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To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?

To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different. Location 1 standard deviation: 0.050 Location 2 standard deviation: 0.34 What is the calculated ? value for comparing the standard deviations?

Chemistry: Matter and Change
Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter14: Mixtures And Solutions
Section: Chapter Questions
Problem 59A
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To determine the organic material in a dried lake bed, the percent carbon by mass is measured at two different locations. To compare the means of the two different locations, it must first be determined whether the standard deviations of the two locations are different.

Location 1 standard deviation: 0.050

Location 2 standard deviation: 0.34

What is the calculated ? value for comparing the standard deviations?

 

Sample 1 2 3 نیا 4 5 Location 1 (% Location 2 (% C) C) 60.40 60.10 60.30 60.90 60.30 60.30 60.40 60.80 60.30 60.40
Transcribed Image Text:Sample 1 2 3 نیا 4 5 Location 1 (% Location 2 (% C) C) 60.40 60.10 60.30 60.90 60.30 60.30 60.40 60.80 60.30 60.40
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