Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 23, Problem 17P
To determine
The maximum surface charge density that can exist at the end of sharp lightning rod.
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Electric charge can accumulate on an airplane in flight. You may have observed needle-shaped metal extensions on the wing tips and tail of an airplane. Their purpose is to allow charge to leak off before much of
it accumulates. The electric field around the needle is much larger than the field around the body of the airplane and, can become large enough to produce dielectric breakdown of the air, discharging the airplane.
To model this process, assume that two charged spherical conductors are connected by a long conducting wire and a charge of 60.0 µC is placed on the combination. One sphere, representing the body of the
airplane, has a radius of 6.00 m, and the other, representing the tip of the needle, has a radius of 2.00 cm.
(a) What is the electric potential of each sphere?
r = 6.00 m:
V
r = 2.00 cm:
(b) What is the electric field at the surface of each sphere?
r = 6.00 m:
magnitude
V/m
direction
---Select--
r = 2.00 cm:
magnitude
V/m
direction
--Select---
Two negative charges are kept at a certain distance in the air medium. What will happen if a dielectric slab is inserted between them?
If the magnitude of the electrical force between two point charges with the same sign in the air is 400 N, what is the magnitude of the force between these two charges when they are immersed in water? (Relative dielectric constant of water is 80)
Chapter 23 Solutions
Physics for Scientists and Engineers
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- (a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 5.00 cm2? (b) Find the maximum charge if polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00 106 V/m and that of polystyrene is 24.0 106 V/m.arrow_forwardFind an expression for the electric field between the two conducting disks in Figure P27.61. Make sure your expression is general enough to include the possibility of a dielectric between the disks. Check your answer using the information given in Section 27-8. Figure P27.61arrow_forwardCalculate the angular velocity of an electron orbiting a proton in the hydrogen atom, given the radius of the orbit is 0.5301010 m. You may assume that the proton is stationary and the centripetal force is supplied by Coulomb attraction.arrow_forward
- Electric charge can accumulate on an airplane in flight. You may have observed needleshaped metal extensions on the wing tips and tail of an airplane. Their purpose is to allow charge to leak off before much of it accumulates. The electric field around the needle is much larger than the field around the body of the airplane and can become large enoughto produce dielectric breakdown of the air, discharging the airplane. To model this process, assume two charged spherical conductors are connected by a long conducting wire and a 1.20-μC charge is placed on the combination. One sphere, representing the body of the airplane, has a radius of 6.00 cm; the other, representing the tip of the needle, has a radius of 2.00 cm. (a) What is the electric potential of each sphere? (b) What is theelectric field at the surface of each sphere?arrow_forwardTwo pith balls, each with a mass of 5.00 g, are attached to non-conducting threads and suspended from the same point on the celling. Each thread has a length of 1.00 m. The balls are then given an identical charge, which causes them to separate. At the point that the elctric and gravitational forces balance, the threads are separated by an angle of 30.0°. Calculate the charge of each pith ball.arrow_forward(a) How much charge can be placed on a capacitor with air between the plates before it breaks down if the area of each plate is 5.00 cm2 ? (b) Find the maximum charge if polystyrene is used between the plates instead of air. Assume the dielectric strength of air is 3.00 × 106 V/m and that of polystyrene is 24.0 × 106 V/m.arrow_forward
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