(a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar width b.
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- At an axial load of 22 kN, a 15-mm-thick x 45-mm-wide polyimide polymer bar elongates 4.0 mm while the bar width contracts 0.15 mm. The bar is 260-mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson's ratio. O 0.175 O 0.217 O 0.297 0.235 O 0.280At an axial load of 22 kN, a 15-mm-thick x 35-mm-wide polyimide polymer bar elongates 4.2 mm while the bar width contracts 0.25 mm. The bar is 215-mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine Poisson's ratio. O 0.366 O 0.336 EBA O 0.473 O 0.229 O 0.427The polymer bar shown in the figure below has a width of b=40 mm, a depth of d=104 mm, and a height of h=255 mm. At a compressive load of P=125 kN, the bar height contracts by Δh=-2.40 mm, and the bar depth elongates by Δd=0.36 mm. At this load, the stress in the polymer bar is less than its proportional limit. Determine: (a) the modulus of elasticity. (b) Poisson’s ratio. (c) the change in the bar width b.
- Strain, Deformation and Thermal Stress Steel Rod A = 600 mm? L= 4.0 m E= 200 GPa Aluminum Rod A = 900 mm? a = 11.70 um/(m°C) L= 3.0 m E = 70 GPa %3D 2. Determine the stress in a = 23 um/(m°C) the aluminum rod if the 3 m 3 m 3 m temperature of steel is increased by 40 degrees A D Celsius at the same time the 50 KN load is applied to the beam. F = 50 KN Strain, Deformation and Thermal Stress · 600 KN The 600 KN load is horizontal when it is first 1.00 m applied to the columns. After some time, the 600 KN load is still horizontal after deformation took place for all the columns. If the diameter of all the columns is 50 mm. Modulus of elasticity of steel is 200 GPa and modulus of elasticity of bronze is 100 GPa. Compute the strain of the steel. 0.25 m Bronze Steel BronzeCalculate the normal stress in the brass rod in MPa. Calculate the normal stress in the bronze rod in MPa. Brass L = 5m A = 400 mm² Bronze L = 6m E = 120 GPa A = 500 mm² E = 100 GPa 3m M 5m NAxial loads are applied to the compound rod that is composed of an aluminum segment rigidly connected between steel and bronze segments. P = 10 kN a. What is the stress (MPa) in the Bronze material? b. What is the stress in Aluminum in MPa? c. What is the stress in Steel in MPa?
- A state of stress is specified in the figure shown. Determine the principal stress oy (mPa) if P =-20 mPa and y = 15 mPa P VM A cylinder of outer radius R2=100 mm is fitted on another cylinder of outside radius R₁=85 mm with thickness t=30 mm, as depicted below. If the (tensile) maximum hoop stress at the interface between the two cylinder is 90 MPa, solve the following questions (E=105 MPa and v=0.15). === R₁ What is the radial stress between the cylinders? What is the shrinkage allowance at the interface? ( M R₂ )At an axial load of 22 kN, a 40-mm-wide by 20-mm-thick polyimide polymer bar elongates 3.2 mm while the bar width contracts 0.18 mm. The bar is 240 mm long. At the 22-kN load, the stress in the polymer bar is less than its proportional limit. Determine (a) the modulus of elasticity. (b) Poisson's ratio. (c) the change in the bar thickness. Answers: (a) E= (b) v = (c) Athickness i i i GPa mm
- Determine Value of x if the Normal stress at rod is equal to the stress at rectangular pipe A =400 mm2 F = 8kN Rod A =650 mm² rectangular PipeA state of stress is specified in the figure shown. Determine the principal stress oy (mPa) if P =-27 mPa and v = 20 mPa P6 - A circular shaft is composed of a steel core and a brass covering, as shown in the figure. Under the applied torque, what is the maximum shear stress in each material? The composite shaft is attached to a wall at A. Im B OPT. →→→→T= 5 KN•m Steel core r=15mm G=78 GPa bross cylinder ro=20mm (outer diameter) G=39 GPa