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- C UUU UUC Phe UUA UCU) UCC UCA UAU UAC Tyr UGU UGC Cys Ser UAA Stop UGA Stop A UAG Stop UGG Trp UUG FLeu UCG CUU CUC CCU] СС CAU1 CAC САC His САА Gln CGU CGC Arg Leu Pro CUA CUG ССА CGA CUG J CCGJ Which of the following tRNA anticodons could theoretically base pair effectively with the codons 5'-AAU-3' and 5'-AAC-3' through third-base CAG, CGG AGU AAUASN AGC AUU AUC File A AUA ACU АСС АСА AAC FAsn AAA Ser C Thr AGA Arg A AUG Met ACG AAG Lys AGG GCU] GCC GCA GCG GGU GGC Gly GGA GAU1 GUU GUC GUA GUG Asp GACJ GAA C Val Ala A GAG Glu GGG wobble? 5'-GGG-3' OI. 5'-AUG-3' II. 5'-GUU-3' I. 5'-CAT-3' IV. 5'-AAA-3 V. Third letter UCAG UUAG A, First letterClal - Bap 23 Hindill 29 Aatll- Iral 4284 B 4209 B 4205 Ecok 185 Spl 4168 Batl- Nel 229 Al 404 an 35 Sgrl 400 hanll 471 Scal 3844 Ball 485 378 Prul 3733- Kee 22 P 300 tr 3002 Sall - let-indl 651 P 712 At 3537 Bal 3433 Tag 09 hel Neel 92 T 3420 PBR322 4361 bp BePI 1045 Bep - a 103 PEMI 1315 PENE 1364 Sl 1360 Awal - 1425 u 1438 Msd 1444 t 14 Pyu 140 Aul 3000 Aa 2884 Bell 2777 rep ch 22 Dell 2575 Bag 1650 Bp 1664 Bal 16 Pal - M 2473 204 farl 2351 - Sapt 20 Ndet 226 2291 BI- Nd 2244/ Ba 2225 Xnel 2009 Pull 2064 Ben 2122 Dell 2162 Tih- PI 217 Figure 1 If your gene of interest was inserted at the Sphl restriction site of the plasmid illustrated in Figure 1, describe the screening process to select the positive recombinants.Second letter C UUU UGU UGC. UUC Phe UUA UUG UCU UCC UCA UCGJ UAU1 UAC. Ser UAA Stop UGA Stop A Tyr Leu UAG Stop UGG Trp CAUTHIS CACS CAA GIn CAG CGU CGC Arg CCU CUU CỤC CỦA CUG J CC Leu Pro ССА CGA CCGJ CGGJ AGU Ser ACU АСС ACA AUU AAU Asn AAC AAA AUC le AGA TArg Thr AUA AUG Met ACG AAGLYS AGG GAU GUU) GUC GUA GUG GCU) GCC GCA GACASP GAA AGlu GAGS GGU GGC Gly Val Ala GGA GGG GCGJ Given the following mRNA sequence: 5' GCCCAUGUGGCGCGAGUGAUUUAA 3' Third letter UCAC UCAG UCAG UCAG 등 | First letter
- Consider the mRNA sequence below. Assume that the following mRNA segment has been translated. 5'-UACCGAAUGUCU-3' Note for numbers 1 and 2: Use the three-letter abbreviation of amino acid; separate amino acids with a hyphen: do not include the stop codon. Example: ala-cys-glu 1. Using the table of the genetic code, determine the sequence of amino acids. 2. If mutation occurs by substitution of the 12th nucleotide with cytidine-5'- monophosphate, what is the resulting amino acid sequence? 3. What type of mutation occurred? Choose from same sense, missense and non-sense.Page 1: Second Letter C 1 2 UUU U UUC UUA Phe UCU UCC UCA UCG UAU UAC UAA UAG UGU Cys U UGC Stop UGA Stop UGG Tyr -- Ser Leu Stop A Trp G UUG CUU C CUC CCU Leu cc CAU His CGU Pro CAC CGC Arg CUA CUG CCA CCG 1st СА Gln CGA CAG CG 3rd letter AUU A AUC AUA AUG ACU ACC ACA AGU Ser AGC u letter AAU AAC AAA AAG Asn He Thr AGA AGG A Arg G Lys Met ACG GUU G GUC GUA GUG GCU GCC GAU Asp GGU GGC U Val GAC GAA GAG Ala Gly GCA GGA GGG Glu GCG 1. Convert the sequence from DNA to Amino Acids. 3-TCACCACTCTGGTCTGGTCATATCTGCCTGATATGAGTACAT - 5' a. direct transcript? b. transcript for translation? c. direction of a? (3' to 5' or 5' to 3') d. direction of a (3' to 5' or 5' to 3') e. translated peptides?ScX O 2020/ X Chapt O Pla + x ti Grades x - Micros x Attach x 2 Edpuz x (1) Dia x A quizizz.com/join/game/U2FsdGVkX19u5PV2q0828jgMm6BEgGF6fEPUbfvRFnusX%252BvbgoJX50wVADbL6X.. Johnson - Bo.. A Classes Course stream ti Planner - ProgressB. Holt McDougal Onli. G snake - Google Sear. O YouTube C 2KMTCentral | NBA A Actively Learn 1/7 Streak Whose research suggested that DNA was helical? Chargaff Watson Crick Franklin
