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- To generate large amounts of DNA to manufacture gene therapy payloads or to be able to see them on gel electrophoresis, specific sequences can be amplified by PCR. For a sequence of a 100 base pairs, calculate the number cycles of PCR required to generate 1 ng of DNA, when starting from a single copy. Note that the molar mass of an average DNA bp is 600 g/mol.The exponential nature of PCR allows spectacular increases in the abundanceof a DNA sequence being amplified. Consider a 10-kbp DNA sequence in agenome of 1010 base pairs. What fraction of the genome does this sequence represent? That is, what is the fractional abundance of this sequence in this genome?Calculate the fractional abundance of this target sequence after 10, 15, and 20 cycles of PCR, starting with DNA representing the whole genome and assuming that no other sequences in the genome undergo amplification in the process.The exponential nature of PCR allows spectacular increases in the abundance of a DNA sequence being amplified. Consider a 10-kbp DNA sequence in a genome of 1010 base pairs. What fraction of the genome is represented by this sequence; i.e., what is the fractional abundance of this sequence in this genome? Calculate the fractional abundance of this target sequence after 10, 15, and 20 cycles of PCR, starting with DNA representing the whole genome and assuming that no other sequences in the genome undergo amplification in the process.
- The final amount of each primer required in a PCR reaction is 25 picomol. If the total volume of the PCR reaction is equal to 100 µl and the stock concentration of each primer is equal to 0.0025 mM. Calculate the volume of stock primer that needs to be added in order to ensure a primer amount of 25 picomol.You are given a tube containing 275 ng of purified PCR product (DNA) that is 1262 bp long. How many picomoles of PCR product are in the tube? The average molecular weight of a deoxynucleotide monophosphate is 328 g/mol.Explain why a positive control and negative control are included in PCR experiments. Explain the three steps involved in each cycle of polymerase chain reaction.Why is loading dye added to the DNA sample for gel electrophoresis? Explain the function of the following components in a PCR reaction:− Primer, dNTP, MgCl, Taq polymerase, buffer.
- Our PCR samples already contain loading dye, but sometimes this isn’t the case. If your samples didn’t already contain dye and you wanted to load your PCR sample onto an agarose gel, you’d need to add loading dye to the proper concentration. There is a 6X loading dye available for use; how many µl of this loading dye will you add to 10 µl of your sample so that it is at a 1X working concentration? Show your work.PCR primers Below is a 300 base pair fragment of DNA. The top strand is written in the 5' to 3' direction. The bottom strand is written 3' to 5'. There are also two primer sequences; both primers are written 5' to 3'. Note that we are displaying a double-stranded DNA fragment, but primers will only bind to one of the two displayed strands. 5' ACCGȚAGCTATATGCTATCGTGACGTATCGGCGCATTAAȚCGGGATCGAT 3 50 3' TGGCÁTCGATATACOATAGCACTOCATAGCCGCGTAATTÀGCCCTAGCTÀ 5' 5' AGCTÇGCTAGCAGGAGAGAȚATCGÇTCATAGCTCCGATCGATGCCGCTAA 3 3' TCGAGCG ATCGTCCTCTCTÁTAGCGAGTATCGAGÓCTAGCTACGGCGATİ 5' 100 5' TATAGCTCTÇTGCGGATATÇGCATATACCẠ AGGCCCTACGTATGTAGCTA 3 150 3' ATATČGAGAGACOCCTATAGCGTATATGGTTCCGGGATGČATACATCGAŤ 5' 5 TGCGTATATÇGGAGAGTCCTGGATATGGAGCTTGACTGCAGAGAGCTCGA 3 200 3' ACGCÁTATAGCCTCICAGGÁCCTATACCTCGAACTGACGTCTCTCGAGCT 5' 5' TATGCGCTTAGGCCGTATATGCTTGGGGAAAGCTCTATGTATGCTATGTG 3 3. ATACGCGAATCCGGCATATACGAACCCCTÍTCGAGATACATACGATACAC 5' 250 5' TGCATGTGCTATGCAACGTTCOGATTGCGȚAGCAGTAATAGCGCCGATTG 3 300 3'…Calculate the volume (in µL) of DNA template required to add 60.0 ng to a 40.0 µL PCR if the DNA template is at a concentration of 28.0 ng µL-1.
- To be able to properly analyze a sample of DNA, you need to have at least 1 µg of the DNA of interest. Assumptions: PCR is run with 30 cycles; Molecular weight per nucleotide in DNA is about 660 g/bp (330 g/bp for single stranded DNA or RNA); bp = base pair. a. Given that you can use the Polymerase Chain Reaction (PCR) to amplify DNA from the original sample and the size of the fragment to be amplified is 10,000 nucleotides long, estimate how many DNA molecules you need to obtain the minimum amount required to analyze the sample. b. Suggest a way to increase your sensitivity, i.e. amplify the DNA starting from even fewer molecules of template DNA.Why is the company Qiagen has more refined DNA extraction steps than a normal Strawberry DNA extraction practical? Summary of Qiagen DNA extraction steps Add ATL buffer and grind with sample. Add 20 microliters of enzyme Proteinase K to degrade protein into a 1.5-2ml microcentrifuge tube. Add 200 microlitres AL lysis buffer, and mix by vortexing for 5–10 seconds, which breaks cell membrane allowing DNA to be released. Incubate the sample at 56 degrees for 10 minutes. Mix the cell lysate with 200 microlitres ethanol by pipetting it at the side of the microcentrifuge wall so DNA precipitates. The DNA forms a white layer and the remaining liquid is discarded. Pipet the mixture into DNeasy Mini spin column placed in a 2 ml collection tube. Centrifuge for a minute at 8000 rpm. Place the mini spin column into a 2 ml collection tube, add 500 µl Buffer AW1, and centrifuge for 1 min at 8000 rpm. Then add it to a new 2 ml collection tube (provided), add 500 µl Buffer AW1, and centrifuge for 1…You Purified plasmid DNA (a 6.0 kb vector) and got the following results... DNA conc: 200 ng/µL A260/280: 1.97 A260/230: 2.15 How would you to set up a ligation reaction with 50 ng of digested DNA and a 1254 base pair PCR insert present at a concentration of 23 ng/µL. How should you pipet the necessary nucleotide components (vector and PCR insert) to obtain a 1:5 vector to insert molar ratio? Keep in mind limitations of pipets when giving your answer.(e.g. Pipetes won't go below 0.5µL)
