Rigid bar ABCD is loaded and supported as shown. Steel [E = 28600 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.67 in.² and bar (2) has a cross-sectional area of 0.32 in.2. After load P is applied, the strain in bar (1) is found to be 810 μe. Assume L₁-51 in., L₂=78 in., a-31 in., b-29 in., and c-37 in. Determine: (a) the stresses in bars (1) and (2). (b) the vertical deflection vp of point D on the rigid bar. (c) the load P. (1) L2 ksi. Answers: (a) σ₁ (b) VD= (c) P = i LA a S b N ksi, 0₂ = in. kips.

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter2: Axially Loaded Members
Section: Chapter Questions
Problem 2.5.23P: Wires B and C are attached to a support at the left-hand end and to a pin-supported rigid bar at the...
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Rigid bar ABCD is loaded and supported as shown. Steel [E = 28600 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar
(1) has a cross-sectional area of 0.67 in.² and bar (2) has a cross-sectional area of 0.32 in.2. After load P is applied, the strain in bar (1) is
found to be 810 μe. Assume L₁-51 in., L₂=78 in., a-31 in., b-29 in., and c-37 in. Determine:
(a) the stresses in bars (1) and (2).
(b) the vertical deflection vp of point D on the rigid bar.
(c) the load P.
(2)
(1)
L₁
B
Answers:
(a) o₁ =
(b) VD=
(c) P= i
i
i
L2
b
ksi, 0₂
in.
kips.
с
=
Mi
D
ksi.
Transcribed Image Text:Rigid bar ABCD is loaded and supported as shown. Steel [E = 28600 ksi] bars (1) and (2) are unstressed before the load P is applied. Bar (1) has a cross-sectional area of 0.67 in.² and bar (2) has a cross-sectional area of 0.32 in.2. After load P is applied, the strain in bar (1) is found to be 810 μe. Assume L₁-51 in., L₂=78 in., a-31 in., b-29 in., and c-37 in. Determine: (a) the stresses in bars (1) and (2). (b) the vertical deflection vp of point D on the rigid bar. (c) the load P. (2) (1) L₁ B Answers: (a) o₁ = (b) VD= (c) P= i i i L2 b ksi, 0₂ in. kips. с = Mi D ksi.
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