A force that sets up or tends to set up magnetic flux in a magnetic By an electric current through a number of turns of a wire produc Magnetic circuit Electromotive force Magnetomotive force Force on two parallel conductors t is the voltage generated by a conductor or coil moving in a mag ield. D Voltage Drop Low Voltage Induced EMF O Voltage Regulation
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- A magnetic circuit with a cross-sectional area of 20 cm? is to be operated at 50 Hz from a 120 V rms supply. The number of turns required to achieve a peak magnetic flux density of 1.8 T in the core isAn iron circuit with a small0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (u, = 800 for iron). Figure 1The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft iron core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20mm. Take the relative permeability of soft iron as 1100. Determine the total flux
- An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm?, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron). Figure 1An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm², and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (ur = 800 for iron).An iron circuit with a small 0.75 mm air gap is shown in Figure 1. A 6000 turn coil carries a current I = 18 mA which sets up a flux within the iron and across the air gap. The cross section of the iron is a consistent 0.8 cm2, and the mean length of the flux path is 0.15 m. a) Redraw the magnetic circuit using schematic symbols of an electric circuit with reluctance in each part of the circuit. b) State's Ohm's Law for magnetic circuit. c) By neglecting the effect of fringing, calculate the reluctance of the circuit. d) Find the flux within the core. N = 6000 Iron circuit (4, = 800 for iron).
- show thatvthis is a magnetic flux density: then prove and interpret it with reasons on each stepThe length of a magnetic circuit in a moving iron instrument is 300mm.The coil around the soft iron core has 360 turns and takes a current of 1.75A.The core is square in section with sides of 20mm.Take the relative permeability of soft iron as 1100. Determine the magnetomotive force in the core. Determine the field strength. Determine the flux density. Determine the total flux.A magnetic ring has reluctance of 1.675 × 10⁰ AT weber. The flux to be produced by the coil is 800 x 10 webers, then the AT required for the m.m.f. will be
- A rectangular coil of wire has a length of 3 cm and a width of 4 cm. It is in a 0.004 T magnetic field. What is the magnetic flux through the coil if the face of the coil is parallel to the B-field lines? What is the flux if the angle between the face of the coil and the magnetic field is 75°?(3.4)The length of a magnetic circuit in a moving iron instrument is 300mm. The coil around the soft-iron core has 360 turns and takes a current of 1.75 A. The core is square in section with sides of 20 mm. Take the relative permeability of soft iron as 1100. 3.4.1) Determine the magnetomotive force in the core 3.4.2)Determine the field strength 3.4.3) Determine the total flux1. What is the relationship between voltage and current when there is saturation in the magnetic circuit? 2. When there is no saturation in the magnetic circuit, what is the relationship between voltage and current? 3. Briefly explain what caused the saturation in the magnetic circuit. 4. What happens to alternating current, alternating current, and alternating magnetic flux in a magnetic circuit when frequency increases? 5. When a magnetic circuit is saturated, explain two solutions that can be used so that the magnetic circuit is no longer saturated.