Probability and Statistics for Engineering and the Sciences
9th Edition
ISBN: 9781305251809
Author: Jay L. Devore
Publisher: Cengage Learning
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Chapter 10.2, Problem 19E
To determine
Find a value for SSE, such that,
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Chapter 10 Solutions
Probability and Statistics for Engineering and the Sciences
Ch. 10.1 - In an experiment to compare the tensile strengths...Ch. 10.1 - Suppose that the compression-strength observations...Ch. 10.1 - The lumen output was determined for each of I = 3...Ch. 10.1 - It is common practice in many countries to destroy...Ch. 10.1 - Consider the following summary data on the modulus...Ch. 10.1 - The article Origin of Precambrian Iron Formations...Ch. 10.1 - An experiment was carried out to compare...Ch. 10.1 - A study of the properties of metal plate-connected...Ch. 10.1 - Six samples of each of four types of cereal grain...Ch. 10.1 - In single-factor ANOVA with I treatments and J...
Ch. 10.2 - An experiment to compare the spreading rates of...Ch. 10.2 - In Exercise 11, suppose x3. = 427.5. Now which...Ch. 10.2 - Prob. 13ECh. 10.2 - Use Tukeys procedure on the data in Example 10.3...Ch. 10.2 - Exercise 10.7 described an experiment in which 26...Ch. 10.2 - Reconsider the axial stiffness data given in...Ch. 10.2 - Prob. 17ECh. 10.2 - Consider the accompanying data on plant growth...Ch. 10.2 - Prob. 19ECh. 10.2 - Refer to Exercise 19 and suppose x1 = 10, x2 = 15,...Ch. 10.2 - The article The Effect of Enzyme Inducing Agents...Ch. 10.3 - The following data refers to yield of tomatoes...Ch. 10.3 - Apply the modified Tukeys method to the data in...Ch. 10.3 - The accompanying summary data on skeletal-muscle...Ch. 10.3 - Lipids provide much of the dietary energy in the...Ch. 10.3 - Samples of six different brands of diet/imitation...Ch. 10.3 - Although tea is the worlds most widely consumed...Ch. 10.3 - For a single-factor ANOVA with sample sizes Ji(i =...Ch. 10.3 - When sample sizes are equal (Ji = J). the...Ch. 10.3 - Reconsider Example 10.8 involving an investigation...Ch. 10.3 - When sample sizes are not equal, the non...Ch. 10.3 - In an experiment to compare the quality of four...Ch. 10.3 - Prob. 33ECh. 10.3 - Simplify E(MSTr) for the random effects model when...Ch. 10 - An experiment was carried out to compare flow...Ch. 10 - Cortisol is a hormone that plays an important role...Ch. 10 - Numerous factors contribute to the smooth running...Ch. 10 - An article in the British scientific journal...Ch. 10 - Prob. 39SECh. 10 - Prob. 40SECh. 10 - Prob. 41SECh. 10 - The critical flicker frequency (cff) is the...Ch. 10 - Prob. 43SECh. 10 - Four types of mortarsordinary cement mortar (OCM)....Ch. 10 - Prob. 45SECh. 10 - Prob. 46SE
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- A researcher conducted a t-test for independent samples to evaluate the mean difference between two treatment conditions and obtained t(48) = 4.00. What would be the computed F, if the outcomes of this study were evaluated by one-actor ANOVA for independent samples?arrow_forwardA study was conducted to determine whether there is a significant difference in the population mean for two groups with a sample size of n = 10 for each group. The results from the Wilcoxon Signed-Ranks Test resulted in a T-value of 15 and a p-value of 0.03. What conclusion can we make about the population means of the two groups?arrow_forwardSuppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . After the calculations performed, it is possible to mark the alternative as correct: a) Test t = -1.25; the calculated degree of freedom v= 8.06; p-value = 0.03; therefore we reject H0 for the 0.05 significance level. b) Test t = 2.15; the calculated degree of freedom v= 9; p-value = 0.13; therefore we accept H0 for the 0.01 significance level. c) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we accept H0 for the 0.01 significance level. d) Test t = -1.20; the calculated degree of freedom v= 9.96; p-value = 0.130; therefore we reject H0 for the 0.01 significance level. e) Test t = -1.25; the calculated…arrow_forward
