General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Question
Chapter 21, Problem 55E
(a)
To determine
The maximum transverse velocity of a point on the string.
(b)
To determine
The maximum kinetic energy of a small segment of the string of mass.
(c)
To determine
The maximum potential energy.
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Students have asked these similar questions
A taut rope is tied to a machine that causes it to
oscillate sinusoidally. You take a picture of the
rope and see that at that moment there are four
complete cycles along 10m. If the oscillator
frequency is 20HZ, find:
a) The wave number
b) The angular frequency
c) If at time t = Os, the height of the wave is Om
when x = 0m, find the phase shift of the
oscillation.
d) If at time t = Os, the transverse velocity is 250m
/ s when x = Om, find the amplitude of the
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e) Write the wave function that describes the
behavior of this wave.
A string has a point attached to a motor that makes it oscillate with a simple harmonic motion, if
the generated mechanical wave propagates to the right with amplitude A=0.10 m. A point on the
string takes 1.1 s to complete one oscillation and the wavelength is 50 cm. At the instant when
time begins, t=0 s, the point on the string above the origin of coordinates is 0.10 m above the
equilibrium point.
From the situation described, determine:
A. the wave function.
B. At time t=0 s, which points on the string have maximum elongation (ymax)?
C. the maximum value of the velocity at points on this string.
D. If the motor that makes the string oscillate has a fault and now produces a SHM with a
frequency that is only a quarter of the initial frequency of the movement, what effect does the
period with which the particles of string move have? rope?
The maximum speed of the bob of a simple pendulum is vmax = 1.8 m/s. At the
position where the potential energy is double the kinetic energy (U= 2K), the speed
of the bob is:
O v= 1.16 m/s
O v= 1.04 m/s
O v = 1.27 m/s
O v = 1.38 m/s
The wave function for a wave on a taut string is given by: y(x,t) = 0.08 sin(0.5mxx-
in meters and it is in seconds. The transverse
Chapter 21 Solutions
General Physics, 2nd Edition
Ch. 21 - Prob. 1RQCh. 21 - Prob. 2RQCh. 21 - Prob. 3RQCh. 21 - Prob. 4RQCh. 21 - Prob. 5RQCh. 21 - Prob. 6RQCh. 21 - Prob. 7RQCh. 21 - Prob. 8RQCh. 21 - Prob. 9RQCh. 21 - Prob. 10RQ
Ch. 21 - Prob. 1ECh. 21 - Prob. 2ECh. 21 - Prob. 3ECh. 21 - Prob. 4ECh. 21 - Prob. 5ECh. 21 - Prob. 6ECh. 21 - Prob. 7ECh. 21 - Prob. 8ECh. 21 - Prob. 9ECh. 21 - Prob. 10ECh. 21 - Prob. 11ECh. 21 - Prob. 12ECh. 21 - Prob. 13ECh. 21 - Prob. 14ECh. 21 - Prob. 15ECh. 21 - Prob. 16ECh. 21 - Prob. 17ECh. 21 - Prob. 18ECh. 21 - Prob. 19ECh. 21 - Prob. 20ECh. 21 - Prob. 21ECh. 21 - Prob. 22ECh. 21 - Prob. 23ECh. 21 - Prob. 24ECh. 21 - Prob. 25ECh. 21 - Prob. 26ECh. 21 - Prob. 27ECh. 21 - Prob. 28ECh. 21 - Prob. 29ECh. 21 - Prob. 30ECh. 21 - Prob. 31ECh. 21 - Prob. 32ECh. 21 - Prob. 33ECh. 21 - Prob. 34ECh. 21 - Prob. 35ECh. 21 - Prob. 36ECh. 21 - Prob. 37ECh. 21 - Prob. 38ECh. 21 - Prob. 39ECh. 21 - Prob. 40ECh. 21 - Prob. 41ECh. 21 - Prob. 42ECh. 21 - Prob. 43ECh. 21 - Prob. 44ECh. 21 - Prob. 45ECh. 21 - Prob. 46ECh. 21 - Prob. 47ECh. 21 - Prob. 48ECh. 21 - Prob. 49ECh. 21 - Prob. 50ECh. 21 - Prob. 51ECh. 21 - Prob. 52ECh. 21 - Prob. 53ECh. 21 - Prob. 54ECh. 21 - Prob. 55ECh. 21 - Prob. 56ECh. 21 - Prob. 57ECh. 21 - Prob. 58ECh. 21 - Prob. 59ECh. 21 - Prob. 60ECh. 21 - Prob. 61ECh. 21 - Prob. 62ECh. 21 - Prob. 63ECh. 21 - Prob. 64ECh. 21 - Prob. 65ECh. 21 - Prob. 66ECh. 21 - Prob. 67ECh. 21 - Prob. 68ECh. 21 - Prob. 69ECh. 21 - Prob. 70ECh. 21 - Prob. 71ECh. 21 - Prob. 72ECh. 21 - Prob. 73ECh. 21 - Prob. 74ECh. 21 - Prob. 75ECh. 21 - Prob. 76ECh. 21 - Prob. 77ECh. 21 - Prob. 78ECh. 21 - Prob. 79ECh. 21 - Prob. 80E
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