Values for the figure are given in the following table. Note thefigure may not be to scale.VariableabFACS =сa.Determine the magnitude of the force in the cord AB,FABb. Determine the magnitude of the force in the spring AC,FACc. Determine the stretch of the spring, sd. Determine the original length (unstretched length) ofthe spring, LoRound your final answers to 3 significant digits/figures.FAB =Lo =Value2 m2 m2 m=3N3N A force of F = 50 N is applied to the rope that causes theangle 0₁ = 60 degrees to keep the system at equilibrium. TheNspring constant is k = 100mBa0₁сabсVariable Value2 m2 m2 mFbValues for the figure are given in the following table. Note thefigure may not be to scale.cc i❀OBY NC SA2013 Michael Swanbom

Answered: Image /qna-images/answer/bafa5a09-6f1f-48da-974c-6a9ebafa6d4a.jpg

A force of F = 50 N is applied to the rope that causes the angle 0₁ = 60 degrees to keep the system at equilibrium. The N spring constant is k = 100 m B 0₁ a с a b с A Variable Value 2 m 2 m 2 m F Values for the figure are given in the following table. Note the figure may not be to scale. b cc 130 BY NC SA 2013 Michael Swanbom

A force of F = 50 N is applied to the rope that causes the angle 0₁ = 60 degrees to keep the system at equilibrium. The N spring constant is k = 100 m B 0₁ a с a b с A Variable Value 2 m 2 m 2 m F Values for the figure are given in the following table. Note the figure may not be to scale. b cc 130 BY NC SA 2013 Michael Swanbom

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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PHYS X PHYS X 印 PHYS X PHYS X POTPHYS X PHYS X E PHYS X E PHYS top/semester2/physics%20for%20engineers/PHYS220_CH15_Lecture%20Notes_Problems%2015 19,15.29 S (D Page view A Read aloud V Draw Problem-15-19: page-475 A 0.500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm. Calculate the maximum value of its (a) speed, and acceleration. (b) the speed and the acceleration when the object is 6.00 em from the equilibrium position, and (c) the time interval required for the object to move from.r50 to r5 8.O0 cm. Solution:
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Consider the following system mä(t) + cx(t) + kx(t) = F,8(t) + F28(t – t1) Assume zero initial conditions. The units are in Newtons. If m = 42.7334 kg, c = 44.7394 Ns/m, k = 6776.8559 N/m, F1 = 47.5525 N.s, F2 = -5.3708 N.s and t = 3.9737 s, the velocity of the system at t2 = 2.3387 s is
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