Normal leg size, characteristic of Kerry-type cattle, is produced by homozygous genotype DD. Short-legged Dexter-type cattle possess the heterozygous genotype Dd. The homozygous genotype dd is lethal producing grossly deformed stillbirths called “bulldog calves”. The presence of horns in cattle is governed by the recessive allele of another gene locus p, the polled condition (absence of horn) being produced by its dominant allele P. In matings between polled Dexter cattle genotype DdPp, a) what expected ratio is expected in the adult progeny? b) what percentage of the progeny will carry the lethal allele

Normal leg size, characteristic of Kerry-type cattle, is produced by homozygous genotype DD. Short-legged Dexter-type cattle possess the heterozygous genotype Dd. The homozygous genotype dd is lethal producing grossly deformed stillbirths called “bulldog calves”. The presence of horns in cattle is governed by the recessive allele of another gene locus p, the polled condition (absence of horn) being produced by its dominant allele P. In matings between polled Dexter cattle genotype DdPp, a) what expected ratio is expected in the adult progeny? b) what percentage of the progeny will carry the lethal allele

Name: Normal leg size, characteristic of Kerry-type cattle, is produced by h
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: Normal leg size, characteristic of Kerry-type cattle, is produced by homozygous genotype DD. Short-legged Dexter-type cattle possess the heterozygous genotype Dd. The homozygous genotype dd is lethal producing grossly deformed stillbirths called “bul

Human Biology (MindTap Course List)

