Part 1= You are to discover the chromosomal location (autosomal or X linked) and mode of inheritance for two new fly mutations couchpotato (cp) and happyhour (hh) The homozygous couchpotato (cpcp) phenotype is (sedentary) an extreme lack of activity The homozygous happyhour (hhhh) can drink any other fly under the table so phenotype (drinker) PARENTS Cross Male double homozygous mutants cp hh with Female wild wild CP HH are to be crossed BUT FIRST you don’t know if either gene is on the X chromosome Parental diploid genotypes could be: male cpcphhhh female CPCPHHHH if Both genes autosomal or Male XcpYhhhh female XCPXCPHHHH if cp on the X chromosome and hh autosomal or Male cpcpXhhY female CPCPXHHXHH if hh on the X chromosome and cp autosomal What are the female and male PARENTAL GAMETE GENOTYPES for the above parental crosses if: a) Both genes were autosomal ((REMEMBER BOTH GENDER HAVE ONE GAMETE GENO) b) cp gene on the X chromosome and hh autosomal (REMEMBER MALES WITH HAVE 2 GAMETE GENO) c) hh gene on the X chromosome and cp autosomal (REMEMBER MALES WITH HAVE 2 GAMETE GENO) Draw the THREE different Punnett squares the Parental x Parental cross if: a) Both genes autosomal b) cp on the X chromosome and hh autosomal c) hh on the X chromosome and cp autosomal First part is done but need help with d-I

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter7: Development And Sex Determination

Section: Chapter Questions

Problem 18QP: Equalizing the Expression of X Chromosome Genes in Males and Females Males have only one X...

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Part 1= You are to discover the chromosomal location (autosomal or X linked) and mode of inheritance for two new fly mutations couchpotato (cp) and happyhour (hh) The homozygous couchpotato (cpcp) phenotype is (sedentary) an extreme lack of activity The homozygous happyhour (hhhh) can drink any other fly under the table so phenotype (drinker) PARENTS Cross Male double homozygous mutants cp hh with Female wild wild CP HH are to be crossed BUT FIRST you don’t know if either gene is on the X chromosome Parental diploid genotypes could be: male cpcphhhh female CPCPHHHH if Both genes autosomal or Male XcpYhhhh female XCPXCPHHHH if cp on the X chromosome and hh autosomal or Male cpcpXhhY female CPCPXHHXHH if hh on the X chromosome and cp autosomal What are the female and male PARENTAL GAMETE GENOTYPES for the above parental crosses if: a) Both genes were autosomal ((REMEMBER BOTH GENDER HAVE ONE GAMETE GENO) b) cp gene on the X chromosome and hh autosomal (REMEMBER MALES WITH HAVE 2 GAMETE GENO) c) hh gene on the X chromosome and cp autosomal (REMEMBER MALES WITH HAVE 2 GAMETE GENO) Draw the THREE different Punnett squares the Parental x Parental cross if: a) Both genes autosomal b) cp on the X chromosome and hh autosomal c) hh on the X chromosome and cp autosomal First part is done but need help with d-I

plola ģenotype for the above parental crosses if:
a) Both genes were autosomal
b) cp gene on the X chromosome and hh autosomal
c) bh gene on the X chromosome and cp autosomal
All resulting F1 flies are heterozygous BUT your lab partner euthanized the flies thinking you had
already gotten the phenotype. OKAY we can live without that F1 generation phenotype data.
What are the female and male GAMETES FROM F1 PARENTS haploid genotypes for crosses if:
d) Both genes autosomal
e) cp on the X chromosome and hh autosomal
f) bh on the X chromosome and cp autosomal
Draw the THREE different 4x4 Punnett squares the F1 x F1 backcross if:
g) Both genes autosomal

a) Brh gene are
aufosomay
Male Cepaphhhh) x Female (CPCPH HAH)
cphh
Clep HHhh
CPepH#hh
Clep HHhh
CPepHHhh
CPH H
CP H H
> ep gene on X' chromBome e nh artosomal
Male (x cp YWh hn) x female (xcP xCP #HFH)
Xephh
XCP Xip Hthh
XCP XepH Hhh| X CP y HHhh
XCPH H
XCP YHHhh
XCP HH
gene
on
'x' chromoseme
autosomend
Cos Merle ? cpep XhhY) x Female (cPCP x HH#XHH)
cpY
CPcp XH HY
CPc pXH HY
CPX HH
CPep x H HXhh
CPAH H
ClepXH H xhh

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