World of Chemistry, 3rd edition
World of Chemistry, 3rd edition
3rd Edition
ISBN: 9781133109655
Author: Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher: Brooks / Cole / Cengage Learning
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Chapter 12, Problem 14A
Interpretation Introduction

Interpretation:

The importance of polarity in water is to be discussed.

Concept introduction:

A covalent bond which is formed by two different atom is polar in nature and its polarity is numerically calculated using dipole moment.

Dipole moment of a bond is defined as product of the charge carried by atom multiplied by distance between the charges.

Let’s consider a bond AB having charge +and with r distance apart, dipole moment is given by:

  dipolemoment=q×r

The units of dipole moment are esucmandDebye(D)

Expert Solution & Answer
Check Mark

Answer to Problem 14A

The presence of dipole moment in water makes it polar and allows it to form hydrogen bonding, to dissolve many compounds in it.

Explanation of Solution

Water is polar because electronegativity of oxygen is more than hydrogen. Oxygen pulls electron density towards itself making hydrogen partially positive. Thus, water is polar. And as the solvency rule says- like dissolves like. So, polar nature of water helps it to work as solvent for many solutes.

  World of Chemistry, 3rd edition, Chapter 12, Problem 14A

Conclusion

Thus, polarity in water helps it be a good solvent.

Chapter 12 Solutions

World of Chemistry, 3rd edition

Ch. 12.2 - Prob. 4RQCh. 12.2 - Prob. 5RQCh. 12.2 - Prob. 6RQCh. 12.2 - Prob. 7RQCh. 12.3 - Prob. 1RQCh. 12.3 - Prob. 2RQCh. 12.3 - Prob. 3RQCh. 12.3 - Prob. 4RQCh. 12.4 - Prob. 1RQCh. 12.4 - Prob. 2RQCh. 12.4 - Prob. 3RQCh. 12.4 - Prob. 4RQCh. 12.4 - Prob. 5RQCh. 12 - Prob. 1ACh. 12 - Prob. 2ACh. 12 - Prob. 3ACh. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Prob. 6ACh. 12 - Prob. 7ACh. 12 - Prob. 8ACh. 12 - Prob. 9ACh. 12 - Prob. 10ACh. 12 - Prob. 11ACh. 12 - Prob. 12ACh. 12 - Prob. 13ACh. 12 - Prob. 14ACh. 12 - Prob. 15ACh. 12 - Prob. 16ACh. 12 - Prob. 17ACh. 12 - Prob. 18ACh. 12 - Prob. 19ACh. 12 - Prob. 20ACh. 12 - Prob. 21ACh. 12 - Prob. 22ACh. 12 - Prob. 23ACh. 12 - Prob. 24ACh. 12 - Prob. 25ACh. 12 - Prob. 26ACh. 12 - Prob. 27ACh. 12 - Prob. 28ACh. 12 - Prob. 29ACh. 12 - Prob. 30ACh. 12 - Prob. 31ACh. 12 - Prob. 32ACh. 12 - Prob. 33ACh. 12 - Prob. 34ACh. 12 - Prob. 35ACh. 12 - Prob. 36ACh. 12 - Prob. 37ACh. 12 - Prob. 38ACh. 12 - Prob. 39ACh. 12 - Prob. 40ACh. 12 - Prob. 41ACh. 12 - Prob. 42ACh. 12 - Prob. 43ACh. 12 - Prob. 44ACh. 12 - Prob. 45ACh. 12 - Prob. 46ACh. 12 - Prob. 47ACh. 12 - Prob. 48ACh. 12 - Prob. 49ACh. 12 - Prob. 50ACh. 12 - Prob. 51ACh. 12 - Prob. 52ACh. 12 - Prob. 53ACh. 12 - Prob. 54ACh. 12 - Prob. 55ACh. 12 - Prob. 56ACh. 12 - Prob. 57ACh. 12 - Prob. 58ACh. 12 - Prob. 59ACh. 12 - Prob. 60ACh. 12 - Prob. 61ACh. 12 - Prob. 62ACh. 12 - Prob. 63ACh. 12 - Prob. 64ACh. 12 - Prob. 1STPCh. 12 - Prob. 2STPCh. 12 - Prob. 3STPCh. 12 - Prob. 4STPCh. 12 - Prob. 5STPCh. 12 - Prob. 6STPCh. 12 - Prob. 7STPCh. 12 - Prob. 8STPCh. 12 - Prob. 9STP
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