold worked to 35%. Assuming that the cross section of the rod is still circular after being cold worked, and that brass experiences cracking at 65% CW, describe the necessary working steps in order to achieve the final product. Take the expression for % cold work to be = (Ao - Af)/ Ao x 100%, where Ao and Af are the original and final circular cross-sectional areas of the rod.
A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively.
Calculate the length of the sheet after the rolling operation in feet.
We wish to produce a 0.3 inch thick plate of 3105 aluminum having a tensile strength of at least 25,000 psi and an elongation of at least 5%. The original thickness of the plate is 3 inches. The maximum cold work in each step is 85%. Which of the following procedures would achieve the correct final properties (more than one answer is possible!)?
Group of answer choices
Hot work from 3 in to 0.7 in; cold work from 0.7 in to 0.3 in
Cold work from 3 in to 0.7 in; do an anneal to recrystallize the material; cold work from 0.7 in to 0.3 in
Cold work from 3 inches to 0.3 inches
Cold work from 3 in to 0.7 in; cold work from 0.7 to 0.5 in; do an anneal to recrystallize the material; cold work from 0.5 in to 0.3 in
Hot work from 3 in to 0.5 in; do an anneal to recrystallize the material; hot work from 0.5 to 0.3 in
Hot work from 3 in to 0.7 in; do an anneal to recrystallize the material; hot work from 0.7 to 0.3 in
Cold work from 3 in to 0.5 in; do an anneal to recrystallize the…
Chapter 6 Solutions
Foundations of Materials Science and Engineering
Ch. 6.13 - (a) How are metal alloys made by the casting...Ch. 6.13 - Why are cast metal sheet ingots hot-rolled first...Ch. 6.13 - What type of heat treatment is given to the rolled...Ch. 6.13 - Describe and illustrate the following types of...Ch. 6.13 - Describe the forging process. What is the...Ch. 6.13 - What is the difference between open-die and...Ch. 6.13 - Describe the wire-drawing process. Why is it...Ch. 6.13 - Distinguish between elastic and plastic...Ch. 6.13 - Define (a) engineering stress and strain and (b)...Ch. 6.13 - Define (a) modulus of elasticity, (b) yield...
Ch. 6.13 - (a) Define the hardness of a metal. (b) How is the...Ch. 6.13 - What types of indenters are used in (a) the...Ch. 6.13 - What are slipbands and slip lines? What causes the...Ch. 6.13 - Describe the slip mechanism that enables a metal...Ch. 6.13 - (a) Why does slip in metals usually take place on...Ch. 6.13 - Prob. 16KCPCh. 6.13 - What other types of slip planes are important...Ch. 6.13 - Define the critical resolved shear stress for a...Ch. 6.13 - Describe the deformation twinning process that...Ch. 6.13 - What is the difference between the slip and...Ch. 6.13 - Prob. 21KCPCh. 6.13 - Prob. 22KCPCh. 6.13 - What experimental evidence shows that grain...Ch. 6.13 - (a) Describe the grain shape changes that occur...Ch. 6.13 - How is the ductility of a metal normally affected...Ch. 6.13 - (a) What is solid-solution strengthening? Describe...Ch. 6.13 - What are the three main metallurgical stages that...Ch. 6.13 - Describe the microstructure of a heavily...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Describe what occurs microscopically when a...Ch. 6.13 - When a cold-worked metal is heated into the...Ch. 6.13 - Prob. 33KCPCh. 6.13 - Prob. 34KCPCh. 6.13 - Prob. 35KCPCh. 6.13 - Prob. 36KCPCh. 6.13 - Prob. 37KCPCh. 6.13 - Why are nanocrystalline materials stronger? Answer...Ch. 6.13 - A 70% Cu30% Zn brass sheet is 0.0955 cm thick and...Ch. 6.13 - A sheet of aluminum alloy is cold-rolled 30% to a...Ch. 6.13 - Calculate the percent cold reduction when an...Ch. 6.13 - Prob. 42AAPCh. 6.13 - What is the relationship between engineering...Ch. 6.13 - A tensile specimen of cartridge brass sheet has a...Ch. 6.13 - A 0.505-in.-diameter rod of an aluminum alloy is...Ch. 6.13 - In Figure 6.23, estimate the toughness of SAE 1340...Ch. 6.13 - The following engineering stress-strain data were...Ch. 6.13 - Prob. 49AAPCh. 6.13 - A 0.505-in.-diameter aluminum alloy test bar is...Ch. 6.13 - A 20-cm-long rod with a diameter of 0.250 cm is...Ch. 6.13 - Prob. 52AAPCh. 6.13 - Prob. 53AAPCh. 6.13 - Prob. 54AAPCh. 6.13 - Prob. 55AAPCh. 6.13 - Prob. 56AAPCh. 6.13 - A specimen of commercially pure titanium has a...Ch. 6.13 - Prob. 58AAPCh. 6.13 - Prob. 59AAPCh. 6.13 - Prob. 60AAPCh. 6.13 - Prob. 61AAPCh. 6.13 - Prob. 62AAPCh. 6.13 - Prob. 63AAPCh. 6.13 - Prob. 64AAPCh. 6.13 - Prob. 65SEPCh. 6.13 - Prob. 66SEPCh. 6.13 - A 20-mm-diameter, 350-mm-long rod made of an...Ch. 6.13 - Prob. 68SEPCh. 6.13 - Prob. 69SEPCh. 6.13 - Consider casting a cube and a sphere on the same...Ch. 6.13 - When manufacturing complex shapes using cold...Ch. 6.13 - Prob. 74SEPCh. 6.13 - Draw a generic engineering stress-strain diagram...Ch. 6.13 - (a) Draw a generic engineering stress-strain...Ch. 6.13 - Prob. 77SEPCh. 6.13 - Prob. 78SEPCh. 6.13 - Prob. 79SEPCh. 6.13 - The material for a rod of cross-sectional area...Ch. 6.13 - What do E, G, v, Ur, and toughness tell you about...Ch. 6.13 - A cylindrical component is loaded in tension until...Ch. 6.13 - Referring to Figures 6.20 and 6.21 (read the...Ch. 6.13 - (a) Show, using the definition of the Poissons...Ch. 6.13 - A one-inch cube of tempered stainless steel (alloy...Ch. 6.13 - Prob. 87SEPCh. 6.13 - Prob. 88SEPCh. 6.13 - Prob. 89SEPCh. 6.13 - Prob. 90SEPCh. 6.13 - Prob. 91SEPCh. 6.13 - Prob. 92SEPCh. 6.13 - Prob. 93SEPCh. 6.13 - Prob. 94SEPCh. 6.13 - Starting with a 2-in.-diameter rod of brass, we...Ch. 6.13 - Prob. 96SEPCh. 6.13 - Prob. 97SEPCh. 6.13 - Prob. 98SEPCh. 6.13 - The cupro-nickel substitutional solid solution...Ch. 6.13 - Prob. 100SEP
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- A sheet of a 70% Cu-30% Zn alloy is cold-rolled 20% to a thickness of 3.0mm. The sheet is then further coldrolledto 2.0 mm. What is the percentage cold work?arrow_forwardA Cu-30% Zn brass plate, originally 1.20 inches thick, is desired to have a yield strength greater than 50,000 psi and a percent elongation of at least 15%. The final geometry of the plate will be obtained by means of cold work. What range of final thicknesses is possible to obtain under the given conditions? The effect of percent cold work on Cu-3096 Zn brass properties is shown below. 100 80 Resistencia a la tensión (ksi) 60 Límite elástico (ksi) 20 Porcentaje de elongación 20 40 60 80 Porcentaje de trabajo en frío Propiedadarrow_forwardA cold worked Al-alloy component takes 200 minutes to recrytallize at 250 °C but takes 14 minutes at 276 °C. How long will the recrystallization take place at 320 °C. Can you cold work or strain harden this component at 320 °C? Why? Note: recrystallization time shows Arrenius type temperature dependence: trec = Bexp(-EA) kI where B is constant, k is Boltzmann's constant and E is activation energy. A bronze component has the composition 94wt.%Cu-6wt.%Sn. Calculate its resistivity (6), and thermal conductivity (x).arrow_forward
- A 20 foot long x 4 feet wide x ½ inch thick sheet of an aluminum alloy is cold rolled to a thickness of ¼ inch. During the rolling operation the with of the sheet increases by 10%. The strength coefficient (K) and the strain hardening coefficient (n ) for the aluminum alloy are 25,500 psi and 0.3, respectively Calculate the true strain at the end of the rolling process.arrow_forwardpart made from AISI 1212 steel undergoes a 20 percent cold-work operation. (a) Obtain the yield strength and ultimate strength before and after the cold-work operation. Determine the percent increase in each strength. (b) Determine the ratios of ultimate strength to yield strength before and after the cold work operation. What does the result indicate about the change of ductility of the part?arrow_forwardDescribe Castigliano’s Second Theorem?arrow_forward
- Cold working of metals will give better final properties than hot working. Select one: True Falsearrow_forwardThe average grain diameter and yield strength for a brass material were measured as a function of time at 650°C. Given the following yield strengths for the two specimens, compute the heat treatment time required at 650°C to give a yield strength of 100 MPa. Assume a value of 2 for n, the grain diameter exponent. Time (min) 30 90 Yield Strength (MPa) 90 75 min Grain Diameter (mm) 3.9 x 10-2 6.6 x 10-2arrow_forward34% @ P 6:06 * ASIACELL I. 1 1 فيفري P 1:48 تحریر The strength constant (C) is increased with increasing of نقطة واحد- .temperature True O False O نقطة واحد- The metal is becoming weaker as strain increases, this is because of strain hardening .(work hardening) property True O darrow_forward
- Q3 contd. (d) The yield strength values of pure aluminium (Al) and pure copper (Cu) are 25 MPa and 20 MPa, respectively; whereas the yield strength values of cold rolled Al-Mn-Mg alloy and cast 60-40 Brass (60% Cu, 40% Zn) are 200 MPa and 105 MPa, respectively. With aid of schematics, explain the main mechanisms account for the increases in the strengths. (e) A cylindrical tie rod with a diameter of 18.4 mm is subjected to cyclic loading. The stress range is +/- 200 kN. Figure Q3.3 shows the S-N curve of the material of which the rod is made, how many cycles will this rod survive? Stress amplitude O₂ (MPa) 1500 1400 1300 1200 1100 1000 900 800 700 600 500 400 10² 10³ 104 4340 low-alloy steel Stress ratio = -1 Fig. Q3.3 105 106 Number of cycles to failure, Nf 107 108arrow_forwardASAParrow_forwardA cylindrical specimen of cold-worked copper has a %CW of 20%. If its cold-worked radius is 6.4 mm, what was the radius before deformation?arrow_forward
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