Chapter 11.1, Problem 33IP

a.

To determine

To find: $m\angle WXY\text{ and }m\angle YXZ$

Answer to Problem 33IP

  $m\angle WXY={60}^{\circ }$

  $m\angle YXZ={120}^{\circ }$

Explanation of Solution

Given: A clock showing 6 o’clock and 10 seconds.

  

In clock two consecutive number subtended ${30}^{\circ }$ at center.

For $m\angle WXY$ two numbers are there.

So, $m\angle WXY={60}^{\circ }$

For $m\angle YXZ$ makes straight line with $m\angle WXY$ .

So,

  $\begin{array}{c}m\angle WXY\text{ + }m\angle YXZ={180}^{\circ }\left(\text{linear pair}\right)\\ {60}^{\circ }+m\angle YXZ={180}^{\circ }\\ m\angle YXZ={120}^{\circ }\end{array}$

b.

To determine

To find: The time when $m\angle WXY\text{ = }m\angle YXZ={90}^{\circ }$

Answer to Problem 33IP

6 o’clock and 15 seconds

Explanation of Solution

Given: $m\angle WXY\text{ = }m\angle YXZ={90}^{\circ }$

  $m\angle WXY\text{ = }m\angle YXZ={90}^{\circ }$

So, clock look like as shown below.

  

According to clock, time is 6 o’clock and 15 seconds.

c.

To determine

To find: The $m\angle WXY$ when it is 25 seconds after 6 0’clock.

Answer to Problem 33IP

  $m\angle WXY\approx {150}^{\circ }$

Explanation of Solution

Given: 6 o’clock and 25 seconds.

6 o’clock and 25 seconds

So, clock look like as shown below.

  

There are 5 consecutive number after 25 seconds.

So, $m\angle WXY\approx {150}^{\circ }$