Physics Fundamentals
2nd Edition
ISBN: 9780971313453
Author: Vincent P. Coletta
Publisher: PHYSICS CURRICULUM+INSTRUCT.INC.
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Chapter 4, Problem 8Q
(a)
To determine
Why it is not impossible for a horse and cart to move considering that the horse exerts a force on the cart in the forward direction and the cart exerts an equal force on the horse in the backward direction.
(b)
To determine
The external force that acts on the free body that comprises of the horse and the cart, causing it to accelerate.
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A force applied to an object of mass m1 produces an acceleration of 3.20 m/s2. The same force applied to a second object of mass m2 produces an acceleration of 1.70 m/s2.
(b) If m1 and m2 are combined into one object, find its acceleration under the action of the force.
Two blocks are in contact on a frictionless table. A horizontal force is applied to the larger block, as . (a) If m1 2.3 kg, m2 1.2 kg, and F = 3.2 N, find the magnitude of the force between the two blocks. (b) Show that if a force of the same magnitude F is applied to the smaller block but in the opposite direction, the magnitude of the force between the blocks is 2.1 N, which is not the same value calculated in (a). (c) Explain the difference.
Two crates, one with mass 4.00 kg and the other with mass 6.00 kg, sit on the frictionless
surface of a frozen pond, connected by a light rope. A woman wearing golf shoes (for
traction) pulls horizontally on the 6.00-kg crate with a force F that gives the crate an
acceleration of 2.50 m/s2. (a) What is the acceleration of the 4.00-kg crate? (b) Draw a free-
body diagram for the 4.00-kg crate. Use that diagram and Newton's second law to find the
tension T in the rope that connects the two crates. (c) Draw a free-body diagram for the 6.00-
kg crate. What is the direction of the net force on the 6.00-kg crate? Which is larger in
magnitude, T or F? (d) Use part (c) and Newton's second law to calculate the magnitude of F.
6.00 kg
4.00 kg
T
Chapter 4 Solutions
Physics Fundamentals
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