Reverse a singly linked list by changing the pointers of the nodes. The data represented by the list should continue to remain in the same nodes of the original list. For example, given a singly linked list START, as shown in Figure P6.9(a), the list needs to be reversed, as shown in Figure P6.9(b), by manipulating the links alone. START a₁ a3 ·¶¯Ð·ÒÅÐ-üh с (a) Original singly linked with a; indicating address of node A START az as E B a4 a4 a; ¨¯ÒÐÒÛR. с (b) Reversed singly linked list Figure P6.9. Reversing a singly linked list by manipulating links D as a₂ E a₁ A
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- Reverse a singly linked list by changing the pointers of the nodes. The data represented by the list should continue to remain in the same nodes of the original list. For example, given a singly linked list START, as shown in Figure P6.9(a), the list needs to be reversed, as shown in Figure P6.9(b), by manipulating the links alone. START as 中中中中中 咁 (a) Original singly linked with a; indicating address of node START as E D 3 C a2 TH A (b) Reversed singly linked list Figure P6.9. Reversing a singly linked list by manipulating linksImplement a program using Doubly LinkedList. Your doubly linked list should store information of students (Reg_no., Name, CGPA, city, age). Your program should provide following functionalities: Insert at Front Insert at Rear Insert in middle Delete from front Delete from rear Delete from middle Display all the data Data Structures in C++ Needed urgent i will thumb up for youImplement the function below void swap(int pos1, int pos2) {} For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. Inital code to be completed: class LinkedList : public List { node* head; node* tail; int index; node* create_node(int num) { node* n = (node*) malloc(sizeof(node)); n->element = num; n->next = NULL; return n; } public: LinkedList() { index = 0; head = NULL; tail = NULL; } int add(int num) { addTail(num); return index; } int get(int pos) { node* currnode = head; int count =0; while (currnode != NULL){ count++; if (count == pos){ return currnode -> element; }else{ currnode = currnode -> next; } }…
- Given pointers to the head nodes of linked lists that merge together at some point, find the node where the two lists merge. The merge point is where both lists point to the same node, i.e. they reference the same memory location. It is guaranteed that the two head nodes will be different, and neither will be NULL. If the lists share a common node, return that node's value. Note: After the merge point, both lists will share the same node pointers. Example In the diagram below, the two lists converge at Node x: [List #1] a--->b--->c \ x--->y--->z--->NULL / [List #2] p--->q Function Description Complete the findMergeNode function in the editor below. findMergeNode has the following parameters: SinglyLinkedListNode pointer head1: a reference to the head of the first list SinglyLinkedListNode pointer head2: a reference to the head of the second list Returns int: the value of the node where the lists merge Input Format Do not read any input from…using c++ concepts of data structure Make a doubly linked list, take n inputs. Print it.Now, swap any two nodes (picked by the user), and print the list again. The node will be pickedon the basis of their value.Note: You have to swap the Node, by managing the links between them. NOT JUST THEVALUE INSDE THEM.In C++, Consider a singly linked list where each node contains two fields – integer dataand node type pointer next. The head pointer of the list, a position, and a valueof data is given. You have to insert a node with the given value at the givenposition. You have to consider any position including first or last. You have toImplement an insert operation as per the above specification.
- Assume that the node of a linked list is in the usual info-link form with the info of the type of int. The following data, as described in parts (a) to (d), is to be inserted into an initially linked list: 72, 43, 8, 12. Suppose that head is a pointer of type nodeType. After the linked list is created, head should point to the first node of the list. Declare additional variables as you need them. Write the C++ code to create the linked list. After the linked list is created, write a code to print the list. What is the output of your code? Insert 72 into an empty linked list. Insert 43 before 72. Insert 8 at the end of the list. Insert 12 after 43Imagine we have a linked list as shown below. The ListNodehas two fields: num, an integer, and next, a pointer to the next node. The list is not sorted. Write the definition of a function that calculates and returns the sum of the numbers in the list.Assume that the node of a linked list is in the usual info-link form with the info of the type int. The following data, as described in parts (a) to (d), is to be insetred into an initially linked list: 72, 43, 8, 12. Suppose that head is a pointer of type nodeType. After the linked list is created, head should point to the first node of the list. Declare additional variables as you need them. Write the C++ code to create the linked list. After the linked list is created, write a code to print the list. What is the output of your code? a. Insert 72 into an empty linked list.b. Insert 43 before 72.c. Insert 8 at the end of the list.d. Insert 12 after 43.
- Reverse a singly linked list by changing the pointers of the nodes. The datarepresented by the list should continue to remain in the same nodes of the originallist.For example, given a singly linked list START, as shown in Figure P6.9(a), the listneeds to be reversed, as shown in Figure P6.9(b), by manipulating the links alone.09.Given a linked list of N nodes such that it may contain a loop. A loop here means that the last node of the link list is connected to the node at position X(1-based index). If the link list does not have any loop, X=0. Remove the loop from the linked list, if it is present, i.e. unlink the last node which is forming the loop. Example 1: Input: N = 3 value[] = {1,3,4} X = 2 Output: 1 Explanation: The link list looks like 1 -> 3 -> 4 ^ | |____|Suppose there are two singly linked lists both of which intersect at some point and become a single linked list. The head or start pointers of both the lists are known, but the intersecting node is unknown. Also, the number of nodes in each of the list before they intersect are unknown and both the list may have it different. List1 may have n nodes before it reaches intersection point and List2 might have m nodes before it reaches intersection point where m and n may be m = n, m > n or m < n. Give an algorithm for finding the merging point. Hints: A brute force approach would be to compare every pointer in one list with every pointer in another list. But in this case the complexity would be O(mn)