2. The following maintenance alteratives are considered for a new assembly line that has an acquisition cost of $250,000. Each has distinct service life expectancies and corresponding probabilities. Determine the maintenance regime most likely to yield an annualized overall cost less than $32k, given an annual rate of 7%. Maintenance regime Service life years (probability) $0 throughout life 7(0.2) 8(0.6) 9(0.2) $25000 (in year 4) 8 (0.15) 10 (0.5) 12 (0.35) $35,000 (years 3 and 6) 10 (0.25) 12 (0.5) 14 (0.25) $75,000 (year 6) 12 (0.3) 13 (0.33) 15 (0.37)

2. The following maintenance alteratives are considered for a new assembly line that has an acquisition cost of $250,000. Each has distinct service life expectancies and corresponding probabilities. Determine the maintenance regime most likely to yield an annualized overall cost less than $32k, given an annual rate of 7%. Maintenance regime Service life years (probability) $0 throughout life 7(0.2) 8(0.6) 9(0.2) $25000 (in year 4) 8 (0.15) 10 (0.5) 12 (0.35) $35,000 (years 3 and 6) 10 (0.25) 12 (0.5) 14 (0.25) $75,000 (year 6) 12 (0.3) 13 (0.33) 15 (0.37)

Essentials Of Investments

11th Edition

ISBN:9781260013924

Author:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Publisher:Bodie, Zvi, Kane, Alex, MARCUS, Alan J.

Chapter1: Investments: Background And Issues

Section: Chapter Questions

Problem 1PS

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The table given below lists the relevant cost items for a specific system purchase. The operating expenses for the new system are $10,000 per year, and the useful life of the system is expected to be five years. The salvage value for depreciation purposes is equal to 25% of the hardware cost. Cost Item Cost Hardware $160,000 Training $15,000 Installation $15,000 a) What is the Book Value (BV) of the device at the end of year three if the Straight Line (SL) depreciation method is used? b) Suppose that after depreciating the device for two years with the SL method, the firm decides to switch to the double declining balance depreciation method for the remainder of the device's life (the remaining three years). What is the device's BV at the end of four years?
Required information A project has a first cost of $670,000, a salvage value of 27% of the first cost after 3 years, and annual (GI-OE) of $275,000. Assume the company has a Te of 37%. Determine the approximate after-tax rate of return (ROR). The after-tax rate of return (ROR) is determined to be
1. Two alternatives are being considered for installation. Which should be selected based on a present worth comparison at an interest rate of 6% per year. Alternative A Alternative B First Cost, $ 17,650 22,900 Maintenance Cost, $/year 1700 1400 Salvage value, $ 10,500 17,000 Life, years 4 3
A company is considering two alternatives with regards to equipment which it needs. The alternatives are as follows: Alternative A: Purchase Cost of Equipment 703,668700,000 Salvage Value 100,454100,000 Daily operating cost 501500 Economic life, years 10 Alternative B: Rental at 1,5751,500 per day. At 18% interest, how many days per year must the equipment be in use if Alternative A is to be chosen.
A new robot has a first cost of $380,000, and an annual operating cost of $88,000 in years 1 and 2, increasing by $10000 per year thereafter. The salvage value of the system is $25,000 regardless of when the system is retired within its maximum useful life of 5 years. Using a MARR of 14% per year, determine the ESL and the respective AW value of the system ESL: a) 1 year b) 4 years c) 5 years d) 3 years AW value of system: a) $204,860 b) $336,284 c) $97,953 d) $496,200
Reference: Case Study S Dunn Manufacturing is considering the following two alternatives. The cost information for the two proposals for replacing an equipment are provided are in table below. Initial cost Benefits/year Machine X $120,000 $20,000 for the first 10 years and $9,000 for the next 10 years Life Salvage value $40,000 MARR 5.2. The NPW of machine X is A) $35,158 B) $48,192 C) $50,752 Machine Y $96,000 $12,000 per year for 20 years. 20 years 8% $20,000
Its required to select one of the two machines, if you know that the firms MARR-12% and if the costs are shown below: Project A Project B Initial cost, $ 7650 12900 Maintenance cost, S/year 1200 900 Salvage value, $ 2000 Economic life, year 4 Compare the two-alternative using: 1-Equavlent Annual worth comparison. 2- Present worth comparison
An engineer must choose between two technically equivalent alternatives, A and B. Based upon the data in the table below over the 12year analysis period and an interest rate of 9%, the PW of machine A is: A B First Cost $3,000 $6,000 Annual Maintenance $500 $300 End of Useful Life Salvage Value $700 $1,000 Useful Life 5 years |15 уears O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,10)-500(P/A,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/F,9%,15)+700(P/F,9%,5)+700(P/F,9%,10)+ 700(P/F,9%,15) O PWA=-3000-3000(P/F,9%,5)-3000(P/F,9%,10)-500(P/A,9%,10)+700(P/F,9%,5)+700(P/F,9%,10)+ 700(P/F,9%,15)
You are given opportunity to purchase product for $42, 000. The product will have annual operating expenses of $4,000, and a salvage value of $20,000 at the end of its useful life of 6 years. Assuming a discount rate of 9.0%, what is the minimum acceptable revenue to justify taking this project? A 1.01% B $333 C $2704 D $767 E $10704
Two types of power converters are under consideration for a specific application. An economic comparison is to be made using a MARR of 10% and the following cost estimates: Alternative Model A Model B Service Life (Years) 5 10 First Cost $10,000 $20,000 Salvage Value 0 5,000 Annual Operating Cost 2,500 1,200 Draw the Cash Fiow Diagram for each alfernative covering the entire analysis period. Compute the Net Present Worth for Model A? Compute the Net Equivalent Uniform Annual Worth for Model A? Which of these alternatives should be selected?
An injection molding system has a first cost of $175,000 and an annual operating cost of $95,000 inyears 1 and 2, increasing by $6,000 per year thereafter.The salvage value of the system is 25% ofthe first cost regardless of when the system is retired within its maximum useful life of 5 years.Using a MARR of11% per year, determine the ESL and the respective AW value of the system.
In an energy systems installation, following financial requirement was identified. Capital cost of equipment and installation - $ 150,000 Recurrent cost of maintenance Replacement of parts Life time of the system Income through energy generation i. iii. -$5,000 per year -$4,000 per year - 12 years - $ 22,000 per year Calculate the payback period of the system. If the scarp value of the equipment is $ 5,000, determine is the net profit expected to be collected for the investment? Explain how this profit is affected by "cost of money" or "interest". No calculations needed.

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