In Exercises 11–14, solve the systems of equations by substitution.
13.
Want to see the full answer?
Check out a sample textbook solutionChapter 2 Solutions
College Algebra in Context with Applications for the Managerial, Life, and Social Sciences (5th Edition)
- Write a uniform motion problem similar to Example 4.15 that relates to where you live with your friends or family members. Then translate to a system of equations and solve it.arrow_forwardIn Exercises 15–16, solve each system by eliminating variables using the addition method. 15. [3x + 12y = 25 |2r - 6y = 12 x + 3y -x + 2y + 3z 2х - 5у — г 16. 5 13 -8arrow_forwardFor Exercises 73–80, (a) evaluate the discriminant and (b) determine the number and type of solutions to each equation. (See Example 9) 73. Зх? 4х + 6 3D 0 74. 5x - 2x + 4 = 0 75. - 2w? + 8w = 3 76. -6d + 9d = 2 77. Зx(х — 4) 3D х — 4 78. 2x(x – 2) = x + 3 79. –1.4m + 0.1 = -4.9m² 80. 3.6n + 0.4 = -8.1n?arrow_forward
- Exercises 149–151 will help you prepare for the material covered in the next section. 149. Multiply: (Vx + 4 + 1)2. 150. Solve: 4x2 16x + 16 = 4(x + 4). 151. Solve: 26 – 11x 16 – 8x + x?.arrow_forwardFor Exercises 81–100, make an appropriate substitution and solve the equation. (See Examples 10–11) 81. (2x + 5)? – 7(2x + 5) - 30 = 0 82. (Зх — 7)? - 6(3х — 7)-16 3D 0 83. (x + 2x)? – 18(r + 2x) = -45 84. (x + 3x)? - 86. (у? — 3)? — 9(y? — 3) — 52 %3D 0 14(x + 3x) = -40 85. (x + 2)2 + (x + 2) – 42 = 0 10 2 10 - 61 m - - 27 = 0 x + + 35 = 0 87. 88. - 121 x + т - m m 89. 2 + 2 + = 12 90. + 3 + 6 + 3 = -8 91. 5c2/5 11c/5 + 2 = 0 92. З3 d'/3 – 4 = 0 93. y'/2 – y/4 6 = 0 94. n'/2 + 6n/4 – 16 = 0 95. 9y 10y + 1 = 0 96. 100х-4 29x-2 + 1 = 0 | 97. 4t – 25 Vi = 0 98. 9m – 16Vm = 0 100. 392 + 16q -1 99. 30k-2 – 23k- + 2 = 0 + 5 = 0arrow_forward5. (06.03) 5.(06.03) How can X-3 X+8 be set up as a system of equations? 4. 2. Bi U Font Family - AA- A =arrow_forward
- The equation in the form Ax + By = C (-6,3) and (0,-2)arrow_forwardExercises 7–12: Determine whether the equation is linear or nonlinear by trying to write it in the form ax + b = 0. 9. 2Va + 2 = 1arrow_forwardFor Exercises 5–10, a. Simplify the expression. b. Substitute 0 for h in the simplified expression. 2(x + h)? + 3(x + h) · 5. (2x + 3x) 3(x + h - 4(x + h) – (3x - 4x) 6. h 1 1 1 1 (x + h) – 2 7. x - 2 2(x + h) + 5 8. 2x + 5 h (x + h) – x 9. (x + h) 10. - X h harrow_forward
- 8. Identify the number of solutions from the description of the equations. Two equations are the same on one side but different on the other. • One of the equations in the system can be rewritten so it is identical to the other equation.arrow_forwardSolve the equations * 2x – y + 3z = -3, 3.x + 3y – z = 10, -x – y + z = -4 O x = 2, y = 1, z = -4 Ox = 4, y = 2, z = -4 O x = 1, y = 2, z = -4 O x = 1, y = 2, z = -1arrow_forward24. Solve the system of equations.* y=-2x² 3x2 +y = 52 *More than one answer may be correct; check all that apply. O (4, – 8) 13 (2i, - 8) 13 ン V13 2. 13) O -21, 4) O (-2i, - 8) (-V13, – 8) □ (學,-号 ) V13 (2i, )arrow_forward
- Big Ideas Math A Bridge To Success Algebra 1: Stu...AlgebraISBN:9781680331141Author:HOUGHTON MIFFLIN HARCOURTPublisher:Houghton Mifflin HarcourtElementary AlgebraAlgebraISBN:9780998625713Author:Lynn Marecek, MaryAnne Anthony-SmithPublisher:OpenStax - Rice University