Consider the following SQL Query: SELECT FNAME, DNAME FROM EMP AS E, DEPT AS D WHERE E.DNO = D.DNUMBER AND D.DNAME='CCI' AND SALARY > 15000; Draw the initial query tree for the above SQL query, and then show how the query tree is optimized by applying the Heuristic Rules. (You need to show the tree after applying a rule).
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- 2. Get the Groups As new students begin to arrive at college, each receives a unique ID number, 1 to n. Initially, the students do not know one another, and each has a different circle of friends. As the semester progresses, other groups of friends begin to form randomly. There will be three arrays, each aligned by an index. The first array will contain a queryType which will be either Friend or Total. The next two arrays, students1 and students2, will each contain a student ID. If the query type is Friend, the two students become friends. If the query type is Total, report the sum of the sizes of each group of friends for the two students.There's a "friend_requests" table that has a column "action_taken" that displays if the friend request was rejected, requested, or accepted.Implement a SQL query to return the percentage of "action_taken" that were "accepted".SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression
- There's a "friend_requests" table that has a column "action_taken" that displays if the friend request was rejected, requested, or accepted.Implement a SQL query to return the number of "action_taken" that were "accepted".What does an EXCEPT (MINUS) query care about operand order, while a UNION query doesn't?There's a "users" table that has more than 1M rows of "users" information. The image below are the first 3 rows.Implement a SQL query that retrieves the "email" and "friend_count" of the "user_id" with the most friends.
- Using explicit cursors write an anonymous block that displays the names of the shoppers followed by the names of the products that they have shopped. You will find this information in the bb_shopper(shopper name), bb_product (product name), bb_basket and bb_basketitem tables. It is fine if some of the product names are repeated in the output, this is because the shopper has brought an item more than once..Translate the following pandas statement in Python to a SQL query so that it can be executed on the SQL database. dfdata[(10*dfdata['cases']>dfdata['cases'])&(dfdata['date']=='2020-10-10')]['county']Define the difference between hashset and treeseet in table format.
- Write a PL/SQL Function that accepts 4 integers, 2 representing the homeTeamID and visitorTeamID, and the other 2 representing the score for each team during a game : htscore and vtscore The function will determine which team won the match and return the teamID of the winning team. You can achive this by comparing htscore > or < then vtscore.. if htscore is bigger then return hteamID or else return vteamID. If the game was a tie (the 2 scores are the same value) return a 0.Develop a PL/SQL block that would go through all the employees from EMPLOYEES table who work in department id= 90 (there is suppose to be 3 employee who work in Department 90)- IN BEGIN END END SECTION; Execute 3 separate of SELECT statement one after the other. Each SELECT will pull first name. salary of each employee and store them in local variables.+ SELECT LOAD INTO v_firstname1, v_salarxlWHERE emrlexee.id=100 Then second WHERE emploxee.id3101+ SELECT first_name, salary INTO v_firstname2, v_salary2 Then third + SELECTSELECTI tirst.name, salary INTO v_firstname3, v_salary3 iin WHERE emploxee id=102 ..... You must now have 6 local variables. DECLARE all of them accordingly in DECLARE section and use them in BEGIN and END.+ Then add another SELECT statement in BEGIN-END to find company average salary SELECT xa(salary) INTO aKasal FROM EMPLOYEES; !!! Do not forget to create y avgsal local variable in DECLARE section.2. Write a method named query2 that uses JDBC to execute a SELECT query to List, for a provided Language, the movies for that language (ID, Title, Release Date) together with the Number of actors that act on each of them. Note if a movie has 0 actors, it should appear with a 0 (For example, film with id 5, in Spanish, has not actors) Example of output for the parameter Spanish': film_id title 2 release_year Number of actors ACE GOLDFINGER AFRICAN EGG 2006 5 2006 10 ALADDIN CALENDAR 2006 3 Use a PreparedStatement with a parameter for the LanguageName and filter the query results to only return rows tied to that Language. b. Pretty-print the results to the console (One line per row in readable aligned columns) This would be invoked on the command line as a. с. java ser322.JdbcLab query2