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c) sulue: Q (y) = f(t) > y (0) = 22,4 (0) = 1, 9" (0) = 4 and fet) = { 10 000 S 10 wst+laet +2 if ost "1/₂ + 12 e ² ta

c) sulue: Q (y) = f(t) > y (0) = 22,4 (0) = 1, 9" (0) = 4 and fet) = { 10 000 S 10 wst+laet +2 if ost "1/₂ + 12 e ² ta

Calculus For The Life Sciences
Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter11: Differential Equations
Section11.CR: Chapter 11 Review
Problem 15CR
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het Q be the differential operator defined by 1 where = Q(y) = y(3) +44 (2) + 54² +24 a) solve: Q (y) = 10 cost +126² +2 b) solve! Q(4) = 10 sint + laet +2 4(0) = 2, 4² (0) = 1, 4" (0) = 4. Y(1/₂) = y(1/₂) = 0 c) solue: Qiy) = f(t) > y (0) = 1, y'(0) = 1, y" (0) = 4 and fet) = { 1000s +120=²+2 it **/2 wst+laet +2 if ost</₂2 if 11/2
Transcribed Image Text:het Q be the differential operator defined by 1 where = Q(y) = y(3) +44 (2) + 54² +24 a) solve: Q (y) = 10 cost +126² +2 b) solve! Q(4) = 10 sint + laet +2 4(0) = 2, 4² (0) = 1, 4" (0) = 4. Y(1/₂) = y(1/₂) = 0 c) solue: Qiy) = f(t) > y (0) = 1, y'(0) = 1, y" (0) = 4 and fet) = { 1000s +120=²+2 it **/2 wst+laet +2 if ost</₂2 if 11/2
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