- Second letter UUU UUC UUA UUG. UCU UCC UCA UCG UAU Tyr UAC. Ser UAA Skp UGIA Stop UGU UGC. Phe Cys Leu UAG Sop UGG Trp CGU CGC Arg CGA CCU CAU CUU CUC CUA CUG His CAC CAA CAG Gin CCC Pro CCA Leu CCG CGG ACU AAUA AGU ]Ser AUU Asn AAC AGC AGA LArg AGG. AUC Be ACC ACA Thr AAA AUA AUG Met ACG MGys GUU GUC Val GUA GCU GCC GCA GCG Ala GAA Glu GAG GAU GAC Asp GGU GGC Gly GGA GGG GUG You come across four polynucleotide strands. The first is an original RNA strand that codes for a protein; the others are similar to the original RNA strand, except that each displays a point mutation. The point mutations are shown in red. 5' - AUG-UGC-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGA-AUU-CCU-GCA-UAA - 3' 5' - AUG-UGC-AUU-CCC-GCA-UAA - 3' 5' - AUG-UGC-GUU-CCU-GCA-UAA - 3' Original RNA: Mutant RNA 1: Mutant RNA 2: Mutant RNA 3: 1. Based on how they will affect the protein product, identify the type of point mutation (missense, nonsense, silent, or frameshift) present in the Mutants 1, 2, and 3. 2. State which of…First base U A G U UUU UUC UUA UUG CUU CUC CUA CUG Phe GUU GUC GUA GUG Leu Leu AUU AUC lle AUA AUG Met or start Val Second base C A UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Ser Pro Thr Ala UAU UGU Tyr Cys UAC UGC UAA Stop UGA Stop A UAG Stop UGG Trp CAU CAC CAA CAG AAU AAC AAA AAG GAU GAC GAA GAG His Gin Asn Lys Asp G Glu CGU CGC CGA CGG AGU AGC AGA AGG GGU GGC GGA GGG Arg Ser Arg Gly UCAG UCAG ט כ с AG А U ט כ C G Third base A mutation in the DNA that codes for hemoglobin changes the sequence CTC to CAC. This will cause a change in the mRNA from (original) ? to (mutated) __?____, resulting in the addition of the amino acid, (mutated) ____?___, instead of (original) ____?_position position (5' end) position (3' end) UUU Phe - F UUC Phe UAU Tyr Y. UAC Tyr UAA Stop UGU Cys UGC Cys UGA Stop UGG Trp UCU Ser UCC Ser U UUA Leu UUG Leu UCA Ser UCG Ser UAG Stop W 輔 CAU His CGU Arg CGC Arg CGA Arg CGG Arg CUU Leu CCU Pro CUC Leu CCC Pro P. CCA Pro CÁC His CỦA Leu CAA Gln CUG Leu CCG Pro CAG GIn AUU lle ACU Thr AAU Asn AGU Ser AUC lle ACC Thr -T ACA Thr AAC Asn_ AGC Ser AGA Arg AGG Arg A AUA lle AAA Lys EK AAG Lys AUG Met ACG Thr GUU Val GGU Gly GGC Gly GGA Gly GGG Gly GAU Asp D GAC Asp GCU Ala GUC Val -V GUA Val GCC Ala GCA Ala GCG Ala G - A GAA Glu FE GAG Glu GUG Val Nonpolar Polar Basic Acidic Stop codon Table 4.1 Biology: How Life Works, Third Edition © 2019 W. H. Freeman and Company Consider the DNA sequence–3'-CACTGGTAGCGA–5', • What is the sequence of the messenger RNA sequence that is transcribed from this DNA sequence? (Indicate the 5' and 3' ends of the RNA molecule.) • Consult the genetic code that is shown above. What is the amino acid sequence of the…
- Second letter UGU UGCCYS UCU UAU UAC Tyr UAA Stop UGA Stop A UAG Stop UGG Trp UUU Phe UUC. UCC Ser UCA UUA Leu UUG S UCG CAU CUU CUC Leu CỦA CGU CCU CC ССА CCG His CAC CGC Pro Arg CAA CGA Gln CUG CAG CGG AGU AGC AGA AAU ACU ACC ACA AUU Ser AUC File A AUA Asn AAC. AAA AAG Thr Lys AUG Met ACG AGG Arg GCU GCC GCA GCG GGU) GGC Gly GUU GUC Val G GUA GAU) Asp GAC Ala GAA Glu GAGJ GGA GUG GGG A mutation takes place during replication and the new DNA strand has the sequence 3'-ATG-5'. What is the codon on an RNA strand transcribed from this series of nucleotides? Which amino acid results from this codon? Use the genetic code to answer this question. Edit View Insert Format Tools Table 12pt Paragraph Av ev T? MacBook Pro 20 00 000 23 $ % & 7 First letter Third letter * OC 全Design Layout References Mailings words ● ● Endocrine System Part 2 Lecture-OBJECTIVES FOR PRE-LECTURE QUIZ #2 ● 1. Recognize the following types of biomolecules when given images such as the ones below and on the next page: ● glucose (which is a monosaccharide) ● triglycerides ● Review phospholipids DNA ● RNA view • X English (United States) Add Pen OFF Draw with Trackpad polysaccharide amino acid protein (recall a protein with less than 50 amino acids can also be called a peptide whereas a protein with 50 or more amino acids can also called a polypeptide) steroids DNA MacBook Air I Focus Page 2 of 10 ERPAYS- DASO บบบ 1 UUC UUA UUG CUU CUC CUA CUG U '} GUU GUC GUA GUG PHE LEU AUU AUC AUA AUG MET or START LEU ILE VAL UCU UCC UCA UCG CCU CCC CCA CCG ACU ACC ACA ACG GCU GCC GCA GCG Second base SER PRO THR ALA UAC} TYR UAA UAG } STOP CAU CAC CAA CAG} AAU AAC AAA AAG J HIS GLN ASN LYS GAU ASP GAC GAG GLU UGU CYS UGC UGA} STOP UGG TRP CGU CGC CGA CGG AGU AGC AGA AGG G GGU GGC GGA GGG ARG SER ARG GLY SCAR SCAG А