A-Given that the volumetric flow rate for a fluid within a circular cross-section tube can be represented by AP Q- where r is the tube radius, u is the fluid viscosity, P is the pressure drop across the tube, and L is the tube length, calculate the pressure drop across a tube of length 1 m and diameter of 23 mm. The fluid is blood (μ = 0.0035 N.s/m²) and has a volumetric flow rate of 4.5 L/min. Assuming the same conditions, what would the required pressure drop be for water (μ = 0.001 N.s/m²) and chocolate syrup (μ = 150 N.s/m²). 8pL

Elements Of Electromagnetics
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A-Given that the volumetric flow rate for a fluid within a circular cross-section tube can be
represented by
#HAP
8pL
Q
where r is the tube radius, u is the fluid viscosity, P is the pressure drop across the tube, and L is
the tube length, calculate the pressure drop across a tube of length 1 m and diameter of 23 mm.
The fluid is blood (μ = 0.0035 N.s/m²) and has a volumetric flow rate of 4.5 L/min. Assuming
the same conditions, what would the required pressure drop be for water (u= 0.001 N.s/m²) and
chocolate syrup (u = 150 N.s/m²).
Transcribed Image Text:A-Given that the volumetric flow rate for a fluid within a circular cross-section tube can be represented by #HAP 8pL Q where r is the tube radius, u is the fluid viscosity, P is the pressure drop across the tube, and L is the tube length, calculate the pressure drop across a tube of length 1 m and diameter of 23 mm. The fluid is blood (μ = 0.0035 N.s/m²) and has a volumetric flow rate of 4.5 L/min. Assuming the same conditions, what would the required pressure drop be for water (u= 0.001 N.s/m²) and chocolate syrup (u = 150 N.s/m²).
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