Essentials of Computer Organization and Architecture
Essentials of Computer Organization and Architecture
5th Edition
ISBN: 9781284123036
Author: Linda Null
Publisher: Jones & Bartlett Learning
Expert Solution & Answer
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Chapter 2, Problem 3E

Explanation of Solution

a)

Converting 137 base 10 to base 3 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 3 which may result in lower number than 137. The number that can be subtracted from the given number 137 with the power of 3 is 81. The number 81 is less than 137. So subtract 81 from 137.

137-81=34x1------------56

Step 2:

The number that can be subtracted from the given number 56 with the power of 3 is 27 and it should be multiplied by 2 in order to get the nearest number of 56. The number 54 is less than 56. So subtract 56 from 54.

56-54=33x2------------2

Step 3:

Take 3 to the power of 2 that is 9. The number 9 is greater than 2. So make the value as 0.

2-0=32x0------------2

Step 4:

Take 3 to power of 1 that is 3

Explanation of Solution

b)

Converting 248 base 10 to base 5 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 5 which may result in lower number than 248. The number that can be subtracted from the given number 248 with the power of 5 is 125. The number 125 is less than 248. So subtract 125 from 248.

248-125=53x1------------123

Step 2:

The number that can be subtracted from the given number 123 with the power of 5 is 25 and it should be multiplied by 4 in order to get the nearest number of 123. The number 100 is less than 123. So subtract 100 from 123.

123-100=52x4------------23

Step 3:

The number that can be subtracted from the given number 23 with the power of 5 is 5 and it should be multiplied by 4 in order to get the nearest number of 23

Explanation of Solution

c)

Converting 387 base 10 to base 7 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 7 which may result in lower number than 387. The number that can be subtracted from the given number 387 with the power of 7 is 343. The number 343 is less than 387. So subtract 343 from 387.

387-343=73x1------------44

Step 2:

Take 7 to power of 2 that is 49. The number 49 is greater than 44. So make the value as 0.

44-0=72x0------------44

Step 3:

The number that can be subtracted from the given number 44 with the power of 7 is 7 and it should be multiplied by 6 in order to get the nearest number of 44. The number 42 is less than 44. So subtract 42 from 44

Explanation of Solution

d)

Converting 633 base 10 to base 9 using subtraction method:

Step 1:

Check the possibility of multiplying any integer with the powers of 9 which may result in lower number than 633. The number that can be subtracted from the given number 633 with the power of 9 is 81 and it should be multiplied by 7 in order to get the nearest number of 633. The number 567 is less than 633. So subtract 567 from 633.

633-567=92x7------------66

Step 2:

The number that can be subtracted from the given number 66 with the power of 9 is 9 and it should be multiplied by 7 in order to get the nearest number of 66. The number 63 is less than 66. So subtract 63 from 66

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Chapter 2 Solutions

Essentials of Computer Organization and Architecture

Ch. 2 - Prob. 11RETCCh. 2 - Prob. 12RETCCh. 2 - Prob. 13RETCCh. 2 - Prob. 14RETCCh. 2 - Prob. 15RETCCh. 2 - Prob. 16RETCCh. 2 - Prob. 17RETCCh. 2 - Prob. 18RETCCh. 2 - Prob. 19RETCCh. 2 - Prob. 20RETCCh. 2 - Prob. 21RETCCh. 2 - Prob. 22RETCCh. 2 - Prob. 23RETCCh. 2 - Prob. 24RETCCh. 2 - Prob. 25RETCCh. 2 - Prob. 26RETCCh. 2 - Prob. 27RETCCh. 2 - Prob. 28RETCCh. 2 - Prob. 29RETCCh. 2 - Prob. 30RETCCh. 2 - Prob. 31RETCCh. 2 - Prob. 32RETCCh. 2 - Prob. 33RETCCh. 2 - Prob. 34RETCCh. 2 - Prob. 1ECh. 2 - Prob. 2ECh. 2 - Prob. 3ECh. 2 - Prob. 4ECh. 2 - Prob. 5ECh. 2 - Prob. 6ECh. 2 - Prob. 7ECh. 2 - Prob. 8ECh. 2 - Prob. 9ECh. 2 - Prob. 10ECh. 2 - Prob. 11ECh. 2 - Prob. 12ECh. 2 - Prob. 13ECh. 2 - Prob. 14ECh. 2 - Prob. 15ECh. 2 - Prob. 16ECh. 2 - Prob. 17ECh. 2 - Prob. 18ECh. 2 - Prob. 19ECh. 2 - Prob. 20ECh. 2 - Prob. 21ECh. 2 - Prob. 22ECh. 2 - Prob. 23ECh. 2 - Prob. 24ECh. 2 - Prob. 25ECh. 2 - Prob. 26ECh. 2 - Prob. 27ECh. 2 - Prob. 29ECh. 2 - Prob. 30ECh. 2 - Prob. 31ECh. 2 - Prob. 32ECh. 2 - Prob. 33ECh. 2 - Prob. 34ECh. 2 - Prob. 35ECh. 2 - Prob. 36ECh. 2 - Prob. 37ECh. 2 - Prob. 38ECh. 2 - Prob. 39ECh. 2 - Prob. 40ECh. 2 - Prob. 41ECh. 2 - Prob. 42ECh. 2 - Prob. 43ECh. 2 - Prob. 44ECh. 2 - Prob. 45ECh. 2 - Prob. 46ECh. 2 - Prob. 47ECh. 2 - Prob. 48ECh. 2 - Prob. 49ECh. 2 - Prob. 50ECh. 2 - Prob. 51ECh. 2 - Prob. 52ECh. 2 - Prob. 53ECh. 2 - Prob. 54ECh. 2 - Prob. 55ECh. 2 - Prob. 56ECh. 2 - Prob. 57ECh. 2 - Prob. 58ECh. 2 - Prob. 59ECh. 2 - Prob. 60ECh. 2 - Prob. 61ECh. 2 - Prob. 62ECh. 2 - Prob. 63ECh. 2 - Prob. 64ECh. 2 - Prob. 65ECh. 2 - Prob. 66ECh. 2 - Prob. 67ECh. 2 - Prob. 68ECh. 2 - Prob. 69ECh. 2 - Prob. 70ECh. 2 - Prob. 71ECh. 2 - Prob. 72ECh. 2 - Prob. 73ECh. 2 - Prob. 74ECh. 2 - Prob. 75ECh. 2 - Prob. 76ECh. 2 - Prob. 77ECh. 2 - Prob. 78ECh. 2 - Prob. 79ECh. 2 - Prob. 80ECh. 2 - Prob. 81ECh. 2 - Prob. 82E
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