Concept explainers
Applying Properties of Exponents In Exercises 1–4, use the properties of exponents to simplify each expression. See Examples 1 and 2.
(a)
(b)
(c)
(d)
Trending nowThis is a popular solution!
Chapter 4 Solutions
Calculus: An Applied Approach (MindTap Course List)
- OA 5 = (3-1) 63 - (2) OB | ABarrow_forwardexpression equivalent to –x + ( –3x) + 12 – 9.arrow_forwardWrite and evaluate an expression of the form C(n, r) that represents each number of combinations of r cubes that can be taken from the eight cubes shown. (a) r = 1 (b) r = 2 (c) r = 3 (d) r = 4 (e) r = 5 (f) r = 6 (g) r = 7 (h) r = 8 II II II IIarrow_forward
- For Exercises 19–22, write each expression as a product. (See Example 3) 20. sin 30+ sin 100arrow_forwardIn Exercises 3–4, use the order of operations to simplify each expression. 8 - 3? ÷ 9 |-5| - [5 - (18 - 6)]? 3. 4. 4 (2 – 9)° + 32 ÷ 1 + 3 5. Simplify: 3 - [2(x – 2) – 5x].arrow_forwardHow do you do 7 and 8? Show workarrow_forward
- e* + 2 = * 8earrow_forwardHhhhhhhhhh also rules needarrow_forwardEXAMPLE 1 Simplify each expression. Assume that x can represent any nonzero real number. (a) 64-1/2 (b) (-16)-5/4 (c) -625-3/4 (d) (-32x5)-2/5 and (e) 1 25-3/2 Strategy 1 or x-m/n We will use one of the rules x-m/n 1 xm/n to write the reciprocal of each exponential expression and change the exponent's sign to positive. tm/n Why If we can produce an equivalent expression having a positive rational exponent, we can use the methods of this section to simplify it. Solution 1 Because the exponent is negative, write the reciprocal of 64¬1/2, and change the sign of the 1 (a) 64-1/2 641/2 64 8. exponent. (b) (-16)-5/4 is not a real number because (-16)5/4 is not a real number. (c) In -625-3/4, the base is 1 1 -625- -3/4 625)3 1 1 %3D %3D %D 6253/4 53 125 1 1 (d) (-32x5)-2/5 = 1 %D %D (-32x5)2/5 ¯ (V-32x5)2 (-2x)² 1 (e) -3/2 = 253/2 = (/25)³ = 53 = Because the exponent is negative, write the reciprocal of 1 25-3/2 and change the sign of the 25-3/2' exponent. ||arrow_forward
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin Harcourt