34. A geosynchronous satellite appears to “hover” stationary directly above a particular point on the Earth’s equator. In order to achieve this the period of the orbit must match the sidereal period of Earth’s rotation, which is 23 hours 56 minutes. Solve for the altitude and speed of such a satellite. (Can only use Newton's 3 laws of motion and the law of gravity where Fg=G(M1M2)/r^2 and g=GM/r^2. You can also use the uniform circular motion formulas for speed and acceleration.)
34. A geosynchronous satellite appears to “hover” stationary directly above a particular point on the Earth’s equator. In order to achieve this the period of the orbit must match the sidereal period of Earth’s rotation, which is 23 hours 56 minutes. Solve for the altitude and speed of such a satellite. (Can only use Newton's 3 laws of motion and the law of gravity where Fg=G(M1M2)/r^2 and g=GM/r^2. You can also use the uniform circular motion formulas for speed and acceleration.)
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter6: Uniform Circular Motion And Gravitation
Section: Chapter Questions
Problem 43PE: A geosynchronous Earth satellite is one that has an orbital period of precisely 1 day. Such orbits...
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34. A geosynchronous satellite appears to “hover” stationary directly above a particular point on the Earth’s equator. In order to achieve this the period of the orbit must match the sidereal period of Earth’s rotation, which is 23 hours 56 minutes. Solve for the altitude and speed of such a satellite.
(Can only use Newton's 3 laws of motion and the law of gravity where Fg=G(M1M2)/r^2 and g=GM/r^2. You can also use the uniform circular motion formulas for speed and acceleration.)
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