Genetics: From Genes to Genomes
6th Edition
ISBN: 9781259700903
Author: Leland Hartwell Dr., Michael L. Goldberg Professor Dr., Janice Fischer, Leroy Hood Dr.
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Textbook Question
Chapter 13, Problem 43P
An allotetraploid species has a genome composed of two ancestral genomes, A and B, each of which have a basic chromosome number (x) of seven. In this species, the two copies of each chromosome of each ancestral genome pair only with each other during meiosis. Resistance to a pathogen that attacks the foliage of the plant is controlled by a dominant allele at the F locus. The recessive alleles Fa and Fb confer sensitivity to the pathogen, but the dominant resistance alleles present in the two genomes have slightly different effects. Plants with at least one FA allele are resistant to races 1 and 2 of the pathogen regardless of the genotype in the B genome, and plants with at least one FB allele are resistant to races 1 and 3 of the pathogen regardless of the genotype in the A genome. What proportion of the self-progeny of an FA Fa FB Fb plant will be resistant to all three races of the pathogen?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Chlamydomonas, a eukaryotic green alga, may be sensitive to the antibiotic erythromycin, which inhibits protein synthesis in bacteria. There are two mating types in this alga, mt+ and mt-. If an mt+ cell sensitive to the antibiotic is crossed with an mt- cell that is resistant, all progeny cells are sensitive. The reciprocal cross (mt+ resistant and mt- sensitive) yields all resistant progeny cells. Assuming that the mutation for resistance is in the chloroplast DNA, what can you conclude from the results of these crosses?
In rice, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of rice plants (i.e. the stamen) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile rice plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines. Give the result(s) of the cross and explain the phenotype of the offspring.
In corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of corn plants (i.e. the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male-fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male-sterile lines.
Using the following color-coded circles, simulate the crosses indicated below. Put the illustrations of crosses in the spaces provided. Be sure to include in the labels the genotypes and phenotypes of the offspring in each cross.
Big light green circle - male-sterile cytoplasm
Big orange circle - male-fertile cytoplasm
Small orange circle - FF nucleus
Small half-light green-half-orange circle - Ff nucleus
Small light-green circle - ff nucleus
Chapter 13 Solutions
Genetics: From Genes to Genomes
Ch. 13 - For each of the terms in the left column, choose...Ch. 13 - Prob. 2PCh. 13 - For each of the following types of chromosomal...Ch. 13 - For the following types of chromosomal...Ch. 13 - One of the X chromosomes in a particular...Ch. 13 - A diploid strain of yeast was made by mating a...Ch. 13 - The two graphs that follow represent genomic...Ch. 13 - A series of chromosomal mutations in Drosophila...Ch. 13 - Indicate which of the four major classes of...Ch. 13 - The recessive, X-linked z1 mutation of the...
Ch. 13 - Genes a and b are 21 m.u. apart when mapped in...Ch. 13 - In the following group of figures, the pink lines...Ch. 13 - Three strains of Drosophila Bravo, X-ray, and...Ch. 13 - Two yeast strains were mated and sporulated...Ch. 13 - Suppose a haploid yeast strain carrying two...Ch. 13 - In the mating between two haploid yeast strains...Ch. 13 - During ascus formation in Neurospora, any...Ch. 13 - In the following figure, black and pink lines...Ch. 13 - In Drosophila, the gene for cinnabar eye color is...Ch. 13 - Semisterility in corn, as seen by unfilled ears...Ch. 13 - A promising biological method for insect control...Ch. 13 - Prob. 23PCh. 13 - a. Among the progeny of a self-fertilized...Ch. 13 - Duchenne muscular dystrophy DMD is caused by a...Ch. 13 - WHIM syndrome is a disease of the immune system...Ch. 13 - Explain how transposable elements can cause the...Ch. 13 - The Drosophila genome normally harbors about 40 P...Ch. 13 - Drosophila P elements were discovered because of a...Ch. 13 - Flies homozygous for mutant alleles of a...Ch. 13 - Fred and Mary have a child named Bob. The genomic...Ch. 13 - Uniparental disomy is a rare phenomenon in which...Ch. 13 - Among adults with Turner syndrome, it has been...Ch. 13 - In Neurospora, his2 mutants require the amino acid...Ch. 13 - Human geneticists interested in the effects of...Ch. 13 - The incidence of Down syndrome will be very high...Ch. 13 - The Drosophila chromosome 4 is extremely small;...Ch. 13 - Down syndrome is usually caused by having a...Ch. 13 - Common red clover, Trifolium pratense, is a...Ch. 13 - The numbers of chromosomes in the somatic cells of...Ch. 13 - Prob. 41PCh. 13 - Somatic cells in organisms of a particular diploid...Ch. 13 - An allotetraploid species has a genome composed of...Ch. 13 - Prob. 44PCh. 13 - Chromosomes normally associate during meiosis I as...Ch. 13 - Using whole-genome sequencing, how could you...