Q.30: For the ideal transformer circuit shown, when V=16cos3t Volt, find the average power delivered to (4Q) resistor? (Ans.: P4=18W) www 1:2 V, || ideal +.
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- FN.Q5 – A Transformer has primary windings as Np = 720 and secondary windings as Ns = 144. Its secondary voltage is Vs = 42V and output power of the transformer is PN= 2750W. The value of loses powers are Pcu = 52,5W and Pre = 39W. The resistance of loads are RLI = 1,660 and R12 = 1,950. (Pcu and PFE will be considered to be approximately the same in different load values.) Determine the following values in the circuit: Primary winding Secondary winding N, turns Ng turns Magnetic Flux, Primary current ISL Secondary 4 current Primary voltage ISL1 (ISL2 Secondary voltage RL1 R12 Transformer Core (a) the primary voltage VP, (b) the secondary load current Isı, if the transformer is rated at RLI and R12, (c) the primary load current IpL, (d) the load resistance R13 when the transformer is fully loaded by third in parallel, (e) efficiency n (fully loaded)Q2/3-phase.E.W.C. R using center tap transformer supplies highly inductive load, find: 1. The average load voltage with and without FWD and discusses these cases. 2-lf firing angle equal to 45°, the supply voltage is240v, transformer ratio is (2/1). Calculate the DC current& voltage of this case. 3- Draw all waveforms diagram. 4- what are the difference between the type of connection (Delta or Star).An RLC series circuit connected to a 110 – volt and 50 – cycle AC source, contains the following series resistances and reactances: R1 = 10 ohm, R2 = 15, R3 = 5 ohms, XL1 = 20 ohms, XL2 = 25 ohms, XC = 40 ohms. Find the following: a.) EQUIVALENT REACTANCE b.) TOTAL IMPEDANCE c.) VOLTAGE DROP ACROSS THE CAPACITOR d.) TOTAL INDUCTANCE IN MILLIHENRY e.) TOTAL CURRENT f.) REACTIVE POWER g.) REAL POWER DRAW THE PHASOR DIAGRAM IF POSSIBLE AND ROUND OFF TO FOUR DECIMAL PLACES
- Construct the circuit in Figure 1 in the Circuit JS simulator. Note that the voltage source is given in RMS. Within Circuit JS while defining the max voltage of the voltage source include “rms” after the number to tell Circuit JS that this is a rms value. Also note that there are additional parameters when instantiating a transformer in Circuit JS. Leave these at the default values. Additionally, transformers may have problems simulating in Circuit JS. Answer the following: 1. From the simulation results, determine the power dissipated in R2 and compare to the expected value from the previous section.2. Change the transformer ratio (“Ratio” as a fraction when you “Edit…” the transformer component) to the value calculated in the previous section to provide maximum power transfer in R2. Note: In Circuit JS, Transformer Ratio = Primary/Secondary.3. Rerun the simulation, calculate the power dissipated in R2 and compare to the expected value from the previous section.4. Change the…Vs=16cos100t Volt using T-equivalent circuit for For the circuit shown, find the steady-state 102 voltage "V" and the input power when 100 0.11I V=16cos100t Volt using T-equivalent circuit for transformer. 0.21I 0.211: 50 (Ans.: V=6cos100t Volt & Pin=11.2W)Efficiency at full-load and half the full-load at 0.8 p.f. lagging current. Equivalent reactance referred to primary & referred to secondary..........ohm , ..........ohm Equivalent resistance referred to primary & referred to secondary..........ohm , ..........ohm Regulation of transformer at 0.5 p.f. lagging current The magnetizing current and reactance component of no-load are.........amper , .........ohm The working current and resistance component of no-load are.........amper , .........ohm *
- Q-3 A Cockeroft-Walton type voltage multiplier has ten stages with capacitances, all equal to 0.1 µF. The supply transformer secondary voltage is 100 kV at a frequency of 60 Hz. If the load current to be supplied is 5 mA, find (a) the percentage ripple, (b) the regulation, and (c) the optimum number of stages for minimum regulation or voltage drop.Q5. A 20 kVA, 2000/200-V, 50-Hz transformer has a high voltage winding resistance of 0.2 2 and a leakage reactance of 0.240. The low voltage winding resistance is 0.05 and the leakage reactance is 0.02 2. Find the equivalent winding resistance, reactance and impedance referred to the (i) high voltage side and (ii) the low-voltage side. (Draw the related equivalent circuits)Q1. What is the principle of Buck-Boost type DC-DC converter? Derive the expression of voltage gain of it. A buck type converter is connected to a PV module, a 60 2 of load impedance and operated at a duty cycle of 45%. What would be the reflected impedance? If the PV module's voltage will be 26.8 Voltage. Find the current of it.
- Choose the supply voltage for a step down chopper circuit which drives the resistive load 4.80 with average load current 32.4A for a duty cycle of 0.4. O a. 2624.400 O b. 777.600 O c. 48.000 O d. 388.800DC 200 V was applied to the primary of a transformer with a conversion ratio of 1/5. Obtained from seconderexplain the reason for this by typing the voltage value to be?A 1,000/200 V transformer takes 0.3 at p.f. of 0.2 on open circuit. Find the magnetising, and iron loss component of no- load primary current.