In a steam power plant, the condenser pressure is 10 kPa. The turbine and pump isentropic efficiencies are both 85 %. Draw the schematic and T-S diagrams. Label the points by setting point 1 at the condenser outlet, point 2 at the pump outlet, point 3 at the boiler outlet, and point 4 at the turbine outlet. Use the label 2a and 4a for the points due to the isentropic efficiency of the pump and turbine, respectively. Use 2 decimal places for the enthalpy and other energies in solving and for the final answers. For the steam quality (x) and entropy (s), use 4 decimal places in solving. For the specific volume, use 6 decimal places. The pressure and the temperature of steam that enters the turbine are 4.5 MPa and 800 oC Determine the following: (INPUT YOUR ANSWERS ON THE BLANK SPACES PROVIDED.) Enthalpy at point 1 in kJ/kg = Enthalpy at point 2 in kJ/kg = Enthalpy at point 3 in kJ/kg = Enthalpy at point 4 in kJ/kg = Actual Enthalpy at point 2a in kJ/kg = Actual Enthalpy at point 4a in kJ/kg = Actual Work of pump in kJ/kg = Actual Work of turbine in kJ/kg = Actual Heat added in kJ/kg = Actual Heat rejected in kJ/kg = Actual Net Work in kJ/kg = Actual Thermal Efficiency in % =
In a steam power plant, the condenser pressure is 10 kPa. The turbine and pump isentropic efficiencies are both 85 %. Draw the schematic and T-S diagrams. Label the points by setting point 1 at the condenser outlet, point 2 at the pump outlet, point 3 at the boiler outlet, and point 4 at the turbine outlet. Use the label 2a and 4a for the points due to the isentropic efficiency of the pump and turbine, respectively. Use 2 decimal places for the enthalpy and other energies in solving and for the final answers. For the steam quality (x) and entropy (s), use 4 decimal places in solving. For the specific volume, use 6 decimal places.
The pressure and the temperature of steam that enters the turbine are 4.5 MPa and 800 oC
Determine the following: (INPUT YOUR ANSWERS ON THE BLANK SPACES PROVIDED.)
Enthalpy at point 1 in kJ/kg =
Enthalpy at point 2 in kJ/kg =
Enthalpy at point 3 in kJ/kg =
Enthalpy at point 4 in kJ/kg =
Actual Enthalpy at point 2a in kJ/kg =
Actual Enthalpy at point 4a in kJ/kg =
Actual Work of pump in kJ/kg =
Actual Work of turbine in kJ/kg =
Actual Heat added in kJ/kg =
Actual Heat rejected in kJ/kg =
Actual Net Work in kJ/kg =
Actual Thermal Efficiency in % =
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