- A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x1 be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x2 be the empathy score of a father. A random sample of 30 mothers gave a sample mean of x, = 67.85. Another random sample of 25 fathers gave x2 = 61.72. Assume that o, = 10.85 and oz = 10.57. (a) Let µ̟ be the population mean of x, and let uz be the population mean of x2. Find a 90% confidence interval for H1 - H2. (Use 2 decimal places.) lower limit upper limitarrow_forwardSuppose μ1 and μ2 are real average stopping distances at 50 mph of a certain type of car equipped with two different types of braking systems. Use the two-sample t test at the 0.01 significance level to test H0: (μ1 - μ2 = -10) vs. Ha: (μ1 - μ2 < -10) for the following data: m = 6 ; x̄ = 115,7 ; s1 = 5,03 ; n = 6 ; ȳ = 129,3 and s2 = 5,38 . Using the above data and calculating a 95% CI for the difference between the actual average stopping distance of cars equipped with brake system 1 and cars with brake system 2. The calculated range suggests that accurate information about the value of this difference is available? From this information, it is possible to mark the alternative as correct: a) The calculated range is (-13.50, -11.80). With this range, even with values so close, it is not possible to say that precise information is available. b) The calculated range is (-20.40, -6.80). With this interval, even being so wide, it is possible to affirm that accurate information is…arrow_forwardPSOHS had administered an IQ level test to 15 randomly selected G11 students. And the result they found from that was the average IQ level score was 110 with a variance of 35. Assume that the t score is 2.365. What is the population mean for this test, which would justify t score value as 2.365.arrow_forward
- A study of parental empathy for sensitivity cues and baby temperament (higher scores mean more empathy) was performed. Let x1 be a random variable that represents the score of a mother on an empathy test (as regards her baby). Let x2 be the empathy score of a father. A random sample of 33 mothers gave a sample mean of x, = 67.51. Another random sample of 33 fathers gave x2 = 59.51. Assume that o, = 11.69 and oz = 11.55. (a) Let u, be the population mean of x, and let uz be the population mean of x2. Find a 99% confidence interval for u - H2. (Use 2 decimal places.) lower limit upper limitarrow_forwardThe road octane numbers of two different formulations of gasoline are being studied. A random sample of size n, = 15 is taken for formulation 1; while, for formulation 2, the random sample size is na = 20. The variance of the octane number for formulation 1 is a, 2 =1 5, and for formulation 2, it is a,2 =1 2. The mean octane numbers observed are x, = 89.6 and x, = 92.5. Assume normality. What is the upper limit of a 95% two- sided confidence interval on the difference in mean octane number (u, - H)?arrow_forwardTwo brands of tyres are tested with the following results: Life(in’000 miles) Brand of TyresX Y20-25 1 025-30 22 2430-35 64 7635-40 10 040-45 3 0 a. Which brand of tyres have greater average life?b. Compare the variability and state which brand of tyres would you use on yourfleet of trucks?arrow_forward
- The recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 111, x = 12.4, and s = 6.69. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? > 15H0: ? = 15Ha: ? < 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? ≠ 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject the null…arrow_forwardThe recommended daily dietary allowance for zinc among males older than age 50 years is 15 mg/day. An article reports the following summary data on intake for a sample of males age 65−74 years: n = 116, x = 12.5, and s = 6.35. Does this data indicate that average daily zinc intake in the population of all males age 65−74 falls below the recommended allowance? (Use ? = 0.05.)State the appropriate null and alternative hypotheses. H0: ? = 15Ha: ? ≠ 15H0: ? = 15Ha: ? > 15 H0: ? = 15Ha: ? ≤ 15H0: ? = 15Ha: ? < 15 Calculate the test statistic and determine the P-value. (Round your test statistic to two decimal places and your P-value to four decimal places.) z = P-value = State the conclusion in the problem context. Do not reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day.Reject the null hypothesis. There is not sufficient evidence that average daily zinc intake falls below 15 mg/day. Do not reject…arrow_forwardLet Y₁, Y2, ..., Yn be a random sample from a population with a Gamma distribution with parameters a = 3 and unknown. Find the Minimum Variance Unbiased Estimator for B. Show your work, and explain how you know your estimator is the MVUE.arrow_forward
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