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Seedless watermelons that you find in the...Ch. 13 - The names of hybrid animals are usually themselves...Ch. 13 - While most animals cannot tolerate polyploidy,...Ch. 13 - What characteristic property of translocations...Ch. 13 - Prob. 53PCh. 13 - In the accompanying figure, the top and bottom...Ch. 13 - Prob. 55PCh. 13 - The accompanying figure shows idiograms of human...Ch. 13 - Prob. 57P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Consider a maize plant: Genotype C/cm ; Ac/Ac+ where cm is an unstable colorless allele caused by Ds insertion. What phenotypic ratios would be produced and in what proportions when this plant is crossed with a mutant c/c Ac+/Ac+? Assume that the Ac and c loci are unlinked, that the chromosome-breakage frequency is negligible, and the C allele encodes pigment production.arrow_forwardFor a haploid fungus, the starting point in the biosynthesis of the amino acid arginine is Compound X, which is always present in and absorbed from the environment. The arginine biosynthetic pathway is: Enzyme A Enzyme B Enzyme Ç Compound X It is know that genes encoding enzymes A and C are on two different chromosomes. Compound Y Compound Z- Arginine A mutant strain of genotype a (lacking only enzyme A) is crossed to a mutant strain of genotype c (lacking only enzyme C) to generate a diploid strain. Sporulation (i.e. meiosis) is subsequently induced in the resulting diploid strain. What proportion of the spores (haploids formed by sporulation) is expected to grow on medium without arginine but supplemented with Compound Y? O 100% 50% 0% 25%arrow_forwardFemales heterozygous for the recessive second chromosome mutations px, sp, and cn are mated to a male homozygous for all three mutations. The offspring are as follows: Must show all work 1.) What gene is in the middle? and what are the map distances between the genes in centimorgans? 2.) What is the interference?arrow_forward
- In autotetraploid Chinese primrose (Primula sinensis L.), the gene controlling stigma color is very near the centromere of the chromosome carrying it. The allele G for green stigma is dominant to g for red stigmas. A homozygous green autotetraploid strain is crossed with a homozygous red autotetraploid strain. Each of the F1 GGgg plants would obtain 12 gametes which are 2GG, 8Gg, and 2g. How were these obtained?arrow_forwardIn the fruit fly, dumpy wings (d) and purple eyes (p) are encoded by mutant alleles that are recessive to those that produce wild type traits; long wings (d+) and red eyes (p+). These two genes are on the same chromosome. In a particular lab, two researchers Walt and Jesse crossed a fly homozygous for dumpy wings and purple eyes with a fly homozygous for the wild type traits. The F1 progeny, which had long wings and red eyes, was then crossed with flies that had dumpy wings and purple eyes. Unfortunately, the progeny of this cross somehow escaped. To prevent their other projects from contamination, they decided to spend an exceptionally boring hour in the lab catching and counting the progeny and found the following: long wings, red eyes – 482 dumpy wings, purple eyes – 473 long wings, purple eyes – 23 dumpy wings, red eyes - 22 What is the genetic distance between these two loci? a. 4.5 cM b. 55 cM c. 45 cM d. 49.5 cM e. 4.7 cMarrow_forwardMale Drosophila from a true-breeding wild-type stock were irradiated with X-rays and then mated with females from a true-breeding stock carrying the following recessive mutations on the X chromosome: yellow body (y), crossveinless wings (cv), cut wings (ct), singed bristles (sn), and miniature wings (m). These markers are known to map in the order: Recessive alleles: y, cv, ct, sn, m Dominant alleles: y+, cv+, ct+, sn+, m+ y-cv-ct-sn-m у CV ct sn m X-rays х х X ct sn CV у m y+ CV+ ct+ sn+ m+ х X ? Exceptional female: Most of the female progeny of this cross were phenotypically wild type, but one female exhibited ct and sn mutant characteristics. When this exceptional ct sn female was mated with a male from the true-breeding wild-type stock, twice as many females as males appeared among the progeny. a. What is the nature of the X-ray-induced mutation present in the exceptional female? b. Draw the X chromosomes present in the exceptional ct sn female as they would appear during pairing…arrow_forward
