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Can you tell me if I am doing this correctly? For the thermoeter correction, we are given that: literature value of standard - experimental value of standard at end of melting temperature.
I found online that the melting range of pure acetanilide is 113-115. From there I calculated the therometer correction.
Substance
|
Melting Point Range Begins/Ends (oC) |
Interval of Melting (oC) |
Thermometer Correction for Calibration Data (oC) |
Corrected Melting Point (oC) |
Crystallized acetanilide Trial #1
|
111.9 – 112.9 |
1.0 |
2.1 |
|
Crystallized acetanilide Trial #2
|
111.0 – 112.3 |
1.3 |
2.7 |
|
Crude acetanilide
|
112.9-115.4 |
2.5 |
-0.4 |
|
Acetanilide standard Lot #
|
115.6-116.5 |
0.9 |
-1.5 |
N/A |
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- What does the %RSD, listed in the spectral data, as well as the correlation coefficient of your standard curve, tell you about the quality of the data and integrity of the results? my standard % RSD is 36.4%, I had to calculate manually from the 5 standard solutions I did have on the spectra. The R squared value from the standard curve is 0.7282With the following information for a GC analysis using an internal standard, calculate the percentage of alcohol in the sample. The 1% ethanol standard sample has an ethanol peak area of 711 and a 1-propanol peak area of 9253; 3% is 3536 and 14432 for ethanol and 1-propanol respectively; 5% is 3506 and 10693; 7% is 5874 and 10847 and 9% is 5203 and 7522. The beer sample has an ethanol peak area of 5471 and 1-propanol of 14384. 4.95% 5.15% 5.05% 5.25%. Nitrite is commonly determined by a colorimetric procedure using a reaction called the Griess reaction. In this reaction, the sample containing nitrite is reacted with sulfanilimide and -(1-Napthyl)ethylenediamine to form a colored species that absorbs at 550 nm. Using an automated flow analysis instrument, the following results were obtained for standard solutions of nitrite and for a sample containing an unknown amount: Solution Absorbance at 550 nm 2.00 0.065 6.00 0.205 10.00 0.338 14.00 0.474 18.00 0.598 Unknown 0.402
- Nitrite is commonly determined by a colorimetric procedure using a reaction called the Griess reaction. In this reaction, the sample containing nitrite is reacted with sulfanilimide and -(1-Napthyl)ethylenediamine to form a colored species that absorbs at 550 nm. Using an automated flow analysis instrument, the following results were obtained for standard solutions of nitrite and for a sample containing an unknown amount: Solution Absorbance at 550 nm 2.00 0.065 6.00 0.205 10.00 0.338 14.00 0.474 18.00 0.598 Unknown 0.402 (Use a spreadsheet to complete this question.) a. Find the slope, intercept, and standard deviation of the calibration curve. b. Determine the concentration of nitrite in the sample.A student prepared a cereal sample solution using a procedure similar to that in Lab 5. The original sample solution was diluted by a factor of two, and then the absorbance of the diluted sample solution was measured and recorded as (2.0x10^-1). Use the following calibration plot and the dilution factor to determine the concentration of iron, in unit of M, in the original cereal sample solution. The trendline (linear regression) as displayed on the plot is y = 11898x - 0.0112.You have carried out an experiment using the spectrophotometry concept. A solutioncontaining compound X is mixed with reagent 1 and then reagent 2. This mixture produces ablue colour whose absorbance (A) could be read at 550 nm. The results are shown below If the standard solution (compound X) used have a concentration of 1 mM: 5. What is the reason for using test tube no. 1 in the table above? Can it be replaced withdistilled water?
- A compound X is to be determined by UV-visible spectrophotometry. A calibration curve is constructed from standard solutions of X with the following results: 0.50 ppm, A = 0.24; 1.5 ppm, A = 0.36; 2.5 ppm, A = 0.44; 3.5 ppm, A = 0.59; 4.5 ppm, A = 0.70. A solution of unknown X concentration had an absorbance of A = 0.50. Find the slope and in te rcept of the calibration curve, the standard error in Y, the concentration of the solution of unknown X concentrat ion, and the standard deviation in the concentration of X. Construct a plot of the calibration curve and determine the unknown concentra tion by hand from the plot. Compare it to that obtained from the regression line.One method for the quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is area normalization. Here, complete elution of all the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction involves dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2 and 30.2, in order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78 and 0.88, respectively.PS. Further values required for the solvings are give in the various situations below. (ANSWER) Situation: A community in a mountainous area of Bohol uses water collected from a nearby natural spring. A sample was submitted to a laboratory for the analysis of its total hardness. Required: SHOW YOUR COMPLETE CALCULATIONS. BASED ON THE IMAGE PROVIDED BELOW FOR THIS QUESTION: Calculate the amount of titrant used in each trial to reach endpoint. Report total hardness of the sample as mean ±sd. a. 250.0 mL of 500.0 ppm of CaCO3 solution from a primary standard (assume solvent is distilled water only). Answer : Mass of CaCO3 = 0.125 g b, The EDTA solution was standardized by titrating it with a 25.0 mL aliquot of the CaCO3 solution. How much of the titrant was consumed. Answer: Volume of EDTA consumed = 12.405 g c. Calculate the average titer (mg CaCO3/mL EDTA). Mass of CaCO3 in 25 mL CaCO3 solution: 0.0125 g Answer: 1.008 mg CaCO3/ mL EDTA
- One method for quantitative determination of the concentration of constituents in a sample analyzed by gas chromatography is the area normalization method. In this method, complete elution of all of the sample constituents is necessary. The area of each peak is then measured and corrected for differences in detector response to the different eluates. This correction is accomplished by dividing the area by an empirically determined correction factor. The concentration of the analyte is found from the ratio of its corrected area to the total corrected area of all peaks. For a chromatogram containing three peaks, the relative areas were found to be 16.4, 45.2, and 30.2 in the order of increasing retention time. Calculate the percentage of each compound if the relative detector responses were 0.60, 0.78, and 0.88, respectivelyA compound X is to be determined by UV/visible spectrophotometry. A calibration curve is constructed from standard solutions of X with the following results: 0.50 ppm, A = 0.24; 1.5 ppm, A = 0.36; 2.5 ppm, A = 0.44; 3.5 ppm, A = 0.59; and 4.5 ppm, A = 0.70. Find the following: 1. slope and intercept of the calibration curve 2. the mean concentration of the solution of unknown X concentration if the absorbance of 3 replicates are A = 0.29, A = 0.30 and A = 0.32. 3. the standard deviation in the concentration of X2. A method for analysis of codeine in prescription drugs yielded the following results when applied to a codeine- free blank: 0.01, -0.2, 0.3, 0.2, 0.0, -0.1 mg codeine. Calculate the detection limit (in terms of miligrams in codeine) at 99% confidence level, based upon the mean.