maximum efficiency condition of a transformer c
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- For a short-circuit test on a 2-winding transformer, with one winding shorted, can you apply the rated voltage on the other winding? (a) Yes (b) NoIn developing per-unit circuits of systems such as the one shown in Figure 3.10. when moving across a transformer, the voltage base is changed in proportion to the transformer voltage ratings. (a) True (b) FalseConsider an ideal transformer with N1=3000andN2=1000 turns. Let winding 1 be connected to a source whose voltage is e1(t)=100(1| t |)volts for 1t1ande1(t)=0 for | t |1 second. A2- farad capacitor is connected across winding 2. Sketch e1(t),e2(t),i1(t),andi2(t) versus time t.
- Q5/A single phase, 50-Hz transformer has 80 turns on the primary winding and 400 turns on the secondary winding. The net cross-sectional area of the core is 200 cm2. If the primary winding is connected to 240-V, 50-Hz supply, determine (a) the emf induced in the secondary winding, and (b) the maximum flux density in the core. ()A 50 Hz 1-phase transformer has a turn-ratio of 6. The resistances are 0.90 ohm and 0.03 ohm and the reactance’s 5 ohm and 0.13 Q for high voltage and low voltage respectively. Determine (a) the voltage to be applied to the high voltage side to obtain full load current of 200 A in the low voltage winding on short circuit (b) the p.f. on short circuit.Determine the regulation of a transformer in which thepercentage resistance drop is 1% and the percentagereactance drop is 5% when the power factor 0.8 leading.
- Q2/ Fill in the blanks: 1- The two windings of a transformer is linked. ***** 2- If a transformer primary is energized from a square wave voltage source, its output voltage will be.......... 3- The primary winding of a 220/6 V, 50 Hz transformer is energized from 110 V, 60 Hz supply. The secondary output voltage will be ...... V.7. The primary of a single-phase transformer takes 1 A at power factor of 0.4 when connected to a 240-V, 50-Hz supply and the secondary is on open circuit. The number of turns on the primary is twice that on the secondary. A load taking 50 A at a lagging power factor of 0.8 is now connected across the secondary. What is now the value of the primary current ? transformer.) (Neglect the voltage drops in the:The transformer Iron losses is .Constant independent of the applied voltage O .A linear function of the supplied voltageO .A second order function of the supplied voltageO
- 8- In core design of power transformer the number of steps increased as the eross-sectional area increased to Increase: a) The leakage inductance. b) The cooling oil paths. c) The flux density. 9- The percentage impedance drop is an effective character of the transformer because: a) It increases the efficiency. b) It reduces leakage reactance. c) It improves the regulation.391. A transformer has maximum efficiency at load copper loss (P.), is of full load. The ratio of its iron loss (P.) and fullFN.Q5 – A Transformer has primary windings as Np = 720 and secondary windings as Ns = 144. Its secondary voltage is Vs = 42V and output power of the transformer is PN= 2750W. The value of loses powers are Pcu = 52,5W and Pre = 39W. The resistance of loads are RLI = 1,660 and R12 = 1,950. (Pcu and PFE will be considered to be approximately the same in different load values.) Determine the following values in the circuit: Primary winding Secondary winding N, turns Ng turns Magnetic Flux, Primary current ISL Secondary 4 current Primary voltage ISL1 (ISL2 Secondary voltage RL1 R12 Transformer Core (a) the primary voltage VP, (b) the secondary load current Isı, if the transformer is rated at RLI and R12, (c) the primary load current IpL, (d) the load resistance R13 when the transformer is fully loaded by third in parallel, (e) efficiency n (fully loaded)