Consider the following SQL query on the university schema: SELECT AVG(salary) - (SUM(salary)/COUNT(*)) FROM instructor; We might expect that the result of this query is zero since the average of a set of numbers is defined to be the sum of the numbers divided by the number of numbers. Indeed, this is true for the example instructor relation in Figure 2.1. However, there are other possible instances of that relation for which the result would NOT be zero. Give one such instance, and explain why the results would not be zero
Consider the following SQL query on the university schema: SELECT AVG(salary) - (SUM(salary)/COUNT(*)) FROM instructor; We might expect that the result of this query is zero since the average of a set of numbers is defined to be the sum of the numbers divided by the number of numbers. Indeed, this is true for the example instructor relation in Figure 2.1. However, there are other possible instances of that relation for which the result would NOT be zero. Give one such instance, and explain why the results would not be zero
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Consider the following SQL query on the university schema:
SELECT AVG(salary) - (SUM(salary)/COUNT(*))
FROM instructor;
We might expect that the result of this query is zero since the average of a set of numbers is defined to be the sum of
the numbers divided by the number of numbers. Indeed, this is true for the example instructor relation in Figure 2.1.
However, there are other possible instances of that relation for which the result would NOT be zero. Give one such
instance, and explain why the results would not be zero.
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