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3. XYZ, a non-electrolyte, is miscible (highly soluble) with water and its molar mass is 132 g/mol. Now, consider 0.15 m XYZ aqueous solution. Which of the following equations will give us the correct result to convert 0.15 m XYZ into the mole fraction of XYZ? Note that the molar mass of water is 18.0 g/mol. 0.15 (a) 0.15+18.0 0.15 (b) 0.1541000 18.0 0.15 (c) 0.15+1000 x18.0 0.15 x132 (d) 0.15 x132 +1000 (e) None of the above

3. XYZ, a non-electrolyte, is miscible (highly soluble) with water and its molar mass is 132 g/mol. Now, consider 0.15 m XYZ aqueous solution. Which of the following equations will give us the correct result to convert 0.15 m XYZ into the mole fraction of XYZ? Note that the molar mass of water is 18.0 g/mol. 0.15 (a) 0.15+18.0 0.15 (b) 0.1541000 18.0 0.15 (c) 0.15+1000 x18.0 0.15 x132 (d) 0.15 x132 +1000 (e) None of the above

Introductory Chemistry For Today
Introductory Chemistry For Today
8th Edition
ISBN:9781285644561
Author:Seager
Publisher:Seager
Chapter7: Solutions And Colloids
Section: Chapter Questions
Problem 7.47E
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3. XYZ, a non-electrolyte, is miscible (highly soluble) with water and its molar mass is 132 g/mol. Now, consider 0.15 m XYZ aqueous solution. Which of the following equations will give us the correct result to convert 0.15 m XYZ into the mole fraction of XYZ? Note that the molar mass of water is 18.0 g/mol. 0.15 (a) 0.15+18.0 0.15 (b) 1000 0.15+ 18.0 0.15 (c) 0.15+1000 x18.0 0.15 x132 (d) 0.15 x132 +1000 (e) None of the above
Transcribed Image Text:3. XYZ, a non-electrolyte, is miscible (highly soluble) with water and its molar mass is 132 g/mol. Now, consider 0.15 m XYZ aqueous solution. Which of the following equations will give us the correct result to convert 0.15 m XYZ into the mole fraction of XYZ? Note that the molar mass of water is 18.0 g/mol. 0.15 (a) 0.15+18.0 0.15 (b) 1000 0.15+ 18.0 0.15 (c) 0.15+1000 x18.0 0.15 x132 (d) 0.15 x132 +1000 (e) None of the above
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