Chapter 14, Problem 62A

(a)

Interpretation Introduction

Interpretation: Whether $CC{l}_4$ exhibit London-dispersion forces or not is to be discussed.

Concept introduction: London-dispersion forces are also called Vander Waal forces. These are present between non-polar molecule or atom.

Answer to Problem 62A

$CC{l}_4$ exhibits London-dispersion forces.

Explanation of Solution

$CC{l}_4$ is non-polar molecules because the electrical charges of these molecules are evenly distributed resulting in zero dipole moment. Hence, it exhibit London-dispersion forces or Vander Waal forces.

(b)

Interpretation Introduction

Interpretation: Whether $N{F}_3$ exhibit London-dispersion forces or not is to be discussed.

Concept introduction: London-dispersion forces are also called Vander Waal forces. These are present between non-polar molecule or atom.

Answer to Problem 62A

$N{F}_3$ doesn’t exhibit London-dispersion forces.

Explanation of Solution

$N{F}_3$ is polar molecule because the electrical charges of these molecules are not evenly distributed. Three N-F dipole moments oppose the moment by lone pair on nitrogen resulting in some net dipole moment. Hence, it doesn’t exhibit London-dispersion forces or vanderwaal forces.

(c)

Interpretation Introduction

Interpretation: Whether $C{O}_2$ exhibit London-dispersion forces or not is to be discussed.

Concept introduction: London-dispersion forces are also called Vander Waal forces. These are present between non-polar molecule or atom.

Answer to Problem 62A

$C{O}_2$ exhibits London-dispersion forces.

Explanation of Solution

$C{O}_2$ is nonpolar molecule because the electrical charges of these molecules are evenly distributed resulting in zero dipole moment. Hence, it exhibit London-dispersion forces or vanderwaal forces.

(d)

Interpretation Introduction

Interpretation: Whether $H_2$ exhibit London-dispersion forces or not is to be discussed.

Concept introduction: London-dispersion forces are also called Vander Waal forces. These are present between non-polar molecule or atom.

Answer to Problem 62A

$H_2$ exhibits London-dispersion forces.

Explanation of Solution

$H_2$ is non-polar molecule because the electrical charges of these molecules are evenly distributed resulting in zero dipole moment. Hence, it exhibit London-dispersion forces or vanderwaal forces.

(e)

Interpretation Introduction

Interpretation: Whether $C{O}_3{}^{2-}$ exhibit London-dispersion forces or not is to be discussed.

Concept introduction: London-dispersion forces are also called Vander Waal forces. These are present between non-polar molecule or atom.

Answer to Problem 62A

$C{O}_3{}^{2-}$ doesn’t exhibit London-dispersion forces.

Explanation of Solution

$C{O}_3{}^{2-}$ is polar molecule because the electrical charges of these molecules are not evenly distributed resulting in some net dipole moment. Hence, it doesn’t exhibit London-dispersion forces or vander Waal forces.