COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 27, Problem 2QAP
To determine
The difference between the atomic number and mass number.
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Strontium - 90 has a half-life of 25 years.How long will it take 10 grams of Strontium – 90 to decay to 3 grams? Round your answer to the nearest hundredth.
time
A = A.•()
half-life
final
amount
initial
amount
This is the split factor.
After a half-life, one pound
becomes pound.
Your answer:
O not enough information is given
O 0.03 years
O 43.42 years
Chapter 27 Solutions
COLLEGE PHYSICS
Ch. 27 - Prob. 1QAPCh. 27 - Prob. 2QAPCh. 27 - Prob. 3QAPCh. 27 - Prob. 4QAPCh. 27 - Prob. 5QAPCh. 27 - Prob. 6QAPCh. 27 - Prob. 7QAPCh. 27 - Prob. 8QAPCh. 27 - Prob. 9QAPCh. 27 - Prob. 10QAP
Ch. 27 - Prob. 11QAPCh. 27 - Prob. 12QAPCh. 27 - Prob. 13QAPCh. 27 - Prob. 14QAPCh. 27 - Prob. 15QAPCh. 27 - Prob. 16QAPCh. 27 - Prob. 17QAPCh. 27 - Prob. 18QAPCh. 27 - Prob. 19QAPCh. 27 - Prob. 20QAPCh. 27 - Prob. 21QAPCh. 27 - Prob. 22QAPCh. 27 - Prob. 23QAPCh. 27 - Prob. 24QAPCh. 27 - Prob. 25QAPCh. 27 - Prob. 26QAPCh. 27 - Prob. 27QAPCh. 27 - Prob. 28QAPCh. 27 - Prob. 29QAPCh. 27 - Prob. 30QAPCh. 27 - Prob. 31QAPCh. 27 - Prob. 32QAPCh. 27 - Prob. 33QAPCh. 27 - Prob. 34QAPCh. 27 - Prob. 35QAPCh. 27 - Prob. 36QAPCh. 27 - Prob. 37QAPCh. 27 - Prob. 38QAPCh. 27 - Prob. 39QAPCh. 27 - Prob. 40QAPCh. 27 - Prob. 41QAPCh. 27 - Prob. 42QAPCh. 27 - Prob. 43QAPCh. 27 - Prob. 44QAPCh. 27 - Prob. 45QAPCh. 27 - Prob. 46QAPCh. 27 - Prob. 47QAPCh. 27 - Prob. 48QAPCh. 27 - Prob. 49QAPCh. 27 - Prob. 50QAPCh. 27 - Prob. 51QAPCh. 27 - Prob. 52QAPCh. 27 - Prob. 53QAPCh. 27 - Prob. 54QAPCh. 27 - Prob. 55QAPCh. 27 - Prob. 56QAPCh. 27 - Prob. 57QAPCh. 27 - Prob. 58QAPCh. 27 - Prob. 59QAPCh. 27 - Prob. 60QAPCh. 27 - Prob. 61QAPCh. 27 - Prob. 62QAPCh. 27 - Prob. 63QAPCh. 27 - Prob. 64QAPCh. 27 - Prob. 65QAPCh. 27 - Prob. 66QAPCh. 27 - Prob. 67QAPCh. 27 - Prob. 68QAPCh. 27 - Prob. 69QAPCh. 27 - Prob. 70QAPCh. 27 - Prob. 71QAPCh. 27 - Prob. 72QAPCh. 27 - Prob. 73QAPCh. 27 - Prob. 74QAPCh. 27 - Prob. 75QAPCh. 27 - Prob. 76QAPCh. 27 - Prob. 77QAPCh. 27 - Prob. 78QAPCh. 27 - Prob. 79QAPCh. 27 - Prob. 80QAPCh. 27 - Prob. 81QAPCh. 27 - Prob. 82QAPCh. 27 - Prob. 83QAPCh. 27 - Prob. 84QAPCh. 27 - Prob. 85QAPCh. 27 - Prob. 86QAPCh. 27 - Prob. 87QAPCh. 27 - Prob. 88QAPCh. 27 - Prob. 89QAPCh. 27 - Prob. 90QAPCh. 27 - Prob. 91QAPCh. 27 - Prob. 92QAPCh. 27 - Prob. 93QAPCh. 27 - Prob. 94QAPCh. 27 - Prob. 95QAPCh. 27 - Prob. 96QAPCh. 27 - Prob. 97QAP
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- Data from the appendices and the periodic table may be needed for these problems. Unreasonable Results (a) Repeat Exercise 31.57 but include the 0.0055% natural abundance of 234U with its 2.45105y halflife. (b) What is unreasonable about this result? (c) What assumption is responsible? (d) Where does the 234U come from if it is not primordial?arrow_forward•61 The isotope 238SU decays to 206 Pb with a half-life of 4.47 x 10° y. Although the decay occurs in many individual steps, the first step has by far the longest half-life; therefore, one can often consider the decay to go directly to lead. That is, 238U → 206Pb + various decay products. A rock is found to contain 4.20 mg of 23$U and 2.135 mg of 206PB. Assume that the rock contained no lead at formation, so all the lead now present arose from the decay of uranium. How many atoms of (a) 238U and (b) 206Pb does the rock now contain? (c) How many atoms of 238U did the rock contain at formation? (d) What is the age of the rock?arrow_forward3) Assume that this room was filled with a gas of oxygen molecules O₂ in thermal equilibrium at 0 °C. There are 8 protons and 8 neutrons in the nucleus of an oxygen atom O. You may take the masses of the proton and the neutron to be the same, and ignore the mass of the electrons. 