An ant crawls on the floor along the curved path shown in the figure below. The ant's positions and velocities are indicated for times t; = 0 and t = 5.20 s. (Notethe ant's initial velocity at t, in the +y-direction and its final velocity at t is in the +x-direction.)y (m)Vav, y= 0.110 m/sKV₁ = 0.110 m/s0.150ti0.100iFind the x- and y-components of the ant's displacement, average velocity, and average acceleration between the two times. (Indicate the direction with the signsof your answers.)(a) displacement (in m)Ax =Δy =av, x(b) average velocity (in m/s)Vav, xav, y0.380=m=m(c) average acceleration (in m/s²)m/s²m/s²m/sm/s0.420x (m)

Given: ti = 0 tf = 5.20 s xi = 0.100 m xf = 0.420 m yi = 0.150 m yf = 0.380 m To find: a)…

An ant crawls on the floor along the curved path shown in the figure below. The ant's positions and velocities are indicated for times t; = 0and tp = 5.20s. (Note the ant's initial velocity at t; in the +y-direction and its final velocity at t, is in the +x-direction.) y (m) 0.380 0.150 of 0.100 = 0.110m/s स 0.420 v; = 0.110m/s • x (m) Find the x- and y-components of the ant's displacement, average velocity, and average acceleration between the two times. (Indicate the direction with the sign

An ant crawls on the floor along the curved path shown in the figure below. The ant's positions and velocities are indicated for times t; = 0and tp = 5.20s. (Note the ant's initial velocity at t; in the +y-direction and its final velocity at t, is in the +x-direction.) y (m) 0.380 0.150 of 0.100 = 0.110m/s स 0.420 v; = 0.110m/s • x (m) Find the x- and y-components of the ant's displacement, average velocity, and average acceleration between the two times. (Indicate the direction with the sign

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

(d) The velocity versus position graph of a motorcycle is given in Figure 1.3 below. Determine its acceleration at s=150 ft (4 Marks) v (ft/s) 50 10 200 400 2 -s (ft)
v (m/s) 4. From experimental data, the motion of the jet plane while travelling along a runway is defined by v-t graph as shown in Figure 4.3. Calculate the velocity V1 if the total distance travelled is 2800 m. 10 s 40 s Figure 4.3
The diagram below represents a swimmer. The swimmer is capable to swim in a still water with a velocity Vị = 1 m's. He aims his body directly across a 100 m wide river whose current has a velocity V;=2 m/s. Use this diagram to answer questions 1 through 3. 1. The time it will take for the swimmer to cross the river is .. (A) 10 sec (B) 20 sec (C) 50 sec (D) 100 sec 2. How far downstream will he land? The correct answer is (A) 100 m (B) 200 m (C) 150 m (D) 180 m
4. A girl tosses a ball at an initial velocity of VA = 8 ft/s at an angle of 0 = 25°. A boy catches the ball at Point B, which is at the same height as Point A. Answer the following questions. a. What is the initial velocity of the ball in A = (VA) x² + (VA) format? Show your work. Velocity in A = (VA) x + (VA)yj format C. b. Where is the ball when it reaches its maximum height? Justify your response by describing where the ball is relative to the position of Points A & B. No math is required. Units What is known about the x- and y-components of velocity and acceleration of the ball at the maximum height? No math is required. d. If we assume that Points A & B are both 3 ft above the ground, what is the maximum total height of the ball? Show your work. Magnitude rounded to 3 sig. fig. Units
v (m/s) 4. From experimental data, the motion of the jet plane while travelling along a runway is defined by v-t graph as shown in Figure 4.3. Calculate the velocity Vị if the total (s) distance travelled is 2800 m. 10s 40 s Figure 4.3
The equations describing the position of a water stream (with respect to time) coming out of the hose, shown in the following figure, are given by the following. y X (Vy)o = 1.5 m/s Hose -Xo = 2m x = x₁ + (Vx) ot y = Y₁ + (V₂) ot — — — gt² 2 V (V₂) = 2.6 m/s Yo = 1.5 m In these relationships, x and y are position coordinates, x and y are initial coordinates of the tip of the hose, (Vx) and (V₂) are the initial velocities of water coming out of the hose in the x- and y-directions, g = 9.81 m/s², and t is time. Plot the x- and y-positions of the water stream as a function of time. Also, plot the path the water stream will follow as a function of time. Compute and plot the components of velocity of the water stream as a function of time. (Submit a file with a maximum size of 1 MB.)
1- The "divergence grad 6" can be written as: a: V(V.) b: Vx(V) e: V.(V.) d: V.(V) 2-The acceleration vector in plane polar coordinates is a = (-ro?)e, +(rö + 2ró)eo If a particle moves on a circle path with constant radius b then the radial and transverse components respectively are: a: be and bö b: b and 2bė e: B - bộ and zero d: zero and b- bo? 3- The concept of impulse can be obtained if the force is: a: F(x) b: F(t) e: F(v) d: constant 4- The position vector of a particle can be written in cylindrical coordinates (R, . z) as: a: r=ReR b: r-R eg +o e, + Ze, e: r=R eg +Ze, d: r=ReR + e,
The figure below (not to scale) shows an acceleration-time graph of a body. a (m/s^2) 0 7 t(s) B 27 If the initial velocity was zero, a(0) = a0 = 10.7 m/s^2, a(7) = a7 = -2.2 m/s^2 and the particle's acceleration returns to zero at t = 10s, what will the body's velocity be at t = 10 s? Express your answer to three significant figures in units of m/s (but do not write the units with your answer).
As shown in the figure. A plot of potential energy U versus position x of a 2 kg particle that can move along x-axis. The graph has these values U_A=9 J, U_C=20J and U_D=24 J. The particle is released at position x=5 m with kinetic energy 4 J where the potential energy is U_B=12J. What is the maximum speed of the particle, and in which interval does it occur. Upf- Uch UA 4 6 7 8. 9 x (m) A v max= 4 m/s interval (6, 7) B v max=2 m/s interval (0,1) (c) none of them D V max=2.45 m/s interval (3,4)
EX- function of time t (in second ) is : The position s ( in meters ) of a moving body as s - 2t + 5t – 3 ; find : a a) The interval from t= 0 to t= 2 seconds . b) The body’s velocity at t=2 seconds . displacement and average velocity for the time
1. The position of a particle moving along the x-axis is described by x = t – 108t in where t is the time in sec. For the time interval t= 0 to t = 10 s, (a) plot the position, velocity, and acceleration as a function of time (b) find the displacement of the particle and (c) determine the distance traveled by the particle.
1. A box slides down a ramp with position vector given by r= 0.5t i + 3f² j + 8t k (m), where t is in s. At t = 3 s, what is the box's velocity and acceleration? What is the box's speed?