11th Edition

ISBN:9781305112100

Author:Cecie Starr, Beverly McMillan

Publisher:Cecie Starr, Beverly McMillan

Chapter19: Introduction To Genetics

Section: Chapter Questions

Problem 9CT

See similar textbooks

Similar questions

In chickens, a dominant hereditary abnormality (e.g., creepers) causes death when the genotype is homozygous (CC). The recessive condition (cc) at this locus produces a normal phenotype. Another gene locus with co dominant alleles is known to govern feather color such that the genotype FF = black, ff = splashed white, and Ff = blue. Also, a completely dominant gene W produces white skin. Yellow skin is produced by the homozygous genotype ww. QUESTIONS: In CcFfWw x ccffWw, what proportion of the offspring is: b.2 normal, white feathered, white skinned b.3 yellow skinned
In Shorthorn cattle, coat color is controlled by a single gene thatcan exist as a red allele (R) or a white allele (r). The heterozygotes (Rr) have a color called roan that looks less red than theRR homozygotes. However, when examined carefully, the roanphenotype in cattle is actually due to a mixture of completelyred hairs and completely white hairs. Should this be calledincomplete dominance, codominance, or something else?Explain your reasoning
In humans, "unattached" earlobes are dominant over "attached" earlobes. "Widows peak" hairline is dominant over "non-widows peak" hairline. Use E and e for the earlobe phenotype alleles, and W and w for the hairline phenotype alleles. A female and a male, both with genotype EeWw have a child. What is the probability it will be a boy, and have attached earlobes and a widows peak hairline?
In mice, the presence of a dominant A allele results in the agouti pattern of fur color, whereas the aa homozygous recessive results in a solid color pattern. The presence of another dominant B allele results in black fur color, whereas the homozygous recessive bb results in brown fur color. The presence of a third dominant C allele is required for any color to be observed (brown or black), whereas the homozygous recessive cc results in lack of any color whatsoever (albino). What is the phenotype of a mouse with the following genotype? Aa bb cc albino Agouti color pattern and brown Solid color pattern and brown Agouti color pattern and black Solid color pattern and black
In mice, the wild-type coat color, agouti (AA) [left mouse], is dominant to solid-colored, black fur (aa) [middle mouse]. However, a separate gene (C) is necessary for pigment production. A mouse that is homozygous for a recessive c allele at this locus is unable to produce pigment and is albino [right mouse] regardless of the allele present at locus A. Thus, the following genotypes are listed with their associated phenotypes: ~ A/A; C/C or A/A; C/c or A/a; C/C or A/a; C/c ==> "agouti" ~ a/a; C/C or a/a; C/c ==> "black" ~ A/A; c/c or A/a; c/c or a/a; c/c or a/a; c/c ==> "albino" This is an example of recessive epistasis, in which the recessive c allele "stands upon" the possible genotypes for the A gene (A/A, A/a, or a/a). If two agouti mice with the A/a; C/c genotype are mated, what is the expected phenotypic ratio in their offspring? A.9 albino, 4 agouti, 3 black B. 9 agouti, 4 albino, 3 black C.9 black, 4 albino, 3 agouti D.9 agouti, 4 black, 3 albino
In aliens, the genes A, B, C, D and E are dominant to their respective alleles a, b, c, d and e: A = one eye a = two eyes B = pointed ears b = round ears C = red skin c = green skin D = two antennae d = three antennae E = square head e = triangular head An alien with genotype AA bb Cc dd Ee marries an alien with genotype Aa Bb Cc Dd Ee. If the genes segregate independently, what is the probability that they will have a child with one eye, pointed ears, red skin, three antennae and a triangular head? A. 9/512 B. 9/128 C. 27/1024 D. 3/64
Bronze coloured turkey is controlled by a dominant allele, B. Red coloured turkey is homozygous for a recessive allele bb. Dominant gene N produce normal feather and recessive genotype produce ‘hairy’ feather nn. In a cross between homozygous bronzed coloured turkey with ‘hairy’ feather and homozygous red coloured turkey with normal feather. What are the ratios of F2 progeny with Bbnn genotypes? (I want to check if what i'm doing is correct)
The white Leghorn breed of chickens is homozygous for the dominant allele C, which produces colored feathers. However, this breed is also homozygous for the dominant allele I of an independently assorting gene that inhibits coloration of the feathers. Consequently, Leghorn chickens have white feathers. The white Wyandotte breed of chickens has neither the allele for color nor the inhibitor of color; it is therefore genotypically cc ii. What are the F2 phenotypes and proportions expected from intercrossing the progeny of a white Leghorn hen and a white Wyandotte rooster?
Suppose a geneticist is using a three-point test cross to map three linked rabbit morphology and behavioral mutations called si, sf, and H. The gene si is associated with the silky fur phenotype, and sf is associated with the short-footed phenotype. Both si and sf are recessive mutations with respect to wild type. H is a dominant mutation that confers the hyper phenotype. The geneticist first crosses true-breeding hyper rabbits to true-breeding silky fur, short-footed rabbits. Next, the geneticist backcrosses the F₁ progeny to the silky fur, short-footed parents, and obtains the results reported in the table. Phenotype hyper silky fur, short-footed short-footed silky fur, hyper silky fur short-footed, hyper silky fur, short-footed, hyper wild type Place the genes in the correct order in the chromosome. LLIIN HEL H Number 815 807 175 169 4 5 27 29 Answer Bank si sf
In Labrador retriever dogs, two alleles (B and b) determine whether coat colour will be black (B)or brown (b). Black coat colour is dominant. A second pair of alleles, E and e, are on a separatechromosome from B and b. The homozygous recessive condition, ee, prevents the expressionof either allele B or b, and produces a dog with a yellow-coloured coat. Some examples ofgenotypes and phenotypes for Labrador retrievers are shown below.Genotype PhenotypeBBEe blackbbEe brownBbee yellow Two dogs, each with the genotype, BbEe, were crossed. What is the percentageprobability that their offspring will have yellow coat colour? (Record your answer as awhole number percentage)
In peaches fuzzy skin (F) is completely dominant to smooth, nectarine skin (f). The gland at the base of the leaves is controlled by a separate, unlinked locus. The gland in heterozygotes is round, while homozygotes with the Go allele have oval glands, and homozygotes with the the GN allele have no glands. A homozygous fuzzy, no-gland peach variety is bred to a smooth, oval-gland variety. The F1 offspring are interbred to produce the F2 generation. What fraction of the F2 offspring will be smooth with round glands? A) 3/16 B) 7/16 C) 4/16 D) 6/16 E) 9/16 F) 2/16 G) 12/16 H) 1/16
A recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.