- In a wild-type fungus, protein E (encoded by the haplosufficient gene E) normally dimerizes to catalyzes a biochemical reaction necessary for the production of a dark pigment. Ed represents a mutant, dominant negative allele of gene E. What is the predicted phenotype of a fungus cell of genotype E*/Ed, and why? O wild type (normal production of the dark pigment), as E is haplosufficient mutant (no pigment production), as no dimers will form in the heterozygous mutant (no pigment production), as the mutant allele Eg is dominant O wild type (normal production of the dark pigment), as dimers of wild-type and mutant protein E will be formed in the heterozygousarrow_forwardConsider a Droscophilia fly with a genotype of Nn XqYY. The dominant allele of the sex-linked gene specifies a black body and the recessive a white body. The recessive autosomal allele specifies hairy bristles while the dominant allele specifies smooth bristles. i)What is the ploidy of this fly? ii) What would the sex of this fly be? iii)What would the phenotype of this fly be with respect to these two loci?arrow_forwardL, R, P and D are four genes located on the same chromosome in a diploid organism. Map distances between different pairs of genes were determined and the following results obtained. Based on these data, what is the order of the genes on the chromosome? D-R: 35 CM P-D: 5 CM L-R: 10 CM D-P: 30 CM D-L 25 CM P-R: 40 CM Note that only one orientation of the order is given as an answer choice. For example: ABCD has the same order as DCBA, but only ABCD would be listed as a possible answer. So be sure to check both orientations when comparing your gene order to the possible answer choices. D-L-P-R P-D-L-R P-R-D-L L-P-R-D R-L-D-Parrow_forward
- Wild-type mice have brown fur and short tails. Loss of function of a particular gene produces white fur, while loss of function of another gene produces long tails, and loss of function at a third locus produces agitated behavior. Each of these loss of function alleles is recessive. If a wild-type mouse is crossed with a triple mutant, and their F1 progeny is test-crossed, the following recombination frequencies are observed among their progeny. Produce a genetic map for these loci. Brown, short tailed, normal: 955 White, short tailed, normal: 16 Brown, short tailed, agitated: 0 White, short tailed, agitated: 36 Brown, long tailed, normal: White, long tailed, normal: Brown, long tailed, agitated: 46 0 14 White, long tailed, agitated: 933arrow_forwardIn corn, male sterility is controlled by maternal cytoplasmic elements. This phenotype renders the male part of the corn plants (i.e the tassel) unable to produce fertile pollen; the female parts, however, remain receptive to pollination by pollen from male fertile corn plants. However, the presence of a nuclear fertility restorer gene F restores fertility to male sterile lines Using the cardboard chips, simulate the crosses indicated below. Give the genotypes and phenotypes of the offsprings in each cross, and properly label the nucleus and the cytoplasm of each individual in the cross Legend male sterile cytoplasm Male fertile cytoplasm FF nucleus Ff nucleus ff nucleus A. Male sterile female x FF male Explain the phenotype of the offspring B. Male sterile female x Ff male Explain the phenotype of the offspringarrow_forwardIn Drosophila, a fully heterozygous female with the X-linked recessive genes a, b, and c (not necessarily in that order on the chromosome) was mated to a male that was genetically a, b, c (not necessarily in that order on the chromosome). The offspring occurred in the following phenotypic ratios: Phenotypes: Numbers: What is the cis/trans arrangement in the heterozygous parent? Wild 426 а, с, b 428 Which gene is in the middle? a 23 c, b 22 If you added 23, 22, 3, and 2, it would give you the map distance between genes C 49 b, a 46 What calculation would you make to determine if interference was occurring? (you don't have to complete the calculation) b. C, a Total 1000 3.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Mechanisms of Genetic Change or Evolution; Author: Scientist Cindy;https://www.youtube.com/watch?v=5FE8WvGzS4Q;License: Standard Youtube License