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At t = 0, a particle moving in the xy plane with constant acceleration has a velocity of
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Chapter 3 Solutions
Principles of Physics: A Calculus-Based Text
- The velocity of a particle moving in thex-y plane is given by (4.03i + 7.36j) m/s at time t = 3.64 s. Its average acceleration during the next 0.020 s is (2.2i + 2.6j) m/s?. Determine the velocity v of the particle at t = 3.660 s and the angle e between the average- acceleration vector and the velocity vector at t = 3.660 s. Answers: v= ( i i+ i j) m/s e =arrow_forwardA particle is in uniform circular motion about the origin of an xy coordinate system, moving clockwise with a period of 8.80 s. At one instant, its position vector (from the origin) is 7 = (2.90 m )i – (4.10 m )j. At that instant, what is its velocity in unit-vector notation?arrow_forwardA particle is performing uniform circular motion around the origin of an xy coordinate system moving clockwise with a speed of 3 m/s. At one instant, its position vector is 7 = (-1 m)î + (1 m)j. At that instant, what is the acceleration å of the particle in unit vector notation.arrow_forward
- A particle describes an UCM(uniform circular motion) with period 0.500 s and circle centered at the origin of the x and y coordinate system. Let î and ȷ be the unit vectors along the x and y directions, respectively. At instant t=0 the particle's acceleration vector (in m/s2) is a =2.30î. What is its acceleration vector (in m/s2) at time t=2.50 s?arrow_forwardFrom the origin, a particle starts at t = 0 s with a velocity vecv=7.0hatim//s and moves in the xy plane with a constant acceleration of veca=(-9.0hati+3.0hatj)m//s^(2). At the time the particle reaches the maximum x coordinate, what is its (a) velocity and (b) position vector?arrow_forwardA particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.40 m, 3.10 m) with a velocity of -3.20 i m/s and an acceleration of +14.3 j m/s?. What are the (a) x and (b) y coordinates of the center of the circular path? (a) Number Unit (b) Number Unitarrow_forward
- A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (4.00 m, 4.00 m) with a velocity of 5.00 m/s and an acceleration of +12.5 m/s2. What are the (a) x and (b) y coordinates of the center of the circular path?arrow_forwardChapter 04, Problem 064 SN A particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point with coordinates (x, y) with a velocity of vi and an acceleration of -a j. In these expressions, v and a are the speed and the magnitude of acceleration, respectively, and thus are positive quantities. In terms of the variables given, what are the coordinates (a) xo and (b) yo of the center of the circular path? (a) Xo = Edit (b) Yo = ? Edit Click if you would like to Show Work for this question: Open Show Work Question Attempts: 0 of 10 used SAVE FOR LATER SUBMIT ANSWERarrow_forwardA particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.20 m, 4.60 m) with a velocity of -4.40 î m/s and an acceleration of +10.4 m/s². What are the (a) x and (b) y coordinates of the center of the circular path?arrow_forward
- A particle is in uniform circular motion about the origin of an xy coordinate system, moving clockwise with a period of 7.00 s. At one instant, its position vector (measured from the origin) is r: = (2.00 m)iˆ - (3.00 m). At that instant, what is its velocity in unit-vector notation?arrow_forwardA particle confined to the xy-plane is in uniform circular motion around the origin. The x- and y-coordinates of the particle vary with time as follows: x(t) = r sin(cot) y(t) = r cos(cot). where >= 2.60 m and c = 2.15 s-¹. What are the x- and y-components of the particle's acceleration at an instant when x = 1.00 m and y = 2.40 m. Give your answers by entering numbers into the empty boxes below. ax || || X x² ms ms-2.arrow_forwardA particle moves horizontally in uniform circular motion, over a horizontal xy plane. At one instant, it moves through the point at coordinates (3.70 m, 4.10m) with a velocity of -2.70 7 m/s and an acceleration of +12.9 m/s². What are the (a) x and (b) y coordinates of the center of the circular path? (a) Number i (b) Number i Unit Unitarrow_forward
- Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning