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In Exercises 13–20, find the particular solution corresponding to the tableau.
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Finite Mathematics & Its Applications (12th Edition)
- In Exercises 11–14, find parametric equations for all least squares solutions of Ax = b, and confirm that all of the solutions have the same error vector. 1 3 1 12. A = -2 -6 |; b = ! 0 3 9. 1arrow_forwardThree components are connected to form a system as shown in the accompanying diagram. Because the components in the 2–3 subsystem are connected in parallel, that subsystem will function if at least one of the two individual components functions. For the entire system to function, component 1 must function and so must the 2–3 subsystem. The experiment consists of determining the condition of each component [S (success) for a functioning component and F (failure) for a nonfunctioning component]. (Enter your answers in set notation. Enter EMPTY or ∅ for the empty set.) There us a graph shown in the pictures. Questions are posted on the pictures too.arrow_forwardLet y represent the annual income of an individual in 2018. Let z represent the number of days the individual worked in 2018. Let x represent the number of days the individual spent snow skiing in 2018. Let w represent the number of days the individual did not work in 2018. Which of the following models violate A3 (MLR.3)? O y = Bo+B1 + 2 + O y = Bo + B₁x + B₂z+u O y = Bo + Bi +B2 z tu All of the above.arrow_forward
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- In Exercises 13–17, determine conditions on the bi ’s, if any, in order to guarantee that the linear system is consistent. 13. x1 +3x2 =b1 −2x1 + x2 =b2 15. x1 −2x2 +5x3 =b1 4x1 −5x2 +8x3 =b2 −3x1 +3x2 −3x3 =b3 14. 6x1 −4x2 =b1 3x1 −2x2 =b2 16. x1 −2x2 − x3 =b1 −4x1 +5x2 +2x3 =b2 −4x1 +7x2 +4x3 =b3 17. x1 − x2 +3x3 +2x4 =b1 −2x1 + x2 + 5x3 + x4 = b2 −3x1 +2x2 +2x3 − x4 =b3 4x1 −3x2 + x3 +3x4 =b4arrow_forward5. a) Make tables of values for y = x², y = 2x², y = x² + 1, and y = (x – 3)². b) Compare the y-values for y = x² and y = 2x². c) Compare the y-values for y = x² and y = x² + 1. d) Compare the y-values for y = x² and y = (x – 3)².arrow_forwardQ : A researcher specities the tollowing model ot human capital HC a t+a,RM +a2Y +a,HS +a SC +asEDH +U Where HC is human capital (for human capital education expenditure is used as a proxy), RM = 1 if a household receives remittances and RM = 0 if a household does not receives remittances, Y = Household income, HS = Household size, SC = total number of school going children per household, EDH = 1 if head of household is literate and EDH = 0 if head of household is illiterate. Using data of 400 households he gets following results (A) HC = -6000+2010RM + 0.11Y - 80HS+805sC + 540EDH (0.02) (15) (105) (140) R(sqaure)= 0.45 SE= (2014) (215) Interpret above results Suppose researcher splits the households into low income households and high income households. He runs separate regressions and finds residuals sum of squares (RSS) 230 and 350 for 180 low income households and . 180 high income households, respectively. Is there any problem of Hetroscedasticity in above model? How do…arrow_forward
- 1. 2. 3. Write v as a linear combination of u and w, if possible, where u = (2, 3) and w = (1, -1). (Enter your answer in terms of u and w. If not possible, enter IMPOSSIBLE.) v = (-2, -3) V = Solve for w where u = (1, 0, -1, 1) and v = (2, 0, 3, -1). w + 2v = -4u W = Write each vector as a linear combination of the vectors in S. (If not possible, enter IMPOSSIBLE.) S = {(2, -1, 3), (5, 0, 4)) (a) z = (7, -6, 14). Z= (b) v = V = (c) w = (3,-9, 15) W = (d) v = (18, - 1, 59) )$₁ U= $₁ + u = (2, 1, -1) )$₁arrow_forwardThe following higher-order ‘y’ contains (possession, hosting) find a global solution using a dependent variablearrow_forward
- Algebra & Trigonometry with Analytic GeometryAlgebraISBN:9781133382119Author:SwokowskiPublisher:Cengage