A unique aquatic plant was discovered from a lagoon in El Nido, Palawan. To determine the protein content of the plant, an adequate amount of the plant extract was acquired, and Bradford assay was performed. Determine the total protein concentration, in µg/mL, of the acquired plant extract. A bovine serum albumin (BSA) stock solution with a concentration of 250 µg/mL was used and mixtures with the following compositions and absorbance readings were prepared:

Curren'S Math For Meds: Dosages & Sol
11th Edition
ISBN:9781305143531
Author:CURREN
Publisher:CURREN
Chapter10: Reconstitution Of Powdered Drugs
Section: Chapter Questions
Problem 7.2P
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A unique aquatic plant was discovered from a lagoon in El Nido,
Palawan. To determine the protein content of the plant, an
adequate amount of the plant extract was acquired, and Bradford
assay was performed. Determine the total protein concentration,
in µg/mL, of the acquired plant extract. A bovine serum albumin
(BSA) stock solution with a concentration of 250 µg/mL was used
and mixtures with the following compositions and absorbance
readings were prepared:
Volume of BSA
(mL)
Volume of water
(mL)
Absorbance
Tube #
at 595 nm
1
0.00
2.00
0.000
2
0.20
1.80
0.112
3
0.40
1.60
0.225
4
0.60
1.40
0.318
5
0.80
1.20
0.432
6
1.00
1.00
0.551
The absorbance reading of the plant extract is 0.275.
Transcribed Image Text:A unique aquatic plant was discovered from a lagoon in El Nido, Palawan. To determine the protein content of the plant, an adequate amount of the plant extract was acquired, and Bradford assay was performed. Determine the total protein concentration, in µg/mL, of the acquired plant extract. A bovine serum albumin (BSA) stock solution with a concentration of 250 µg/mL was used and mixtures with the following compositions and absorbance readings were prepared: Volume of BSA (mL) Volume of water (mL) Absorbance Tube # at 595 nm 1 0.00 2.00 0.000 2 0.20 1.80 0.112 3 0.40 1.60 0.225 4 0.60 1.40 0.318 5 0.80 1.20 0.432 6 1.00 1.00 0.551 The absorbance reading of the plant extract is 0.275.
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