Explanation Explanation Given : ‖ N ( u , v ) ‖ = 5 for all ( u, v ) Domain of parameterization is the square 0 ≤ u , v ≤ 2 Formula Used: ∬ S d S = ∬ D ‖ N ( u , v ) ‖ d A Calculations: A r e a ( S ) = ∬ S d S ∬ S d S = ∬ A ‖ N ( u , v ) ‖ d A Given that ‖ N ( u , v ) ‖ = 5 for all ( u, v ), we get: ∬ S d S = ∬ A ( 5 )

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 17.4, Problem 5PQ

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To determine:

A surface S has a parameterization whose domain is the square $0 \leq u, v \leq 2$ such that $‖ N (u, v) ‖ = 5$ for all (u, v). What is Area(S)?

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Chapter 17.4, Problem 4PQ

Chapter 17.4, Problem 6PQ

Chapter 17 Solutions

CALCULUS (CLOTH)

Ch. 17.1 - Prob. 1PQ Ch. 17.1 - Prob. 2PQ Ch. 17.1 - Prob. 3PQ Ch. 17.1 - Prob. 4PQ Ch. 17.1 - Prob. 1E Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - Prob. 5E Ch. 17.1 - Prob. 6E

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A surface S has a parameterization whose domain is the square 0 ≤ u , v ≤ 2 such that ‖ N ( u , v ) ‖ = 5 for all ( u, v ). What is Area( S )?

Solution Summary: The author explains that A surface S has a parameterization whose domain is the square 0 u, v

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To determine:

A surface S has a parameterization whose domain is the square $0 \leq u, v \leq 2$ such that $‖ N (u, v) ‖ = 5$ for all (u, v). What is Area(S)?

Want to see the full answer?

Chapter 17 Solutions

A surface S has a parameterization whose domain is the square 0 ≤ u , v ≤ 2 such that ‖ N ( u , v ) ‖ = 5 for all ( u, v ). What is Area( S )?

Solution Summary: The author explains that A surface S has a parameterization whose domain is the square 0 u, v

Videos

To determine: A surface S has a parameterization whose domain is the square 0≤u,v≤2 such that ‖N(u,v)‖=5 for all (u, v). What is Area(S)?

Want to see the full answer?

Chapter 17 Solutions

To determine:

A surface S has a parameterization whose domain is the square $0 \leq u, v \leq 2$ such that $‖ N (u, v) ‖ = 5$ for all (u, v). What is Area(S)?