Write a function called chop_list that takes a list, modifies it by removing the first and last elements, and return a list.
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Types of Linked List
A sequence of data elements connected through links is called a linked list (LL). The elements of a linked list are nodes containing data and a reference to the next node in the list. In a linked list, the elements are stored in a non-contiguous manner and the linear order in maintained by means of a pointer associated with each node in the list which is used to point to the subsequent node in the list.
Linked List
When a set of items is organized sequentially, it is termed as list. Linked list is a list whose order is given by links from one item to the next. It contains a link to the structure containing the next item so we can say that it is a completely different way to represent a list. In linked list, each structure of the list is known as node and it consists of two fields (one for containing the item and other one is for containing the next item address).
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- two_sum is a Python function that takes in a list of integers (elements) and an integer number (num) and returns True if there exist two values in elements that add up to num, otherwise, function returns False. def two_sum(elements: List[int], num: int): for i in range(len(elements)): for j in range(i + 1): if elements[i] + elements[j] == num: return True return False Study above function and answer below questions: A. What is time complexity of two_sum? B. Is it possible to improve on above algorithm performance (in terms of its asymptotic cost)? If yes, describe your algorithm, be detailed as much as possible.JS Write a function named list_concat that has a single parameter. This parameter will be a list/array. The parameter's entries will be strings. Your function needs to return a string. The returned string's value should be the concatention of all of the entries in the parameter with a space after each entry. Sample test cases: list_concat(["single"]) evaluates to "single list_concat(["limit", "break", "ready"]) evaluates to "limit break readyIf you have the following node declaration:struct Node {int number;struct Node * next;};typedef struct Node node;node *head,*newNode;Write a C program that contains the following functions to manipulate this linked list : 3. A function deletes the element in the middle of the list (free this memory location) (if the list has 100 or 101 elements, it will delete the 50th element). The function will take a list as a parameter and return the updated list. 4. 2nd function named changeFirstAndLast that swaps the node at the end of the list and the node at the beginning of the list. The function will take a list as a parameter and return the updated list. 5. 3rd function using given prototype below. This function cuts the first node of the list and adds it to the end as last node. It takes beginning address of the list as a parameter and returns the updated list.node* cutheadaddlast(node* head);
- The mapped list pattern Our second pattern is the mapped list pattern, described in video 4 3 mapped list pattern. Often we need to write a function that takes a list as a parameter and returns a new list in which each item in the original list is "mapped" to a new item in the result list. For example, the following function takes a list of numbers as a parameter and returns a list of all the numbers squared, e.g. squares ( [1, 3, 7]) returns [1, 9, 49]. def squares (nums): "Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result Although this is just a special case of the accumulator pattern, it is so common that we give it its own name: the mapped list pattern. Consider the following function: def squares(nums): ""Returns the squares of the given numbers""" result = [] for num in nums: result.append (num * num) return result If the main program calls print(squares ( [5, -3, 2, 7]) what is the state table for the function…PYTHON CS1 PROBLEM Define a function that takes a list of lists, glol, as a parameter. You may assume that the inner lists in glol are lists of positive integers. Your function should return True if at least one of the inner lists in glol contains two or more multiples of 10. Otherwise it should return False. For example: If glol = [ ] then your function returns False. If glol = [[ ], [4, 2]] then your function returns False. If glol = [[10, 2, 6, 8], [12, 6], [15, 20, 5]] then your function returns False. If glol = [[10, 2, 6], [12, 6], [10, 2, 70, 15], [15, 10, 5]] then your function returns True as the inner list [10, 2, 70, 15] contains 10 and 70. If glol = [[10, 2, 6], [12, 6], [10, 7, 15], [50, 10, 50, 4, 6]] then your function returns True as the inner list [50, 10, 50, 4, 6] contains 50 twice. 6. If glol = [[10, 20, 6, 90], [12, 6], [ 7, 3, 15], [50, 10, 50, 4, 7]] then your function returns True as the inner lists [50, 10, 50, 4, 7] and [10, 20, 6, 90] contain more…struct Node { int data; Node * next; }; Node • head; a. Write a function named addNode that takes in a variable of type int and inserts it at the head of the list. b. Write a function named removeNode that removes a node at the head of the list.
- Code in python Given a list, L, the function front_two creates a new list of length 2 out of the first two items in L as follows: In the new list, the second item becomes the first item, and the first item becomes the second. If L contains only one item, the first item in the new list should be the value None. If L is empty, both items in the new list should be value None. The function returns the new list. For example: Test Result L = ['a', 'b', 'c', 'd'] print(front_two(L)) ['b', 'a'] L = [] print(front_two(L)) [None, None] L = [5, 2] print(front_two(L)) [2, 5] L = [7] print(front_two(L)) [None, 7]Write the code of the following functions: def fillX(pointsX,lowerLimit, upperLimit): This function receives a list pointsX and returns the same list with values between loverLimit and upperLimit. There are number of them.a- Write a Python function Salary_levels, that takes a list as an argument and returns the number of the high salaries (salary>=5000), the average salaries(1000<=salary<5000, and the low salaries (salary<1000). You can use the following list : salaries= [500,1070,1450,6500,9000,940,450,400,600,2750,1100,8400,1500,900,1200] b- Use the above function to print the counts of the high, average, and low salaries. N.B: the codes of parts a and b should be included in your answer.
- Write a C function list_pass () for the linked list. This function should list all student information which average is equal or greater than 50. Use the structure shown below as the node of the linked list struct student { int stdno: char name[25]; int midterm, quiz, final: float aver; struct student *nextPtr:Write a function in_list that will take as its parameters an input list called mylist and a number. If the number is in the list the function should retun true, ottherwise, it should retun false. def in_list(mylist,number):Using the ListNode structure introduced in this chapter, write a function void printFirst(ListNode *ptr)that prints the value stored in the first node of a list passed to it as parameter. The function should print an error message and terminate the program if the list passed to it is empty.