Create a function for the queue headers that removes a consecutive list of items. The function will accept 2 parameters, where the first parameter is a value in the list and the second parameter is a whole number. The function will search for the firs parameter, and if the value is in it will remove the items following the searched value nth times. Use the following example: Example 1: the list has 10 items namely a, s, c, v, m, b, x, p,k, i the function accepts 2 parameters v and 3. The resulting link will be a, s, c, x, p,k, I Example 2: the list has 10 items namely 0, 9, 8, 7, 6, 5, 4, 3, 2, 1 the function accepts 2 parameters 6 and 4.
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C++ Data Structures. Use the array based list headers for queue
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- Write a function that takes two queue structures as _parameters: original queue and modified queue. The function finds the numbers greater than or equal to 5 in the original queue and places 1 to the same position in the modified queue. For the numbers less than 5, modified queue element has 0. Assume that two input queues have the same number of elements at a time. Example Original Queue: 35 16 28 Example Modified Queue: O1101 void modifyqueue (struct queue *org, struct queue *mod){ Note that you need printqueue function to display the queue contents in order to verify your solutions.Modify the given code to make it work using the keywords (undo,redo,display and exit) instead of the case statment. It will insert by default but when it reads one of the keywords it will go the function we call. Example: Enter the element to be inserted in the queue: hello Enter the element to be inserted in the queue: world Enter the element to be inserted in the queue:display hello world Enter the element to be inserted in the queue:undo Enter the element to be inserted in the queue:display hello Enter the element to be inserted in the queue:redo Enter the element to be inserted in the queue:display hello world ***************************** The Code #include <stdio.h>#include <stdlib.h>struct node{char data[100];struct node *link;}*front, *rear; struct node *list=NULL;void insert(){struct node *temp;temp = (struct node*)malloc(sizeof(struct node));printf("Enter the element to be inserted in the queue: ");scanf("%s",temp->data);temp->link = NULL;if (rear ==…write a function that add any item in a linked list after the item X, if the item X is not found in the linked list don't add the item. data structre please solve it fast less than 30 minute
- The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…Suppose a list contains marks earned in the courses CSE110, PHY111, and MAT110 of each student consecutively in a nested list form. Your task is to take a course name as input and sort the list based on the marks obtained in that course to finally print the names of the students in descending order of marks obtained i.e. from the student who earned the highest marks to the student who earned the lowest. For example, the list may look like stu_lst = [ ["Alan", 95, 87, 91], ["Turing", 92, 90, 83], ["Elon", 87, 92, 80], ["Musk", 85, 94, 90] ] where for each nested list, 1st index holds the name of the student, 2nd index is total marks earned in the CSE110 course, 3rd index is PHY111 marks and 4th index is MAT110 marks. [You cannot use python build-in sort() function, you can call your own sort function or copy your code from previous tasks instead] =============================================================== Sample Input 1 MAT110 Sample Output 1 ['Alan', 'Musk', 'Turing', 'Elon']…Suppose a list contains marks earned in the courses CSE110, PHY111, and MAT110 of each student consecutively in a nested list form. Your task is to take a course name as input and sort the list based on the marks obtained in that course to finally print the names of the students in descending order of marks obtained i.e. from the student who earned the highest marks to the student who earned the lowest. For example, the list may look like stu_lst = [ ["Alan", 95, 87, 91], ["Turing", 92, 90, 83], ["Elon", 87, 92, 80], ["Musk", 85, 94, 90] ] where for each nested list, 1st index holds the name of the student, 2nd index is total marks earned in the CSE110 course, 3rd index is PHY111 marks and 4th index is MAT110 marks. [You cannot use python build-in sort() function, you can call your own sort function or copy your code from previous tasks instead] =============================================================== Sample Input 1 MAT110 Sample Output 1 ['Alan', 'Musk', 'Turing', 'Elon']…
- Code in python Given a list, L, the function front_two creates a new list of length 2 out of the first two items in L as follows: In the new list, the second item becomes the first item, and the first item becomes the second. If L contains only one item, the first item in the new list should be the value None. If L is empty, both items in the new list should be value None. The function returns the new list. For example: Test Result L = ['a', 'b', 'c', 'd'] print(front_two(L)) ['b', 'a'] L = [] print(front_two(L)) [None, None] L = [5, 2] print(front_two(L)) [2, 5] L = [7] print(front_two(L)) [None, 7]Instructions Create a program that contains a function append_combine(x, a) where x is a list of integers and a is an integer. Aside from appending a to list x , the function should also check if the number at the end of list before appending a are equal. If they are, then these two values should be combined instead. Combining should be done repeteadly until there are no more consecutive pairs in the list. See example below. Example test cases X = [] append_combine(x, 1) # [1] append_combine(x, 2) # -> [1, 2] append_combine(x, 2) # -> [1, 2, 2] -> [1, 4] append_combine(x, 2) # -> [1, 4, 2] append_combine(x, 2) # -> [1, 4, 2, 2] -> [1, 4, 4] -> [1, 8] append_combine (x, 3) # -> [1, 8, 3] append_combine(x, 2) # -> [1, 8, 3, 2] append_combine(x, 4) # -> [1, 8, 3, 2, 4] append_combine(x, 4) # -> [1, 8, 3, 2, 4, 4] -> [1, 8, 3, 2, 8] # Final value of x is [1, 8, 3, 2, 8]You are given the pointer to the head node of a linked list and an integer to add to the list. Create a new node with the given integer. Insert this node at the tail of the linked list and return the head node of the linked list formed after inserting this new node. The given head pointer may be null, meaning that the initial list is empty. Function Description Complete the insertNodeAtTail function in the editor below. insertNodeAtTail has the following parameters: SinglyLinkedListNode pointer head: a reference to the head of a list int data: the data value for the node to insert Returns SinglyLinkedListNode pointer: reference to the head of the modified linked list Input Format The first line contains an integer , the number of elements in the linked list.The next lines contain an integer each, the value that needs to be inserted at tail. Constraints Sample Input STDIN Function ----- -------- 5 size of linked list n = 5 141 linked list data values…
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