1 atm=1.01x105 N/m², h=1.05x10-34 J-s, mp=1.67x10-27 kg, ka=1.38x10-23 J/K. a) What would the (particle) number density, n, be according to the ideal gas law? b) Compare the number density with the quantum concentration, no, at the same temperature. Is the gas in the classical or quantum regime?arrow_forward
- The half-life of Unobtanium-118 is 3 days. How many days pass for 800 grams of this element to be reduced to 25 grams? • Previousarrow_forward47 - 48. A radioactive substance has a half-life of approximately 10 years. If 25 g of the material was stored for 15 years, how much of the material would be left? O 1.9 g O 4.5 g O 9g O 2garrow_forward13) Compute the approximate nuclear radius of bismuth (A = 209).arrow_forward
- 1. The decay of radioactive substance is given by T N = Nᵒe (1), where N is the number of atoms present at time t, No is the initial number of atoms and 7 is the exponential decay constant, which is related to the decay rate of the element. The half-life thalf is N the time required for the number to atoms to decay by half (- No = 0.693 x ✔ S -1/2). Solve for thalf starting from equation (1) in terms of T. Note: Use MathType to enter in T. Do not use the letter "T" from the keyboard. Don't forget the multiplication sign between variables. Use the asterisk symbol (*) for multiplication or the multiplication symbol in the math editor (orange box). thalf =arrow_forward•3 @ A thermal neutron (with approximately zero kinetic energy) is absorbed by a 23U nucleus. How much energy is transferred from mass energy to the resulting oscillation of the nucleus? Here are some atomic masses and the neutron mass. 237U 237.048 723 u 239U 239.054 287 u 238U 238.050 782 u 240U 240.056 585 u 1.008 664 uarrow_forwardWhich of the following best describes the atom? I - Large-mass positive charges are found inside the nucleus. II - Smaller-mass negative charges are found outside the nucleus. III - Large-mass neutral charges are found outside the nucleus. O I & II O I & III O II & III O I, II, & IIIarrow_forward
- In a real or imaginary nucleus of 45X⁹7, (a) how many protons are in the nucleus, (b) how many neutrons are in the nucleus, and (c) how many electrons are in orbit about the nucleus, assuming the atom is electrically neutral? (a) Number (b) Number i (c) Number Units Units Unitsarrow_forwardThe rate at which radon is being created is the rate at which radium is decaying, namely A1 N1 or A1 Noe-Ait. But the radon is also decaying at the rate A,N2. Hence, we have dN2 = \1N1 – A2N2, dt or dN2 + A2N2 = A1N1 = 11 Noe¬A1t_ dt This equation is of the form (3.1), and we solve it as follows: I = / A2 dt = Azt, (3.10) N2e^2t A, Noe-Aite^2t dt + c = e(A2-A1)t dt + c= d1 No (A2-A1)t + c, A2 - A1 12, see Problem 19.) Since N2 = 0 at t = 0 (we if A1 + d2. (For the case A1 assumed pure Ra at t = 0), we must have d1 No A1 No 0 = d2 – di or c = Substituting this value of c into (3.10) and solving for N2, we get d, No (e- d2 - A1 - e-Aat). Ait N2arrow_forwardIn the planetary model of the atom where electrons orbit a centralized nucleus, what is the approximate ratio of the radius of the nucleus to that of the electron orbits?arrow_forward
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