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Part A Calculate the standard cell potential for each of the following electrochemical cells. Standard Electrode Potentials at 25 °C Reduction half-reaction E° (V) 2 Ag* (ag) + Pb(s) → 2 Ag(s) + Pb²+ (aq) Ag*(aq) +e →Ag(s) 0.80 Express your answer using two decimal places and include the appropriate units. РЬ (аg) + 2 е —РЫ(8) ClO2 (9) + e →CIO2 (ag) I2(8) + 2 e +2I (aq) Zn²+ (s) +2 e¯ →Zn(s) -0.13 0.95 ? 0.54 Eell = Value Units -0.76 O2(9) + 4 H† (aq) +2 e →2 H2O(1) 1.23 Submit Request Answer

Part A Calculate the standard cell potential for each of the following electrochemical cells. Standard Electrode Potentials at 25 °C Reduction half-reaction E° (V) 2 Ag* (ag) + Pb(s) → 2 Ag(s) + Pb²+ (aq) Ag*(aq) +e →Ag(s) 0.80 Express your answer using two decimal places and include the appropriate units. РЬ (аg) + 2 е —РЫ(8) ClO2 (9) + e →CIO2 (ag) I2(8) + 2 e +2I (aq) Zn²+ (s) +2 e¯ →Zn(s) -0.13 0.95 ? 0.54 Eell = Value Units -0.76 O2(9) + 4 H† (aq) +2 e →2 H2O(1) 1.23 Submit Request Answer

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter17: Electrochemistry And Its Applications
Section: Chapter Questions
Problem 38QRT
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Part A Calculate the standard cell potential for each of the following electrochemical cells. Standard Electrode Potentials at 25 °C E° (V) 2 Ag*(ag) + Pb(s) → 2 Ag(s) + Pb²+ (ag) Reduction half-reaction Ag+(aq) +e¯ →Ag(s) 0.80 Express your answer using two decimal places and include the appropriate units. Pb2+ (aq) + 2 e- →Pb(s) -0.13 ClO2(9) +e¯ →ClO2¯(aq) 0.95 HÀ ? I2(s) +2 e →2I-(aq) 0.54 Zn²+ + (s) +2 e¯ →Zn(s) E ell = Value Units -0.76 O2 (9) + 4 H† (ag) + 2 e¯ →2 H2O(1) 1.23 Submit Request Answer
Transcribed Image Text:Part A Calculate the standard cell potential for each of the following electrochemical cells. Standard Electrode Potentials at 25 °C E° (V) 2 Ag*(ag) + Pb(s) → 2 Ag(s) + Pb²+ (ag) Reduction half-reaction Ag+(aq) +e¯ →Ag(s) 0.80 Express your answer using two decimal places and include the appropriate units. Pb2+ (aq) + 2 e- →Pb(s) -0.13 ClO2(9) +e¯ →ClO2¯(aq) 0.95 HÀ ? I2(s) +2 e →2I-(aq) 0.54 Zn²+ + (s) +2 e¯ →Zn(s) E ell = Value Units -0.76 O2 (9) + 4 H† (ag) + 2 e¯ →2 H2O(1) 1.23 Submit Request Answer
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