j162 24 2 j40 요일 100 V/30 ( -jl N j4 2 =-Q 8 j102 3 j9 2 -j10 2= 10 Ω 32 82 QUESTION 3 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the -18 ohm capacitor. O 14V RMS O 8.5V RMS O 34V RMS O 23V RMS QUESTION 4 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor. O 2 8A RMS O 11.1A RMS O 850mA RMS O 6.3A RMS e

j162 24 2 j40 요일 100 V/30 ( -jl N j4 2 =-Q 8 j102 3 j9 2 -j10 2= 10 Ω 32 82 QUESTION 3 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the voltage across the -18 ohm capacitor. O 14V RMS O 8.5V RMS O 34V RMS O 23V RMS QUESTION 4 Using Figure 23-24 on page 688 of your textbook, calculate the magnitude of the current through the j9 ohm inductor. O 2 8A RMS O 11.1A RMS O 850mA RMS O 6.3A RMS e

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter7: Alternating Current, Power Distribution, And Voltage Systems

Section: Chapter Questions

Problem 7RQ

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