
Concept explainers
Consider an
- (a) Diagram the cell, and label each of the components (including the anode, cathode, and salt bridge).
- (b) Use the equations for the half-reactions to write a balanced, net ionic equation for the overall cell reaction.
- (c) What is the polarity of each electrode?
- (d) What is the value of E°cell?
- (e) In which direction do electrons flow in the external circuit?
- (f) Assume that a salt bridge containing NaNO3 connects the two half-cells. In which direction do the Na+(aq) ions move? In which direction do the NO3− (aq) ions move?
- (g) Calculate the equilibrium constant for the reaction.
- (h) If the concentration of Cd2+ is reduced to 0.010 M and [Ni2+] = 1.0 M, what is the value of Ecell? Is the net reaction still the reaction given in part (b)?
- (i) If 0.050 A is drawn from the battery, how long can it last if you begin with 1.0 L of each of the solutions and each was initially 1.0 M in dissolved species? Each electrode weighs 50.0 g in the beginning.
(a)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The cell has to be drawn and label each of the component.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Explanation of Solution
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The voltaic cell are as follows:
(b)

Interpretation:
To determine the following.
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The balance equation has to be given.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Balanced reaction:Cd(s) + Ni2+(aq) →Cd2+(aq) + Ni(s)
Explanation of Solution
Let’s write the half reactions occur at anode and cathode:
At anode:Cd(s) →Cd2+(aq) + 2e-At cathode:Ni2+(aq)+2e- →Ni(s)
By adding these two half reactions we get balanced reaction.
Cd(s) →Cd2+(aq) + 2e-Ni2+(aq)+2e- →Ni(s)________________________Cd(s) + Ni2+(aq) →Cd2+(aq) + Ni(s)
(c)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The polarity of each electrode has to be determined.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Anode is negative cathode is positive.
Explanation of Solution
In the voltaic cell has two voltaic cells. One electrode has positive charge called cathode and another electrode has negative called anode.
(d)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The Eocell has to be calculated.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Eocell of the reaction is 0.15 V
Explanation of Solution
The reactions occur at anode and cathode is as follows.
At anode:Cd(s) →Cd2+(aq) + 2e- ; E0= -0.40 VAt cathode:Ni2+(aq)+2e- →Ni(s) ; E0= -0.25 V
Let’s calculate the Eocell of the reaction
Eocell=Eocathode-Eoanode= -0.25 V-(-0.40) V= 0.15 V
(e)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The direction in which electrons flow in the external circuit has to be given.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Electrons are flow from anode to cathode.
Explanation of Solution
In the voltaic cell electrons are move anode to cathode.
(f)

Interpretation:
To determine the following.
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
Assume that a salt bride containing NaNO3 connect the two half cells. It has to be identified in which direction do Na+(aq) ions and NO-3 (aq) move.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Na+ ions moves from anode to cathode
NO-3 ions move from cathode to anode
Explanation of Solution
Salt bridge contains NaNO3 solution and it is dissociates into Na+ and NO-3 ions.
Na+ ions moves from anode to cathode
NO-3 ions move from cathode to anode
(g)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The equilibrium constant has to be determined.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
The equilibrium constant of the reaction is 1.1×105.
Explanation of Solution
lnK=nE00.0257=(2)(0.15 V)0.0257=11.673K=1.1 ×105
(h)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
If the concentration of Cd2+(aq) is reduced to 0.010 M and [Ni2+]=1.0 M. The Eocell of the reaction has to be calculated.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
Ecell of the reaction is 0.21 V.
Explanation of Solution
Ecell= Eocell-0.02572lnQ=Eocell-0.02572ln[Cd2+][Ni2+]=0.15 V-0.02572ln(0.010 M)(1.0 M)=0.21 V
Net reaction will be still given in part (b)
(i)

Interpretation:
The half reactions are as follows.
Ni2+(aq) + 2e- →Ni(s) and Cd2+(aq)+2e- →Cd(s)
The time the battery will last if 0.050 M is drawn from the battery has to be determined.
Concept introduction:
Voltaic cell or Galvanic cell:
The device to produce electricity by using chemical reactions. In these divces are redox chemical reactions are occured.
A voltaic cell converts chemical energy into electrical energy.
It consists of two half cells. Each half cell consists of a metal and a solution of a salt of metal. Two half cells are connected by salt bridge.
The chemical reaction in the half cell is an oxidation reduction (redox)reactions.
For example:
Cell diagram of voltaic or galvanic cell is as follows.
Salt bridge ↓Cu(s)|Cu2+(aq) || Ag+(aq)|Ag(s)____________ ___________ ↓ ↓ Half cell Half cell
Answer to Problem 99IL
The time required for the electrolysis is 4800 h
Explanation of Solution
Moles of electrons required:Mole e-= (50 g Cd)(1 mol112.4 mol e-)(2 mol e-1 mol Cd)=0.88896 mol e-
Let’s calculate the charge of the cell:
Charge (C) = (0.8896 mol e-)(96500 C1 mol e-)= 8.58 u ×104 C
Therefore, the time can be calculated as follows.
Charge = Current (A) × time (s)8.584×104 C= 0.05 A ×time (s)time (s)=1.7×106 S=4800 h
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Chapter 19 Solutions
Chemistry & Chemical Reactivity
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