8. The value V (in thousands of dollars) of an industrial machine is modeled by V(N) = (3N + 430) 2/3 (N + 1)2/3 where N is the number of hours the machine is used each day. Suppose further that usage varies with time in such a way that N(t) = √²-10t + 61 where t is the number of months the machine has been in operation. Over what time interval is the value of the machine increasing? When it is decreasing? At what time t is the value of the machine the largest? What is the maximum value?

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 15T
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8. The value V (in thousands of dollars) of an industrial machine is modeled by
V(N) =
(3N + 430) 2/3
(N + 1)2/3
where N is the number of hours the machine is used each day. Suppose further that
usage varies with time in such a way that
N(t) = √² - 10t +61
where t is the number of months the machine has been in operation. Over what time
interval is the value of the machine increasing? When it is decreasing? At what time t
is the value of the machine the largest? What is the maximum value?
Transcribed Image Text:8. The value V (in thousands of dollars) of an industrial machine is modeled by V(N) = (3N + 430) 2/3 (N + 1)2/3 where N is the number of hours the machine is used each day. Suppose further that usage varies with time in such a way that N(t) = √² - 10t +61 where t is the number of months the machine has been in operation. Over what time interval is the value of the machine increasing? When it is decreasing? At what time t is the value of the machine the largest? What is the maximum value?
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