In 2006, the murder of Alexander Litvinenko, a Russian dissident, was thought to be by poisoning from the rate and highly radioactive element polonium-210 ( 210 Po ) , The half-life of 210 Po is 138.4 yr. If 0.1 mg of 210 Po is present in a sample then A ( t ) = 0.1 ( 1 2 ) t / 138.4 gives the amount A ( t ) (in mg) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary. a. A ( 138.4 ) b. A ( 276.8 ) c. A ( 500 )
In 2006, the murder of Alexander Litvinenko, a Russian dissident, was thought to be by poisoning from the rate and highly radioactive element polonium-210 ( 210 Po ) , The half-life of 210 Po is 138.4 yr. If 0.1 mg of 210 Po is present in a sample then A ( t ) = 0.1 ( 1 2 ) t / 138.4 gives the amount A ( t ) (in mg) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary. a. A ( 138.4 ) b. A ( 276.8 ) c. A ( 500 )
Solution Summary: The author calculates that the remaining amount of polonium-210 is 0.05mg after 138.4 year.
In 2006, the murder of Alexander Litvinenko, a Russian dissident, was thought to be by poisoning from the rate and highly radioactive element polonium-210
(
210
Po
)
, The half-life of
210
Po
is 138.4 yr. If 0.1 mg of
210
Po
is present in a sample then
A
(
t
)
=
0.1
(
1
2
)
t
/
138.4
gives the amount
A
(
t
)
(in mg) present after t years. Evaluate the function for the given values of t and interpret the meaning in context. Round to 3 decimal places if necessary.
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