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In Exercises 4–10, find the global maximum and minimum for the function on the closed interval.
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Calculus: Single And Multivariable
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- In Exercises 39–44, each function f(x) changes value when x changes from x, to xo + dx. Find a. the change Af = f(xo + dx) – f(xo); b. the value of the estimate df = f'(xo) dx; and c. the approximation error |Af – df|. y = f(x)/ Af = f(xo + dx) – f(x) df = f'(xo) dx (xo, F(xo)) dx Tangent 0| xo + dx 39. f(x) 3D х? + 2x, хо —D 1, 40. f(x) = 2x² + 4x – 3, xo = -1, dx = 0.1 41. f(x) = x³ - x, xo = 1, dx = 0.1 dx = 0.1 %3D 42. f(x) 3 х, Хо —D 1, dx %3D 0.1 43. f(x) — х 1, Хо —D 0.5, dx %3D0.1 44. f(x) 3D х3 — 2х + 3, Хо — 2, dx 3D 0.1arrow_forwardIn Exercises 104–105, express the given function h as a composition of two functions f and g so that h(x) = (f• g)(x). 104. h(x) = (x² + 2x – 1)* 105. h(x) = V7x + 4 %3! %3!arrow_forwardEach of Exercises 25–36 gives a formula for a function y = f(x). In each case, find f-x) and identify the domain and range of f-. As a check, show that f(fx)) = f-"f(x)) = x. 25. f(x) = x 26. f(x) = x, x20 %3D %3D 27. f(x) = x + 1 28. f(x) = (1/2)x – 7/2 30. f(x) = 1/r, x * 0 %3D 29. f(x) = 1/x, x>0 x + 3 31. f(x) 32. f(x) = VE - 3 34. f(x) = (2x + 1)/5 2 33. f(x) = x - 2r, xs1 (Hint: Complete the square.) * + b x - 2' 35. f(x) = b>-2 and constant 36. f(x) = x? 2bx, b> 0 and constant, xsbarrow_forward
- In Exercises 33–38, express the function, f, in simplified form. Assume that x can be any real number. 33. f(x) = V36(x + 2)² 34. f(x) = V81(x – 2)2 35. f(x) = V32(x + 2)³ 36. f(x) = V48(x – 2)³ 37. f(x) = V3x² – 6x + 3 38. f(x) = V5x2 – 10x + 5 %3Darrow_forwardExercises 65–70: Find the maximum y-value on the graph of y = f(x). 65. flx) = -x² + 3x – 2 66. f(x) = -x² + 4x + 5 67. f(x) = 5x – x? 68. fx) = -2x² – 2x – 5 69. f(x) = 2x – 3x2 70. f(x) = -4x² + 6x – 9arrow_forwarda) Find the domain of f, g, f + g, f – & fg, ff, f/ g b) Find (f + g)(x), (f – g)(x), (fg)(x), (ff)(x), For each pair of functions in Exercises 17–32: 15. (8 and g/f. Find f+ g)(x), (f – g)(x), (fg)(x), (ff)(x), (f/8)(x), and (g/f)(x). 17. f(x) = 2x + 3, g(x) = 3 – 5x %3D 18. f(x) = -x + 1, g(x) = 4x – 2 19. f(x) = x – 3, g(x) = Vx + 4 20. f(x) = x + 2, g(x) = Vx – 1 21. f(x) = 2x – 1, g(x) = – 2x² 22. f(x) = x² – 1, g(x) = 2x + 5 23. f(x) = Vx – 3, g(x) : = Vx + 3arrow_forward
- In Exercises 129–130, find the inflection points (if any) on the graph of the function and the coordinates of the points on the graph where the function has a local maximum or local minimum value. Then graph the function in a region large enough to show all these points simultane-ously. Add to your picture the graphs of the function’s first and second derivatives. How are the values at which these graphs intersect the x-axis related to the graph of the function? In what other ways are the graphs of the derivatives related to the graph of the function? 1 29. y = x5 - 5x4 - 240 130. y = x3 - 12x2arrow_forwardIn Exercises 11–14,approximate the critical numbers of the function shown inthe graph. Determine whether the function has a relativemaximum, a relative minimum, an absolute maximum, anabsolute minimum, or none of these at each critical number onthe interval shown. image4arrow_forwardIn Exercises 16–22, show that the two functions are inverses of each other. 2 16. f(x) = 3x + 2 and g(x) = 3arrow_forward
- Use graphs to determine if each function f in Exercises 45–48 is continuous at the given point x = c. [2 – x, if x rational x², if x irrational, 45. f(x) c = 2 x² – 3, if x rational 46. f(x) = { 3x +1, if x irrational, c = 0 [2 – x, if x rational 47. f(x) = { x², if x irrational, c = 1 x² – 3, if x rational 3x +1, if x irrational, 48. f(x) : c = 4arrow_forwardIn Exercises 139–142, determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. x2 – 25 = x - 5 5 139. X - x? + 7 140. = x? + 1 7 7 domain of f(x) = is x(x – 3) + 5(x - 3) 141. The (-0, 3) U (3, 0). 142. The restrictions on the values of x when performing the division f(x) h(x) g(x) k (x) are g(x) + 0, k(x) # 0, and h(x) + 0.arrow_forwardLet f(x) = x3 - 12x+2. Find the global maximum and minimum of f(x) over the interval [-2,1]. (Explain basic steps.) %3Darrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage